feat: update lc problems

doocs · acbin · Oct 1, 2023 · Oct 1, 2023 · Oct 1, 2023 · abc42c532058cc7aa1f9f941efe8c68acd6d3396
commit abc42c532058cc7aa1f9f941efe8c68acd6d3396
diff --git a/solution/2800-2899/2869.Minimum Operations to Collect Elements/README.md b/solution/2800-2899/2869.Minimum Operations to Collect Elements/README.md
@@ -1,11 +1,13 @@
-# [2869. Minimum Operations to Collect Elements](https://leetcode.cn/problems/minimum-operations-to-collect-elements/)
+# [2869. 收集元素的最少操作次数](https://leetcode.cn/problems/minimum-operations-to-collect-elements/)
 
 [English Version](/solution/2800-2899/2869.Minimum%20Operations%20to%20Collect%20Elements/README_EN.md)
 
 ## 题目描述
 
 <!-- 这里写题目描述 -->
 
+<p>给你一个正整数数组&nbsp;<code>nums</code>&nbsp;和一个整数&nbsp;<code>k</code>&nbsp;。</p>
+
 <p>一次操作中，你可以将数组的最后一个元素删除，将该元素添加到一个集合中。</p>
 
 <p>请你返回收集元素&nbsp;<code>1, 2, ..., k</code>&nbsp;需要的&nbsp;<strong>最少操作次数</strong>&nbsp;。</p>
@@ -14,21 +16,24 @@
 
 <p><strong class="example">示例 1：</strong></p>
 
-<pre><b>输入：</b>nums = [3,1,5,4,2], k = 2
+<pre>
+<b>输入：</b>nums = [3,1,5,4,2], k = 2
 <b>输出：</b>4
 <b>解释：</b>4 次操作后，集合中的元素依次添加了 2 ，4 ，5 和 1 。此时集合中包含元素 1 和 2 ，所以答案为 4 。
 </pre>
 
 <p><strong class="example">示例 2：</strong></p>
 
-<pre><b>输入：</b>nums = [3,1,5,4,2], k = 5
+<pre>
+<b>输入：</b>nums = [3,1,5,4,2], k = 5
 <b>输出：</b>5
 <b>解释：</b>5 次操作后，集合中的元素依次添加了 2 ，4 ，5 ，1 和 3 。此时集合中包含元素 1 到 5 ，所以答案为 5 。
 </pre>
 
 <p><strong class="example">示例 3：</strong></p>
 
-<pre><b>输入：</b>nums = [3,2,5,3,1], k = 3
+<pre>
+<b>输入：</b>nums = [3,2,5,3,1], k = 3
 <b>输出：</b>4
 <b>解释：</b>4 次操作后，集合中的元素依次添加了 1 ，3 ，5 和 2 。此时集合中包含元素 1 到 3  ，所以答案为 4 。
 </pre>

diff --git a/solution/2800-2899/2869.Minimum Operations to Collect Elements/README_EN.md b/solution/2800-2899/2869.Minimum Operations to Collect Elements/README_EN.md
@@ -4,28 +4,33 @@
 
 ## Description
 
+<p>You are given an array <code>nums</code> of positive integers and an integer <code>k</code>.</p>
+
 <p>In one operation, you can remove the last element of the array and add it to your collection.</p>
 
 <p>Return <em>the <strong>minimum number of operations</strong> needed to collect elements</em> <code>1, 2, ..., k</code>.</p>
 
 <p>&nbsp;</p>
 <p><strong class="example">Example 1:</strong></p>
 
-<pre><strong>Input:</strong> nums = [3,1,5,4,2], k = 2
+<pre>
+<strong>Input:</strong> nums = [3,1,5,4,2], k = 2
 <strong>Output:</strong> 4
 <strong>Explanation:</strong> After 4 operations, we collect elements 2, 4, 5, and 1, in this order. Our collection contains elements 1 and 2. Hence, the answer is 4.
 </pre>
 
 <p><strong class="example">Example 2:</strong></p>
 
-<pre><strong>Input:</strong> nums = [3,1,5,4,2], k = 5
+<pre>
+<strong>Input:</strong> nums = [3,1,5,4,2], k = 5
 <strong>Output:</strong> 5
 <strong>Explanation:</strong> After 5 operations, we collect elements 2, 4, 5, 1, and 3, in this order. Our collection contains elements 1 through 5. Hence, the answer is 5.
 </pre>
 
