feat: add swift implementation to lcp problem: No.51

lcp/LCP 51. 烹饪料理/README.md

@@ -235,6 +235,46 @@ function perfectMenu(
 }
 ```
 
+#### Swift
+
+```swift
+class Solution {
+    func perfectMenu(_ materials: [Int], _ cookbooks: [[Int]], _ attribute: [[Int]], _ limit: Int) -> Int {
+        let n = cookbooks.count
+        var ans = -1
+
+        for mask in 0..<(1 << n) {
+            var a = 0, b = 0
+            var cnt = [Int](repeating: 0, count: 5)
+
+            for i in 0..<n {
+                if (mask >> i & 1) == 1 {
+                    a += attribute[i][0]
+                    b += attribute[i][1]
+                    for j in 0..<cookbooks[i].count {
+                        cnt[j] += cookbooks[i][j]
+                    }
+                }
+            }
+
+            var ok = true
+            for i in 0..<5 {
+                if cnt[i] > materials[i] {
+                    ok = false
+                    break
+                }
+            }
+
+            if b >= limit && a > ans && ok {
+                ans = a
+            }
+        }
+
+        return ans
+    }
+}
+```
+
 <!-- tabs:end -->
 
 <!-- solution:end -->

lcp/LCP 51. 烹饪料理/Solution.swift

@@ -0,0 +1,35 @@
+class Solution {
+    func perfectMenu(_ materials: [Int], _ cookbooks: [[Int]], _ attribute: [[Int]], _ limit: Int) -> Int {
+        let n = cookbooks.count
+        var ans = -1
+
+        for mask in 0..<(1 << n) {
+            var a = 0, b = 0
+            var cnt = [Int](repeating: 0, count: 5)
+
+            for i in 0..<n {
+                if (mask >> i & 1) == 1 {
+                    a += attribute[i][0]
+                    b += attribute[i][1]
+                    for j in 0..<cookbooks[i].count {
+                        cnt[j] += cookbooks[i][j]
+                    }
+                }
+            }
+
+            var ok = true
+            for i in 0..<5 {
+                if cnt[i] > materials[i] {
+                    ok = false
+                    break
+                }
+            }
+
+            if b >= limit && a > ans && ok {
+                ans = a
+            }
+        }
+
+        return ans
+    }
+}