|
51 | 51 | <!-- 这里可写当前语言的特殊实现逻辑 -->
|
52 | 52 |
|
53 | 53 | ```python
|
54 |
| - |
| 54 | +# Definition for a binary tree node. |
| 55 | +# class TreeNode: |
| 56 | +# def __init__(self, val=0, left=None, right=None): |
| 57 | +# self.val = val |
| 58 | +# self.left = left |
| 59 | +# self.right = right |
| 60 | +class Solution: |
| 61 | + def sortedArrayToBST(self, nums: List[int]) -> TreeNode: |
| 62 | + def buildBST(nums, start, end): |
| 63 | + if start > end: |
| 64 | + return None |
| 65 | + mid = (start + end) >> 1 |
| 66 | + return TreeNode(nums[mid], buildBST(nums, start, mid - 1), buildBST(nums, mid + 1, end)) |
| 67 | + |
| 68 | + return buildBST(nums, 0, len(nums) - 1) |
55 | 69 | ```
|
56 | 70 |
|
57 | 71 | ### **Java**
|
58 | 72 |
|
59 | 73 | <!-- 这里可写当前语言的特殊实现逻辑 -->
|
60 | 74 |
|
61 | 75 | ```java
|
| 76 | +/** |
| 77 | + * Definition for a binary tree node. |
| 78 | + * public class TreeNode { |
| 79 | + * int val; |
| 80 | + * TreeNode left; |
| 81 | + * TreeNode right; |
| 82 | + * TreeNode() {} |
| 83 | + * TreeNode(int val) { this.val = val; } |
| 84 | + * TreeNode(int val, TreeNode left, TreeNode right) { |
| 85 | + * this.val = val; |
| 86 | + * this.left = left; |
| 87 | + * this.right = right; |
| 88 | + * } |
| 89 | + * } |
| 90 | + */ |
| 91 | +class Solution { |
| 92 | + public TreeNode sortedArrayToBST(int[] nums) { |
| 93 | + return buildBST(nums, 0, nums.length - 1); |
| 94 | + } |
| 95 | + |
| 96 | + private TreeNode buildBST(int[] nums, int start, int end) { |
| 97 | + if (start > end) { |
| 98 | + return null; |
| 99 | + } |
| 100 | + int mid = (start + end) >> 1; |
| 101 | + TreeNode root = new TreeNode(nums[mid]); |
| 102 | + root.left = buildBST(nums, start, mid - 1); |
| 103 | + root.right = buildBST(nums, mid + 1, end); |
| 104 | + return root; |
| 105 | + } |
| 106 | +} |
| 107 | +``` |
| 108 | + |
| 109 | +### **C++** |
| 110 | + |
| 111 | +```cpp |
| 112 | +/** |
| 113 | + * Definition for a binary tree node. |
| 114 | + * struct TreeNode { |
| 115 | + * int val; |
| 116 | + * TreeNode *left; |
| 117 | + * TreeNode *right; |
| 118 | + * TreeNode() : val(0), left(nullptr), right(nullptr) {} |
| 119 | + * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} |
| 120 | + * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} |
| 121 | + * }; |
| 122 | + */ |
| 123 | +class Solution { |
| 124 | +public: |
| 125 | + TreeNode* sortedArrayToBST(vector<int>& nums) { |
| 126 | + return buildBST(nums, 0, nums.size() - 1); |
| 127 | + } |
| 128 | + |
| 129 | +private: |
| 130 | + TreeNode* buildBST(vector<int>& nums, int start, int end) { |
| 131 | + if (start > end) { |
| 132 | + return nullptr; |
| 133 | + } |
| 134 | + int mid = (start + end) / 2; |
| 135 | + TreeNode *root = new TreeNode(nums[mid]); |
| 136 | + root->left = buildBST(nums, start, mid - 1); |
| 137 | + root->right = buildBST(nums, mid + 1, end); |
| 138 | + return root; |
| 139 | + } |
| 140 | +}; |
| 141 | +``` |
62 | 142 |
|
| 143 | +### **JavaScript** |
| 144 | +
|
| 145 | +```js |
| 146 | +/** |
| 147 | + * Definition for a binary tree node. |
| 148 | + * function TreeNode(val, left, right) { |
| 149 | + * this.val = (val===undefined ? 0 : val) |
| 150 | + * this.left = (left===undefined ? null : left) |
| 151 | + * this.right = (right===undefined ? null : right) |
| 152 | + * } |
| 153 | + */ |
| 154 | +/** |
| 155 | + * @param {number[]} nums |
| 156 | + * @return {TreeNode} |
| 157 | + */ |
| 158 | +var sortedArrayToBST = function(nums) { |
| 159 | + const buildBST = (nums, start, end) => { |
| 160 | + if (start > end) { |
| 161 | + return null; |
| 162 | + } |
| 163 | + const mid = (start + end) >> 1; |
| 164 | + const root = new TreeNode(nums[mid]); |
| 165 | + root.left = buildBST(nums, start, mid - 1); |
| 166 | + root.right = buildBST(nums, mid + 1, end); |
| 167 | + return root; |
| 168 | + } |
| 169 | +
|
| 170 | + return buildBST(nums, 0, nums.length - 1); |
| 171 | +}; |
63 | 172 | ```
|
64 | 173 |
|
65 | 174 | ### **...**
|
|
0 commit comments