 <p><strong class="example">Example 3:</strong></p>
 
-<pre><strong>Input:</strong> nums = [3,2,5,3,1], k = 3
+<pre>
+<strong>Input:</strong> nums = [3,2,5,3,1], k = 3
 <strong>Output:</strong> 4
 <strong>Explanation:</strong> After 4 operations, we collect elements 1, 3, 5, and 2, in this order. Our collection contains elements 1 through 3. Hence, the answer is 4.
 </pre>

diff --git a/solution/2800-2899/2870.Minimum Number of Operations to Make Array Empty/README.md b/solution/2800-2899/2870.Minimum Number of Operations to Make Array Empty/README.md
@@ -1,11 +1,13 @@
-# [2870. Minimum Number of Operations to Make Array Empty](https://leetcode.cn/problems/minimum-number-of-operations-to-make-array-empty/)
+# [2870. 使数组为空的最少操作次数](https://leetcode.cn/problems/minimum-number-of-operations-to-make-array-empty/)
 
 [English Version](/solution/2800-2899/2870.Minimum%20Number%20of%20Operations%20to%20Make%20Array%20Empty/README_EN.md)
 
 ## 题目描述
 
 <!-- 这里写题目描述 -->
 
+<p>给你一个下标从 <strong>0</strong>&nbsp;开始的正整数数组&nbsp;<code>nums</code>&nbsp;。</p>
+
 <p>你可以对数组执行以下两种操作 <strong>任意次</strong>&nbsp;：</p>
 
 <ul>
@@ -19,7 +21,8 @@
 
 <p><strong class="example">示例 1：</strong></p>
 
-<pre><strong>输入：</strong>nums = [2,3,3,2,2,4,2,3,4]
+<pre>
+<strong>输入：</strong>nums = [2,3,3,2,2,4,2,3,4]
 <b>输出：</b>4
 <b>解释：</b>我们可以执行以下操作使数组为空：
 - 对下标为 0 和 3 的元素执行第一种操作，得到 nums = [3,3,2,4,2,3,4] 。
@@ -31,7 +34,8 @@
 
 <p><strong class="example">示例 2：</strong></p>
 
-<pre><b>输入：</b>nums = [2,1,2,2,3,3]
+<pre>
+<b>输入：</b>nums = [2,1,2,2,3,3]
 <b>输出：</b>-1
 <b>解释：</b>无法使数组为空。
 </pre>

diff --git a/...on/2800-2899/2870.Minimum Number of Operations to Make Array Empty/README_EN.md b/...on/2800-2899/2870.Minimum Number of Operations to Make Array Empty/README_EN.md
@@ -4,6 +4,8 @@
 
 ## Description
 
+<p>You are given a <strong>0-indexed</strong> array <code>nums</code> consisting of positive integers.</p>
+
 <p>There are two types of operations that you can apply on the array <strong>any</strong> number of times:</p>
 
 <ul>
@@ -16,7 +18,8 @@
 <p>&nbsp;</p>
 <p><strong class="example">Example 1:</strong></p>
 
-<pre><strong>Input:</strong> nums = [2,3,3,2,2,4,2,3,4]
+<pre>
+<strong>Input:</strong> nums = [2,3,3,2,2,4,2,3,4]
 <strong>Output:</strong> 4
 <strong>Explanation:</strong> We can apply the following operations to make the array empty:
 - Apply the first operation on the elements at indices 0 and 3. The resulting array is nums = [3,3,2,4,2,3,4].
@@ -28,7 +31,8 @@ It can be shown that we cannot make the array empty in less than 4 operations.
 
