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‎solution/1600-1699/1645.Hopper Company Queries II/README.md

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# [1645. ](https://leetcode-cn.com/problems/hopper-company-queries-ii)
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# [1645. Hopper Company Queries II](https://leetcode-cn.com/problems/hopper-company-queries-ii)
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[English Version](/solution/1600-1699/1645.Hopper%20Company%20Queries%20II/README_EN.md)
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## 题目描述
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<!-- 这里写题目描述 -->
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None
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<p>Table: <code>Drivers</code></p>
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<pre>
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+-------------+---------+
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| Column Name | Type |
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+-------------+---------+
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| driver_id | int |
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| join_date | date |
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+-------------+---------+
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driver_id is the primary key for this table.
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Each row of this table contains the driver&#39;s ID and the date they joined the Hopper company.
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</pre>
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<p>&nbsp;</p>
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<p>Table: <code>Rides</code></p>
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<pre>
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+--------------+---------+
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| Column Name | Type |
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+--------------+---------+
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| ride_id | int |
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| user_id | int |
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| requested_at | date |
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+--------------+---------+
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ride_id is the primary key for this table.
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Each row of this table contains the ID of a ride, the user&#39;s ID that requested it, and the day they requested it.
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There may be some ride requests in this table that were not accepted.
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</pre>
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<p>&nbsp;</p>
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<p>Table: <code>AcceptedRides</code></p>
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<pre>
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+---------------+---------+
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| Column Name | Type |
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+---------------+---------+
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| ride_id | int |
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| driver_id | int |
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| ride_distance | int |
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| ride_duration | int |
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+---------------+---------+
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ride_id is the primary key for this table.
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Each row of this table contains some information about an accepted ride.
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It is guaranteed that each accepted ride exists in the Rides table.
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</pre>
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<p>&nbsp;</p>
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<p>Write an SQL query to report the <strong>percentage</strong> of working drivers (<code>working_percentage</code>) for each month of <strong>2020</strong> where:</p>
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<img alt="" src="https://cdn.jsdelivr.net/gh/doocs/leetcode@main/solution/1600-1699/1645.Hopper%20Company%20Queries%20II/images/codecogseqn.png" style="width: 970px; height: 44px;" />
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<p><strong>Note</strong> that if the number of available drivers during a month is zero, we consider the <code>working_percentage</code> to be <code>0</code>.</p>
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<p>Return the result table ordered by <code>month</code> in <strong>ascending</strong> order, where <code>month</code> is the month&#39;s number (January is <code>1</code>, February is <code>2</code>, etc.). Round <code>working_percentage</code> to the nearest <strong>2 decimal places</strong>.</p>
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<p>The query result format is in the following example.</p>
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<p>&nbsp;</p>
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<pre>
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Drivers table:
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+-----------+------------+
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| driver_id | join_date |
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+-----------+------------+
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| 10 | 2019-12-10 |
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| 8 | 2020-1-13 |
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| 5 | 2020-2-16 |
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| 7 | 2020-3-8 |
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| 4 | 2020-5-17 |
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| 1 | 2020-10-24 |
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| 6 | 2021-1-5 |
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+-----------+------------+
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Rides table:
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+---------+---------+--------------+
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| ride_id | user_id | requested_at |
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+---------+---------+--------------+
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| 6 | 75 | 2019-12-9 |
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| 1 | 54 | 2020-2-9 |
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| 10 | 63 | 2020-3-4 |
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| 19 | 39 | 2020-4-6 |
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| 3 | 41 | 2020-6-3 |
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| 13 | 52 | 2020-6-22 |
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| 7 | 69 | 2020-7-16 |
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| 17 | 70 | 2020-8-25 |
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| 20 | 81 | 2020-11-2 |
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| 5 | 57 | 2020-11-9 |
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| 2 | 42 | 2020-12-9 |
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| 11 | 68 | 2021-1-11 |
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| 15 | 32 | 2021-1-17 |
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| 12 | 11 | 2021-1-19 |
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| 14 | 18 | 2021-1-27 |
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+---------+---------+--------------+
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AcceptedRides table:
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+---------+-----------+---------------+---------------+
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| ride_id | driver_id | ride_distance | ride_duration |
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+---------+-----------+---------------+---------------+
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| 10 | 10 | 63 | 38 |
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| 13 | 10 | 73 | 96 |
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| 7 | 8 | 100 | 28 |
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| 17 | 7 | 119 | 68 |
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| 20 | 1 | 121 | 92 |
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| 5 | 7 | 42 | 101 |
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| 2 | 4 | 6 | 38 |
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| 11 | 8 | 37 | 43 |
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| 15 | 8 | 108 | 82 |
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| 12 | 8 | 38 | 34 |
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| 14 | 1 | 90 | 74 |
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+---------+-----------+---------------+---------------+
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Result table:
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+-------+--------------------+
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| month | working_percentage |
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+-------+--------------------+
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| 1 | 0.00 |
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| 2 | 0.00 |
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| 3 | 25.00 |
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| 4 | 0.00 |
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| 5 | 0.00 |
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| 6 | 20.00 |
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| 7 | 20.00 |
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| 8 | 20.00 |
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| 9 | 0.00 |
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| 10 | 0.00 |
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| 11 | 33.33 |
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| 12 | 16.67 |
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+-------+--------------------+
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By the end of January --&gt; two active drivers (10, 8) and no accepted rides. The percentage is 0%.
