Skip to content

feat: update solutions to lc problems: No.1146,2639 #2649

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
merged 1 commit into from
Apr 24, 2024
Merged
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
125 changes: 77 additions & 48 deletions solution/1100-1199/1146.Snapshot Array/README.md
Original file line number Diff line number Diff line change
Expand Up @@ -47,33 +47,35 @@ snapshotArr.get(0,0); // 获取 snap_id = 0 的快照中 array[0] 的值,返

### 方法一:数组 + 二分查找

维护一个数组,数组中的每个元素是一个列表,列表中存储的是每次设置的值以及对应的快照编号
我们维护一个长度为 $\text{length}$ 的数组,数组中的每个元素是一个列表,用来存储每次设置的值以及对应的快照 ID

每次设置值时,将值和快照编号添加到对应索引的列表中
调用 `set` 方法时,将值和快照 ID 添加到对应索引的列表中。时间复杂度 $O(1)$

每次获取值时,使用二分查找,找到对应位置第一个大于快照编号 `snap_id` 的值,然后返回前一个值即可
调用 `snap` 方法时,我们先将快照 ID 加一,然后返回快照 ID 减一。时间复杂度 $O(1)$

时间复杂度上,设置值的时间复杂度为 $O(1)$,快照的时间复杂度为 $O(1)$,获取值的时间复杂度为 $O(\log n)$。
调用 `get` 方法时,我们使用二分查找找到对应位置的第一个快照 ID 大于 `snap_id` 的值,然后返回前一个的值。如果找不到,则返回 0。时间复杂度 $O(\log n)$。

空间复杂度 $O(n)$。

<!-- tabs:start -->

```python
class SnapshotArray:

def __init__(self, length: int):
self.idx = 0
self.arr = defaultdict(list)
self.arr = [[] for _ in range(length)]
self.i = 0

def set(self, index: int, val: int) -> None:
self.arr[index].append((self.idx, val))
self.arr[index].append((self.i, val))

def snap(self) -> int:
self.idx += 1
return self.idx - 1
self.i += 1
return self.i - 1

def get(self, index: int, snap_id: int) -> int:
vals = self.arr[index]
i = bisect_right(vals, (snap_id, inf)) - 1
return 0 if i < 0 else vals[i][1]
i = bisect_left(self.arr[index], (snap_id, inf)) - 1
return 0 if i < 0 else self.arr[index][i][1]


# Your SnapshotArray object will be instantiated and called as such:
Expand Down Expand Up @@ -102,17 +104,17 @@ class SnapshotArray {
}

public int get(int index, int snap_id) {
var vals = arr[index];
int left = 0, right = vals.size();
while (left < right) {
int mid = (left + right) >> 1;
if (vals.get(mid)[0] > snap_id) {
right = mid;
int l = 0, r = arr[index].size();
while (l < r) {
int mid = (l + r) >> 1;
if (arr[index].get(mid)[0] > snap_id) {
r = mid;
} else {
left = mid + 1;
l = mid + 1;
}
}
return left == 0 ? 0 : vals.get(left - 1)[1];
--l;
return l < 0 ? 0 : arr[index].get(l)[1];
}
}

Expand All @@ -129,35 +131,25 @@ class SnapshotArray {
class SnapshotArray {
public:
SnapshotArray(int length) {
idx = 0;
arr = vector<vector<pair<int, int>>>(length);
arr.resize(length);
}

void set(int index, int val) {
arr[index].push_back({idx, val});
arr[index].emplace_back(i, val);
}

int snap() {
return idx++;
return i++;
}

int get(int index, int snap_id) {
auto& vals = arr[index];
int left = 0, right = vals.size();
while (left < right) {
int mid = (left + right) >> 1;
if (vals[mid].first > snap_id) {
right = mid;
} else {
left = mid + 1;
}
}
return left == 0 ? 0 : vals[left - 1].second;
auto it = upper_bound(arr[index].begin(), arr[index].end(), make_pair(snap_id, INT_MAX));
return it == arr[index].begin() ? 0 : prev(it)->second;
}

private:
vector<vector<pair<int, int>>> arr;
int idx;
int i = 0;
};

/**
Expand All @@ -171,34 +163,31 @@ private:

```go
type SnapshotArray struct {
idx int
arr [][]pair
arr [][][2]int
i int
}

func Constructor(length int) SnapshotArray {
return SnapshotArray{0, make([][]pair, length)}
return SnapshotArray{make([][][2]int, length), 0}
}

func (this *SnapshotArray) Set(index int, val int) {
this.arr[index] = append(this.arr[index], pair{this.idx, val})
this.arr[index] = append(this.arr[index], [2]int{this.i, val})
}

func (this *SnapshotArray) Snap() int {
this.idx++
return this.idx - 1
this.i++
return this.i - 1
}

func (this *SnapshotArray) Get(index int, snap_id int) int {
vals := this.arr[index]
i := sort.Search(len(vals), func(i int) bool { return vals[i].i > snap_id })
if i == 0 {
i := sort.Search(len(this.arr[index]), func(i int) bool { return this.arr[index][i][0] > snap_id }) - 1
if i < 0 {
return 0
}
return vals[i-1].v
return this.arr[index][i][1]
}

type pair struct{ i, v int }

/**
* Your SnapshotArray object will be instantiated and called as such:
* obj := Constructor(length);
Expand All @@ -208,6 +197,46 @@ type pair struct{ i, v int }
*/
```

```ts
class SnapshotArray {
private arr: [number, number][][];
private i: number = 0;
constructor(length: number) {
this.arr = Array.from({ length }, () => []);
}

set(index: number, val: number): void {
this.arr[index].push([this.i, val]);
}

snap(): number {
return this.i++;
}

get(index: number, snap_id: number): number {
let [l, r] = [0, this.arr[index].length];
while (l < r) {
const mid = (l + r) >> 1;
if (this.arr[index][mid][0] > snap_id) {
r = mid;
} else {
l = mid + 1;
}
}
--l;
return l < 0 ? 0 : this.arr[index][l][1];
}
}

/**
* Your SnapshotArray object will be instantiated and called as such:
* var obj = new SnapshotArray(length)
* obj.set(index,val)
* var param_2 = obj.snap()
* var param_3 = obj.get(index,snap_id)
*/
```

<!-- tabs:end -->

<!-- end -->
Loading