 <p><strong class="example">Example 2:</strong></p>
 
-<pre><strong>Input:</strong> nums = [2,1,2,2,3,3]
+<pre>
+<strong>Input:</strong> nums = [2,1,2,2,3,3]
 <strong>Output:</strong> -1
 <strong>Explanation:</strong> It is impossible to empty the array.
 </pre>

diff --git a/solution/2800-2899/2871.Split Array Into Maximum Number of Subarrays/README.md b/solution/2800-2899/2871.Split Array Into Maximum Number of Subarrays/README.md
@@ -1,11 +1,13 @@
-# [2871. Split Array Into Maximum Number of Subarrays](https://leetcode.cn/problems/split-array-into-maximum-number-of-subarrays/)
+# [2871. 将数组分割成最多数目的子数组](https://leetcode.cn/problems/split-array-into-maximum-number-of-subarrays/)
 
 [English Version](/solution/2800-2899/2871.Split%20Array%20Into%20Maximum%20Number%20of%20Subarrays/README_EN.md)
 
 ## 题目描述
 
 <!-- 这里写题目描述 -->
 
+<p>给你一个只包含 <strong>非负</strong>&nbsp;整数的数组&nbsp;<code>nums</code>&nbsp;。</p>
+
 <p>我们定义满足 <code>l &lt;= r</code>&nbsp;的子数组&nbsp;<code>nums[l..r]</code>&nbsp;的分数为&nbsp;<code>nums[l] AND nums[l + 1] AND ... AND nums[r]</code>&nbsp;，其中&nbsp;<strong>AND</strong>&nbsp;是按位与运算。</p>
 
 <p>请你将数组分割成一个或者更多子数组，满足：</p>
@@ -23,7 +25,8 @@
 
 <p><strong class="example">示例 1：</strong></p>
 
-<pre><b>输入：</b>nums = [1,0,2,0,1,2]
+<pre>
+<b>输入：</b>nums = [1,0,2,0,1,2]
 <b>输出：</b>3
 <strong>解释：</strong>我们可以将数组分割成以下子数组：
 - [1,0] 。子数组分数为 1 AND 0 = 0 。
@@ -35,7 +38,8 @@
 
 <p><strong class="example">示例 2：</strong></p>
 
-<pre><b>输入：</b>nums = [5,7,1,3]
+<pre>
+<b>输入：</b>nums = [5,7,1,3]
 <b>输出：</b>1
 <b>解释：</b>我们可以将数组分割成一个子数组：[5,7,1,3] ，分数为 1 ，这是可以得到的最小总分数。
 在总分数为 1 的前提下，最多可以将数组分割成 1 个子数组。所以返回 1 。

diff --git a/solution/2800-2899/2871.Split Array Into Maximum Number of Subarrays/README_EN.md b/solution/2800-2899/2871.Split Array Into Maximum Number of Subarrays/README_EN.md
@@ -4,6 +4,8 @@
 
 ## Description
 
+<p>You are given an array <code>nums</code> consisting of <strong>non-negative</strong> integers.</p>
+
 <p>We define the score of subarray <code>nums[l..r]</code> such that <code>l &lt;= r</code> as <code>nums[l] AND nums[l + 1] AND ... AND nums[r]</code> where <strong>AND</strong> is the bitwise <code>AND</code> operation.</p>
 
 <p>Consider splitting the array into one or more subarrays such that the following conditions are satisfied:</p>
@@ -20,7 +22,8 @@
 <p>&nbsp;</p>
 <p><strong class="example">Example 1:</strong></p>
 
-<pre><strong>Input:</strong> nums = [1,0,2,0,1,2]
+<pre>
+<strong>Input:</strong> nums = [1,0,2,0,1,2]
 <strong>Output:</strong> 3
 <strong>Explanation:</strong> We can split the array into the following subarrays:
 - [1,0]. The score of this subarray is 1 AND 0 = 0.
@@ -32,7 +35,8 @@ It can be shown that we cannot split the array into more than 3 subarrays with a
 
 <p><strong class="example">Example 2:</strong></p>
 
-<pre><strong>Input:</strong> nums = [5,7,1,3]
+<pre>
+<strong>Input:</strong> nums = [5,7,1,3]
 <strong>Output:</strong> 1
 <strong>Explanation:</strong> We can split the array into one subarray: [5,7,1,3] with a score of 1, which is the minimum possible score that we can obtain.
 It can be shown that we cannot split the array into more than 1 subarray with a total score of 1. So we return 1.

diff --git a/solution/2800-2899/2872.Maximum Number of K-Divisible Components/README.md b/solution/2800-2899/2872.Maximum Number of K-Divisible Components/README.md
@@ -1,4 +1,4 @@
-# [2872. Maximum Number of K-Divisible Components](https://leetcode.com/problems/maximum-number-of-k-divisible-components/)
+# [2872. 可以被 K 整除连通块的最大数目](https://leetcode.com/problems/maximum-number-of-k-divisible-components/)
 