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By the end of February --&gt; three active drivers (10, 8, 5) and no accepted rides. The percentage is 0%.
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By the end of March --&gt; four active drivers (10, 8, 5, 7) and one accepted ride by driver (10). The percentage is (1 / 4) * 100 = 25%.
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By the end of April --&gt; four active drivers (10, 8, 5, 7) and no accepted rides. The percentage is 0%.
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By the end of May --&gt; five active drivers (10, 8, 5, 7, 4) and no accepted rides. The percentage is 0%.
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By the end of June --&gt; five active drivers (10, 8, 5, 7, 4) and one accepted ride by driver (10). The percentage is (1 / 5) * 100 = 20%.
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By the end of July --&gt; five active drivers (10, 8, 5, 7, 4) and one accepted ride by driver (8). The percentage is (1 / 5) * 100 = 20%.
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By the end of August --&gt; five active drivers (10, 8, 5, 7, 4) and one accepted ride by driver (7). The percentage is (1 / 5) * 100 = 20%.
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By the end of Septemeber --&gt; five active drivers (10, 8, 5, 7, 4) and no accepted rides. The percentage is 0%.
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By the end of October --&gt; six active drivers (10, 8, 5, 7, 4, 1) and no accepted rides. The percentage is 0%.
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By the end of November --&gt; six active drivers (10, 8, 5, 7, 4, 1) and two accepted rides by <strong>two different</strong> drivers (1, 7). The percentage is (2 / 6) * 100 = 33.33%.
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By the end of December --&gt; six active drivers (10, 8, 5, 7, 4, 1) and one accepted ride by driver (4). The percentage is (1 / 6) * 100 = 16.67%.
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</pre>
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## 解法
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### **SQL**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```sql
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```

‎solution/1600-1699/1651.Hopper Company Queries III/README.md

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# [1651. ](https://leetcode-cn.com/problems/hopper-company-queries-iii)
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# [1651. Hopper Company Queries III](https://leetcode-cn.com/problems/hopper-company-queries-iii)
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[English Version](/solution/1600-1699/1651.Hopper%20Company%20Queries%20III/README_EN.md)
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## 题目描述
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<!-- 这里写题目描述 -->
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None
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<p>Table: <code>Drivers</code></p>
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## 解法
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<pre>
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+-------------+---------+
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| Column Name | Type |
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+-------------+---------+
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| driver_id | int |
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| join_date | date |
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+-------------+---------+
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driver_id is the primary key for this table.
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Each row of this table contains the driver&#39;s ID and the date they joined the Hopper company.
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</pre>
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<!-- 这里可写通用的实现逻辑 -->
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<p>&nbsp;</p>
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<!-- tabs:start -->
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<p>Table: <code>Rides</code></p>
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### **Python3**
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<pre>
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+--------------+---------+
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| Column Name | Type |
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+--------------+---------+
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| ride_id | int |
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| user_id | int |
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| requested_at | date |
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+--------------+---------+
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ride_id is the primary key for this table.
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Each row of this table contains the ID of a ride, the user&#39;s ID that requested it, and the day they requested it.
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There may be some ride requests in this table that were not accepted.
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</pre>
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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<p>&nbsp;</p>
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<p>Table: <code>AcceptedRides</code></p>
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<pre>
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+---------------+---------+
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| Column Name | Type |
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+---------------+---------+
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| ride_id | int |
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| driver_id | int |
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| ride_distance | int |
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| ride_duration | int |
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+---------------+---------+
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ride_id is the primary key for this table.
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Each row of this table contains some information about an accepted ride.
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It is guaranteed that each accepted ride exists in the Rides table.
