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feat: add solutions to lc/lcof2 problems: No.9 #632

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25 changes: 25 additions & 0 deletions lcof2/剑指 Offer II 009. 乘积小于 K 的子数组/README.md
Original file line number Diff line number Diff line change
@@ -111,6 +111,31 @@ func numSubarrayProductLessThanK(nums []int, k int) int {
}
```

### **C++**

```cpp
class Solution {
public:
int numSubarrayProductLessThanK(vector<int>& nums, int k) {
int left = 0, right;
long mul = 1;
int count = 0;

for (right = 0; right < nums.size(); right++) {
mul *= nums[right];

while(left <= right && mul >= k) {
mul /= nums[left++];
}

count += right >= left? right - left + 1: 0;
}

return count;
}
};
```

### **...**

```
Original file line number Diff line number Diff line change
@@ -0,0 +1,20 @@
class Solution {
public:
int numSubarrayProductLessThanK(vector<int>& nums, int k) {
int left = 0, right;
long mul = 1;
int count = 0;

for (right = 0; right < nums.size(); right++) {
mul *= nums[right];

while(left <= right && mul >= k) {
mul /= nums[left++];
}

count += right >= left? right - left + 1: 0;
}

return count;
}
};
26 changes: 26 additions & 0 deletions solution/0700-0799/0713.Subarray Product Less Than K/README.md
Original file line number Diff line number Diff line change
@@ -34,6 +34,32 @@

<!-- tabs:start -->

### **C++**

```cpp
class Solution {
public:
int numSubarrayProductLessThanK(vector<int>& nums, int k) {
int left = 0, right;
long mul = 1;
int count = 0;

for (right = 0; right < nums.size(); right++) {
mul *= nums[right];

while(left <= right && mul >= k) {
mul /= nums[left++];
}

count += right >= left? right - left + 1: 0;
}

return count;
}
};
```


### **Python3**

<!-- 这里可写当前语言的特殊实现逻辑 -->
26 changes: 26 additions & 0 deletions solution/0700-0799/0713.Subarray Product Less Than K/README_EN.md
Original file line number Diff line number Diff line change
@@ -42,6 +42,32 @@ Note that [10, 5, 2] is not included as the product of 100 is not strictly less

<!-- tabs:start -->

### **C++**

```cpp
class Solution {
public:
int numSubarrayProductLessThanK(vector<int>& nums, int k) {
int left = 0, right;
long mul = 1;
int count = 0;

for (right = 0; right < nums.size(); right++) {
mul *= nums[right];

while(left <= right && mul >= k) {
mul /= nums[left++];
}

count += right >= left? right - left + 1: 0;
}

return count;
}
};
```


### **Python3**

```python
20 changes: 20 additions & 0 deletions solution/0700-0799/0713.Subarray Product Less Than K/Solution.cpp
Original file line number Diff line number Diff line change
@@ -0,0 +1,20 @@
class Solution {
public:
int numSubarrayProductLessThanK(vector<int>& nums, int k) {
int left = 0, right;
long mul = 1;
int count = 0;

for (right = 0; right < nums.size(); right++) {
mul *= nums[right];

while(left <= right && mul >= k) {
mul /= nums[left++];
}

count += right >= left? right - left + 1: 0;
}

return count;
}
};