 [English Version](/solution/2800-2899/2872.Maximum%20Number%20of%20K-Divisible%20Components/README_EN.md)
 
@@ -18,9 +18,10 @@
 
 <p><strong class="example">示例 1：</strong></p>
 
-<p><img alt="" src="./images/example1.jpg" style="width: 1024px; height: 453px;"></p>
+<p><img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/2800-2899/2872.Maximum%20Number%20of%20K-Divisible%20Components/images/example12-cropped2svg.jpg" style="width: 1024px; height: 453px;" /></p>
 
-<pre><b>输入：</b>n = 5, edges = [[0,2],[1,2],[1,3],[2,4]], values = [1,8,1,4,4], k = 6
+<pre>
+<b>输入：</b>n = 5, edges = [[0,2],[1,2],[1,3],[2,4]], values = [1,8,1,4,4], k = 6
 <b>输出：</b>2
 <b>解释：</b>我们删除节点 1 和 2 之间的边。这是一个合法分割，因为：
 - 节点 1 和 3 所在连通块的值为 values[1] + values[3] = 12 。
@@ -29,9 +30,10 @@
 
 <p><strong class="example">示例 2：</strong></p>
 
-<p><img alt="" src="./images/example2.jpg" style="width: 999px; height: 338px;"></p>
+<p><img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/2800-2899/2872.Maximum%20Number%20of%20K-Divisible%20Components/images/example21svg-1.jpg" style="width: 999px; height: 338px;" /></p>
 
-<pre><b>输入：</b>n = 7, edges = [[0,1],[0,2],[1,3],[1,4],[2,5],[2,6]], values = [3,0,6,1,5,2,1], k = 3
+<pre>
+<b>输入：</b>n = 7, edges = [[0,1],[0,2],[1,3],[1,4],[2,5],[2,6]], values = [3,0,6,1,5,2,1], k = 3
 <b>输出：</b>3
 <b>解释：</b>我们删除节点 0 和 2 ，以及节点 0 和 1 之间的边。这是一个合法分割，因为：
 - 节点 0 的连通块的值为 values[0] = 3 。

diff --git a/solution/2800-2899/2872.Maximum Number of K-Divisible Components/README_EN.md b/solution/2800-2899/2872.Maximum Number of K-Divisible Components/README_EN.md
@@ -14,17 +14,19 @@
 
 <p>&nbsp;</p>
 <p><strong class="example">Example 1:</strong></p>
-<img alt="" src="./images/example1.jpg" style="width: 1024px; height: 453px;">
-<pre><strong>Input:</strong> n = 5, edges = [[0,2],[1,2],[1,3],[2,4]], values = [1,8,1,4,4], k = 6
+<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/2800-2899/2872.Maximum%20Number%20of%20K-Divisible%20Components/images/example12-cropped2svg.jpg" style="width: 1024px; height: 453px;" />
+<pre>
+<strong>Input:</strong> n = 5, edges = [[0,2],[1,2],[1,3],[2,4]], values = [1,8,1,4,4], k = 6
 <strong>Output:</strong> 2
 <strong>Explanation:</strong> We remove the edge connecting node 1 with 2. The resulting split is valid because:
 - The value of the component containing nodes 1 and 3 is values[1] + values[3] = 12.
 - The value of the component containing nodes 0, 2, and 4 is values[0] + values[2] + values[4] = 6.
 It can be shown that no other valid split has more than 2 connected components.</pre>
 
 <p><strong class="example">Example 2:</strong></p>
-<img alt="" src="./images/example2.jpg" style="width: 999px; height: 338px;">
-<pre><strong>Input:</strong> n = 7, edges = [[0,1],[0,2],[1,3],[1,4],[2,5],[2,6]], values = [3,0,6,1,5,2,1], k = 3
+<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/2800-2899/2872.Maximum%20Number%20of%20K-Divisible%20Components/images/example21svg-1.jpg" style="width: 999px; height: 338px;" />
+<pre>
+<strong>Input:</strong> n = 7, edges = [[0,1],[0,2],[1,3],[1,4],[2,5],[2,6]], values = [3,0,6,1,5,2,1], k = 3
 <strong>Output:</strong> 3
 <strong>Explanation:</strong> We remove the edge connecting node 0 with 2, and the edge connecting node 0 with 1. The resulting split is valid because:
 - The value of the component containing node 0 is values[0] = 3.

