feat: add ts solution to lc problem: No.935

solution/0900-0999/0935.Knight Dialer/README.md

@@ -224,6 +224,45 @@ public class Solution {
 }
 ```
 
+### **TypeScript**
+
+```ts
+function knightDialer(n: number): number {
+    const MOD: number = 1e9 + 7;
+
+    if (n === 1) {
+        return 10;
+    }
+
+    let f: number[] = new Array(10).fill(1);
+
+    while (--n > 0) {
+        let t: number[] = new Array(10).fill(0);
+
+        t[0] = f[4] + f[6];
+        t[1] = f[6] + f[8];
+        t[2] = f[7] + f[9];
+        t[3] = f[4] + f[8];
+        t[4] = f[0] + f[3] + f[9];
+        t[6] = f[0] + f[1] + f[7];
+        t[7] = f[2] + f[6];
+        t[8] = f[1] + f[3];
+        t[9] = f[2] + f[4];
+
+        for (let i = 0; i < 10; ++i) {
+            f[i] = t[i] % MOD;
+        }
+    }
+
+    let ans: number = 0;
+    for (let v of f) {
+        ans = (ans + v) % MOD;
+    }
+
+    return ans;
+}
+```
+
 ### **...**
 
 ```

solution/0900-0999/0935.Knight Dialer/README_EN.md

@@ -205,6 +205,45 @@ public class Solution {
 }
 ```
 
+### **TypeScript**
+
+```ts
+function knightDialer(n: number): number {
+    const MOD: number = 1e9 + 7;
+
+    if (n === 1) {
+        return 10;
+    }
+
+    let f: number[] = new Array(10).fill(1);
+
+    while (--n > 0) {
+        let t: number[] = new Array(10).fill(0);
+
+        t[0] = f[4] + f[6];
+        t[1] = f[6] + f[8];
+        t[2] = f[7] + f[9];
+        t[3] = f[4] + f[8];
+        t[4] = f[0] + f[3] + f[9];
+        t[6] = f[0] + f[1] + f[7];
+        t[7] = f[2] + f[6];
+        t[8] = f[1] + f[3];
+        t[9] = f[2] + f[4];
+
+        for (let i = 0; i < 10; ++i) {
+            f[i] = t[i] % MOD;
+        }
+    }
+
+    let ans: number = 0;
+    for (let v of f) {
+        ans = (ans + v) % MOD;
+    }
+
+    return ans;
+}
+```
+
 ### **...**
 
 ```

solution/0900-0999/0935.Knight Dialer/solution.ts

@@ -0,0 +1,34 @@
+function knightDialer(n: number): number {
+    const MOD: number = 1e9 + 7;
+
+    if (n === 1) {
+        return 10;
+    }
+
+    let f: number[] = new Array(10).fill(1);
+
+    while (--n > 0) {
+        let t: number[] = new Array(10).fill(0);
+
+        t[0] = f[4] + f[6];
+        t[1] = f[6] + f[8];
+        t[2] = f[7] + f[9];
+        t[3] = f[4] + f[8];
+        t[4] = f[0] + f[3] + f[9];
+        t[6] = f[0] + f[1] + f[7];
+        t[7] = f[2] + f[6];
+        t[8] = f[1] + f[3];
+        t[9] = f[2] + f[4];
+
+        for (let i = 0; i < 10; ++i) {
+            f[i] = t[i] % MOD;
+        }
+    }
+
+    let ans: number = 0;
+    for (let v of f) {
+        ans = (ans + v) % MOD;
+    }
+
+    return ans;
+}