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</pre>
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<p>&nbsp;</p>
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<p>Write an SQL query to compute the <code>average_ride_distance</code> and <code>average_ride_duration</code> of every 3-month window starting from <strong>January - March 2020</strong> to <strong>October - December 2020</strong>. Round <code>average_ride_distance</code> and <code>average_ride_duration</code> to the nearest <strong>two decimal places</strong>.</p>
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<p>The <code>average_ride_distance</code> is calculated by summing up the total <code>ride_distance</code> values from the three months and dividing it by <code>3</code>. The <code>average_ride_duration</code> is calculated in a similar way.</p>
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<p>Return the result table ordered by <code>month</code> in ascending order, where <code>month</code> is the starting month&#39;s number (January is <code>1</code>, February is <code>2</code>, etc.).</p>
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<p>The query result format is in the following example.</p>
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<p>&nbsp;</p>
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<pre>
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Drivers table:
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+-----------+------------+
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| driver_id | join_date |
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+-----------+------------+
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| 10 | 2019-12-10 |
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| 8 | 2020-1-13 |
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| 5 | 2020-2-16 |
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| 7 | 2020-3-8 |
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| 4 | 2020-5-17 |
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| 1 | 2020-10-24 |
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| 6 | 2021-1-5 |
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+-----------+------------+
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Rides table:
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+---------+---------+--------------+
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| ride_id | user_id | requested_at |
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+---------+---------+--------------+
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| 6 | 75 | 2019-12-9 |
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| 1 | 54 | 2020-2-9 |
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| 10 | 63 | 2020-3-4 |
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| 19 | 39 | 2020-4-6 |
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| 3 | 41 | 2020-6-3 |
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| 13 | 52 | 2020-6-22 |
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| 7 | 69 | 2020-7-16 |
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| 17 | 70 | 2020-8-25 |
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| 20 | 81 | 2020-11-2 |
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| 5 | 57 | 2020-11-9 |
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| 2 | 42 | 2020-12-9 |
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| 11 | 68 | 2021-1-11 |
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| 15 | 32 | 2021-1-17 |
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| 12 | 11 | 2021-1-19 |
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| 14 | 18 | 2021-1-27 |
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+---------+---------+--------------+
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AcceptedRides table:
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+---------+-----------+---------------+---------------+
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| ride_id | driver_id | ride_distance | ride_duration |
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+---------+-----------+---------------+---------------+
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| 10 | 10 | 63 | 38 |
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| 13 | 10 | 73 | 96 |
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| 7 | 8 | 100 | 28 |
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| 17 | 7 | 119 | 68 |
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| 20 | 1 | 121 | 92 |
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| 5 | 7 | 42 | 101 |
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| 2 | 4 | 6 | 38 |
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| 11 | 8 | 37 | 43 |
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| 15 | 8 | 108 | 82 |
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| 12 | 8 | 38 | 34 |
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| 14 | 1 | 90 | 74 |
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+---------+-----------+---------------+---------------+
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Result table:
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+-------+-----------------------+-----------------------+
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| month | average_ride_distance | average_ride_duration |
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+-------+-----------------------+-----------------------+
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| 1 | 21.00 | 12.67 |
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| 2 | 21.00 | 12.67 |
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| 3 | 21.00 | 12.67 |
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| 4 | 24.33 | 32.00 |
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| 5 | 57.67 | 41.33 |
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| 6 | 97.33 | 64.00 |
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| 7 | 73.00 | 32.00 |
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| 8 | 39.67 | 22.67 |
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| 9 | 54.33 | 64.33 |
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| 10 | 56.33 | 77.00 |
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+-------+-----------------------+-----------------------+
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By the end of January --&gt; average_ride_distance = (0+0+63)/3=21, average_ride_duration = (0+0+38)/3=12.67
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By the end of February --&gt; average_ride_distance = (0+63+0)/3=21, average_ride_duration = (0+38+0)/3=12.67
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By the end of March --&gt; average_ride_distance = (63+0+0)/3=21, average_ride_duration = (38+0+0)/3=12.67
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By the end of April --&gt; average_ride_distance = (0+0+73)/3=24.33, average_ride_duration = (0+0+96)/3=32.00
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By the end of May --&gt; average_ride_distance = (0+73+100)/3=57.67, average_ride_duration = (0+96+28)/3=41.33
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By the end of June --&gt; average_ride_distance = (73+100+119)/3=97.33, average_ride_duration = (96+28+68)/3=64.00
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By the end of July --&gt; average_ride_distance = (100+119+0)/3=73.00, average_ride_duration = (28+68+0)/3=32.00
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By the end of August --&gt; average_ride_distance = (119+0+0)/3=39.67, average_ride_duration = (68+0+0)/3=22.67
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By the end of Septemeber --&gt; average_ride_distance = (0+0+163)/3=54.33, average_ride_duration = (0+0+193)/3=64.33
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By the end of October --&gt; average_ride_distance = (0+163+6)/3=56.33, average_ride_duration = (0+193+38)/3=77.00
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</pre>
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## 解法
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<!-- 这里可写通用的实现逻辑 -->
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<!-- tabs:start -->
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### **SQL**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```sql
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```
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<!-- tabs:end -->
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<!-- tabs:end -->

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