diff --git a/solution/CONTEST_README.md b/solution/CONTEST_README.md
@@ -22,6 +22,13 @@
 
 ## 往期竞赛
 
+#### 第 114 场双周赛(2023-09-30 22:30, 90 分钟) 参赛人数 2406
+
+- [2869. 收集元素的最少操作次数](/solution/2800-2899/2869.Minimum%20Operations%20to%20Collect%20Elements/README.md)
+- [2870. 使数组为空的最少操作次数](/solution/2800-2899/2870.Minimum%20Number%20of%20Operations%20to%20Make%20Array%20Empty/README.md)
+- [2871. 将数组分割成最多数目的子数组](/solution/2800-2899/2871.Split%20Array%20Into%20Maximum%20Number%20of%20Subarrays/README.md)
+- [2872. 可以被 K 整除连通块的最大数目](/solution/2800-2899/2872.Maximum%20Number%20of%20K-Divisible%20Components/README.md)
+
 #### 第 364 场周赛(2023-09-24 10:30, 90 分钟) 参赛人数 4304
 
 - [2864. 最大二进制奇数](/solution/2800-2899/2864.Maximum%20Odd%20Binary%20Number/README.md)

diff --git a/solution/CONTEST_README_EN.md b/solution/CONTEST_README_EN.md
@@ -25,6 +25,13 @@ Get your rating changes right after the completion of LeetCode contests, https:/
 
 ## Past Contests
 
+#### Biweekly Contest 114
+
+- [2869. Minimum Operations to Collect Elements](/solution/2800-2899/2869.Minimum%20Operations%20to%20Collect%20Elements/README_EN.md)
+- [2870. Minimum Number of Operations to Make Array Empty](/solution/2800-2899/2870.Minimum%20Number%20of%20Operations%20to%20Make%20Array%20Empty/README_EN.md)
+- [2871. Split Array Into Maximum Number of Subarrays](/solution/2800-2899/2871.Split%20Array%20Into%20Maximum%20Number%20of%20Subarrays/README_EN.md)
+- [2872. Maximum Number of K-Divisible Components](/solution/2800-2899/2872.Maximum%20Number%20of%20K-Divisible%20Components/README_EN.md)
+
 #### Weekly Contest 364
 
 - [2864. Maximum Odd Binary Number](/solution/2800-2899/2864.Maximum%20Odd%20Binary%20Number/README_EN.md)

diff --git a/solution/README.md b/solution/README.md
@@ -2879,6 +2879,10 @@
 |  2866  |  [美丽塔 II](/solution/2800-2899/2866.Beautiful%20Towers%20II/README.md)  |  `栈`,`数组`,`单调栈`  |  中等  |  第 364 场周赛  |
 |  2867  |  [统计树中的合法路径数目](/solution/2800-2899/2867.Count%20Valid%20Paths%20in%20a%20Tree/README.md)  |  `树`,`深度优先搜索`,`数学`,`动态规划`,`数论`  |  困难  |  第 364 场周赛  |
 |  2868  |  [单词游戏](/solution/2800-2899/2868.The%20Wording%20Game/README.md)  |    |  困难  |  🔒  |
+|  2869  |  [收集元素的最少操作次数](/solution/2800-2899/2869.Minimum%20Operations%20to%20Collect%20Elements/README.md)  |    |  简单  |  第 114 场双周赛  |
+|  2870  |  [使数组为空的最少操作次数](/solution/2800-2899/2870.Minimum%20Number%20of%20Operations%20to%20Make%20Array%20Empty/README.md)  |    |  中等  |  第 114 场双周赛  |
+|  2871  |  [将数组分割成最多数目的子数组](/solution/2800-2899/2871.Split%20Array%20Into%20Maximum%20Number%20of%20Subarrays/README.md)  |    |  中等  |  第 114 场双周赛  |
+|  2872  |  [可以被 K 整除连通块的最大数目](/solution/2800-2899/2872.Maximum%20Number%20of%20K-Divisible%20Components/README.md)  |    |  困难  |  第 114 场双周赛  |
 
