feat: update solutions to lc problems: No.0001,0035

solution/0000-0099/0001.Two Sum/README.md

@@ -145,14 +145,13 @@ use std::collections::HashMap;
 
 impl Solution {
     pub fn two_sum(nums: Vec<i32>, target: i32) -> Vec<i32> {
-        let mut map = HashMap::new();
-        for (i, item) in nums.iter().enumerate() {
-            if map.contains_key(item) {
-                return vec![i as i32, map[item]];
-            } else {
-                let x = target - nums[i];
-                map.insert(x, i as i32);
+        let mut m = HashMap::new();
+        for (i, &x) in nums.iter().enumerate() {
+            let y = target - x;
+            if let Some(&j) = m.get(&y) {
+                return vec![j as i32, i as i32];
             }
+            m.insert(x, i as i32);
         }
         unreachable!()
     }
@@ -204,12 +203,13 @@ class Solution {
      * @return Integer[]
      */
     function twoSum($nums, $target) {
-        foreach ($nums as $key => $x) {
+        $m = [];
+        foreach ($nums as $i => $x) {
             $y = $target - $x;
-            if (isset($hashtable[$y])) {
-                return [$hashtable[$y], $key];
+            if (isset($m[$y])) {
+                return [$m[$y], $i];
             }
-            $hashtable[$x] = $key;
+            $m[$x] = $i;
         }
     }
 }

solution/0000-0099/0001.Two Sum/README_EN.md

@@ -140,14 +140,13 @@ use std::collections::HashMap;
 
 impl Solution {
     pub fn two_sum(nums: Vec<i32>, target: i32) -> Vec<i32> {
-        let mut map = HashMap::new();
-        for (i, item) in nums.iter().enumerate() {
-            if map.contains_key(item) {
-                return vec![i as i32, map[item]];
-            } else {
-                let x = target - nums[i];
-                map.insert(x, i as i32);
+        let mut m = HashMap::new();
+        for (i, &x) in nums.iter().enumerate() {
+            let y = target - x;
+            if let Some(&j) = m.get(&y) {
+                return vec![j as i32, i as i32];
             }
+            m.insert(x, i as i32);
         }
         unreachable!()
     }
@@ -199,12 +198,13 @@ class Solution {
      * @return Integer[]
      */
     function twoSum($nums, $target) {
-        foreach ($nums as $key => $x) {
+        $m = [];
+        foreach ($nums as $i => $x) {
             $y = $target - $x;
-            if (isset($hashtable[$y])) {
-                return [$hashtable[$y], $key];
+            if (isset($m[$y])) {
+                return [$m[$y], $i];
             }
-            $hashtable[$x] = $key;
+            $m[$x] = $i;
         }
     }
 }

solution/0000-0099/0001.Two Sum/Solution.php

@@ -5,12 +5,13 @@ class Solution {
      * @return Integer[]
      */
     function twoSum($nums, $target) {
-        foreach ($nums as $key => $x) {
+        $m = [];
+        foreach ($nums as $i => $x) {
             $y = $target - $x;
-            if (isset($hashtable[$y])) {
-                return [$hashtable[$y], $key];
+            if (isset($m[$y])) {
+                return [$m[$y], $i];
             }
-            $hashtable[$x] = $key;
+            $m[$x] = $i;
         }
     }
-}
+}

solution/0000-0099/0001.Two Sum/Solution.rs

@@ -2,14 +2,13 @@ use std::collections::HashMap;
 
 impl Solution {
     pub fn two_sum(nums: Vec<i32>, target: i32) -> Vec<i32> {
-        let mut map = HashMap::new();
-        for (i, item) in nums.iter().enumerate() {
-            if map.contains_key(item) {
-                return vec![i as i32, map[item]];
-            } else {
-                let x = target - nums[i];
-                map.insert(x, i as i32);
+        let mut m = HashMap::new();
+        for (i, &x) in nums.iter().enumerate() {
+            let y = target - x;
+            if let Some(&j) = m.get(&y) {
+                return vec![j as i32, i as i32];
             }
+            m.insert(x, i as i32);
         }
         unreachable!()
     }

solution/0000-0099/0035.Search Insert Position/README.md

@@ -166,7 +166,11 @@ var searchInsert = function (nums, target) {
 
 <!-- tabs:end -->
 
-### 方法二
+### 方法二：二分查找（内置函数）
+
+我们也可以直接使用内置函数进行二分查找。
+
+时间复杂度 $O(\log n)$，其中 $n$ 为数组 $nums$ 的长度。空间复杂度 $O(1)$。
 
 <!-- tabs:start -->
 
@@ -176,6 +180,15 @@ class Solution:
         return bisect_left(nums, target)
 ```
 
+```java
+class Solution {
+    public int searchInsert(int[] nums, int target) {
+        int i = Arrays.binarySearch(nums, target);
+        return i < 0 ? -i - 1 : i;
+    }
+}
+```
+
 ```cpp
 class Solution {
 public:

solution/0000-0099/0035.Search Insert Position/README_EN.md

@@ -162,7 +162,11 @@ var searchInsert = function (nums, target) {
 
 <!-- tabs:end -->
 
-### Solution 2
+### Solution 2: Binary Search (Built-in Function)
+
+We can also directly use the built-in function for binary search.
+
+The time complexity is $O(\log n)$, where $n$ is the length of the array $nums$. The space complexity is $O(1)$.
 
 <!-- tabs:start -->
 
@@ -172,6 +176,15 @@ class Solution:
         return bisect_left(nums, target)
 ```
 
+```java
+class Solution {
+    public int searchInsert(int[] nums, int target) {
+        int i = Arrays.binarySearch(nums, target);
+        return i < 0 ? -i - 1 : i;
+    }
+}
+```
+
 ```cpp
 class Solution {
 public:

solution/0000-0099/0035.Search Insert Position/Solution2.java

@@ -0,0 +1,6 @@
+class Solution {
+    public int searchInsert(int[] nums, int target) {
+        int i = Arrays.binarySearch(nums, target);
+        return i < 0 ? -i - 1 : i;
+    }
+}