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docs: add a description of the solution to lc problem: No.0183 #751

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Mar 15, 2022
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docs: add a description of the solution to lc problem: No.0183 #751

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8 changes: 8 additions & 0 deletions solution/0100-0199/0183.Customers Who Never Order/README.md
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<!-- 这里可写通用的实现逻辑 -->

**方法一：**

列举所有已存在订单的客户 ID，使用 `NOT IN` 找到不存在其中的客户。

**方法二：**

使用 `LEFT JOIN` 连接表格，返回 `CustomerId` 为 `NULL` 的数据。

<!-- tabs:start -->

### **SQL**
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