 ## 版权
 

diff --git a/solution/README_EN.md b/solution/README_EN.md
@@ -2877,6 +2877,10 @@ Press <kbd>Control</kbd> + <kbd>F</kbd>(or <kbd>Command</kbd> + <kbd>F</kbd> on
 |  2866  |  [Beautiful Towers II](/solution/2800-2899/2866.Beautiful%20Towers%20II/README_EN.md)  |  `Stack`,`Array`,`Monotonic Stack`  |  Medium  |  Weekly Contest 364  |
 |  2867  |  [Count Valid Paths in a Tree](/solution/2800-2899/2867.Count%20Valid%20Paths%20in%20a%20Tree/README_EN.md)  |  `Tree`,`Depth-First Search`,`Math`,`Dynamic Programming`,`Number Theory`  |  Hard  |  Weekly Contest 364  |
 |  2868  |  [The Wording Game](/solution/2800-2899/2868.The%20Wording%20Game/README_EN.md)  |    |  Hard  |  🔒  |
+|  2869  |  [Minimum Operations to Collect Elements](/solution/2800-2899/2869.Minimum%20Operations%20to%20Collect%20Elements/README_EN.md)  |    |  Easy  |  Biweekly Contest 114  |
+|  2870  |  [Minimum Number of Operations to Make Array Empty](/solution/2800-2899/2870.Minimum%20Number%20of%20Operations%20to%20Make%20Array%20Empty/README_EN.md)  |    |  Medium  |  Biweekly Contest 114  |
+|  2871  |  [Split Array Into Maximum Number of Subarrays](/solution/2800-2899/2871.Split%20Array%20Into%20Maximum%20Number%20of%20Subarrays/README_EN.md)  |    |  Medium  |  Biweekly Contest 114  |
+|  2872  |  [Maximum Number of K-Divisible Components](/solution/2800-2899/2872.Maximum%20Number%20of%20K-Divisible%20Components/README_EN.md)  |    |  Hard  |  Biweekly Contest 114  |
 
 ## Copyright
 

diff --git a/solution/summary.md b/solution/summary.md
@@ -2924,3 +2924,7 @@
   - [2866.美丽塔 II](/solution/2800-2899/2866.Beautiful%20Towers%20II/README.md)
   - [2867.统计树中的合法路径数目](/solution/2800-2899/2867.Count%20Valid%20Paths%20in%20a%20Tree/README.md)
   - [2868.单词游戏](/solution/2800-2899/2868.The%20Wording%20Game/README.md)
+  - [2869.收集元素的最少操作次数](/solution/2800-2899/2869.Minimum%20Operations%20to%20Collect%20Elements/README.md)
+  - [2870.使数组为空的最少操作次数](/solution/2800-2899/2870.Minimum%20Number%20of%20Operations%20to%20Make%20Array%20Empty/README.md)
+  - [2871.将数组分割成最多数目的子数组](/solution/2800-2899/2871.Split%20Array%20Into%20Maximum%20Number%20of%20Subarrays/README.md)
+  - [2872.可以被 K 整除连通块的最大数目](/solution/2800-2899/2872.Maximum%20Number%20of%20K-Divisible%20Components/README.md)
diff --git a/solution/summary_en.md b/solution/summary_en.md
@@ -2924,3 +2924,7 @@
   - [2866.Beautiful Towers II](/solution/2800-2899/2866.Beautiful%20Towers%20II/README_EN.md)
   - [2867.Count Valid Paths in a Tree](/solution/2800-2899/2867.Count%20Valid%20Paths%20in%20a%20Tree/README_EN.md)
   - [2868.The Wording Game](/solution/2800-2899/2868.The%20Wording%20Game/README_EN.md)
+  - [2869.Minimum Operations to Collect Elements](/solution/2800-2899/2869.Minimum%20Operations%20to%20Collect%20Elements/README_EN.md)
+  - [2870.Minimum Number of Operations to Make Array Empty](/solution/2800-2899/2870.Minimum%20Number%20of%20Operations%20to%20Make%20Array%20Empty/README_EN.md)
+  - [2871.Split Array Into Maximum Number of Subarrays](/solution/2800-2899/2871.Split%20Array%20Into%20Maximum%20Number%20of%20Subarrays/README_EN.md)
+  - [2872.Maximum Number of K-Divisible Components](/solution/2800-2899/2872.Maximum%20Number%20of%20K-Divisible%20Components/README_EN.md)