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32 changes: 32 additions & 0 deletions 14. Questions/leetcode 530 - minimum absolute difference in BST.py
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# minimum absolute difference in BST | leetcode 530 | https://leetcode.com/problems/minimum-absolute-difference-in-bst/
# method: dfs, inorder traversal

# Definition for a binary tree node.
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right

class Solution:
def getMinimumDifference(self, root: TreeNode):
minDiff = float('inf')
prevNod = None

def dfs(node):
nonlocal minDiff, prevNod
if node is None:
return

dfs(node.left)

if prevNod != None:
minDiff = min(minDiff, abs(node.val - prevNod))
prevNod = node.val

dfs(node.right)

dfs(root)
return minDiff


16 changes: 16 additions & 0 deletions 14. Questions/leetcode 797 - all paths from source to target.py
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# all paths from source to target | leetcode 797 | https://leetcode.com/problems/all-paths-from-source-to-target/
# method: dfs

class Solution:
def allPathsSourceTarget(self, graph: list[list[int]]) -> list[list[int]]:
possiblePaths = []

def dfs(node, visited):
if node == len(graph) - 1:
possiblePaths.append(visited)

for neighbour in graph[node]:
dfs(neighbour, [*visited, node])

dfs(0, [0])
return possiblePaths
21 changes: 21 additions & 0 deletions 14. Questions/leetcode 96 - unique binary search trees.py
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# unique binary search trees | leetcode 96 | https://leetcode.com/problems/unique-binary-search-trees/
# method: dp, use cached results for subtrees of all possible roots

class Solution:
def numTrees(self, n: int) -> int:
# cache of possible trees
possibleTrees = [1] * (n + 1)

# for each number of nodes
for numNodes in range(2, n + 1):

# for each possible root
possibleSubTrees = 0
for possibleRoot in range(1, numNodes + 1):
Left = possibleRoot - 1
Right = numNodes - possibleRoot
possibleSubTrees += possibleTrees[Left] * possibleTrees[Right]
possibleTrees[numNodes] = possibleSubTrees

return possibleTrees[n]

21 changes: 21 additions & 0 deletions 14. Questions/leetcode 997 - find the town judge.py
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# find the town judge | leetcode 997 | https://leetcode.com/problems/find-the-town-judge/submissions/
# method: decrement trust value if you trust someone, increment if someone trusts you

class Solution:
def findJudge(self, n: int, trust: list[list[int]]) -> int:

# for each person
# trust += 1 if someone trusts you
# trust -= 1 if you trust someone
trustValue = [0] * (n + 1)

for edge in trust:
trustValue[edge[0]] -= 1
trustValue[edge[1]] += 1

for i in range(1, n + 1):
if trustValue[i] == (n - 1):
return i

return -1