Dev lc610

.prettierrc

@@ -14,6 +14,7 @@
         {
             "files": [
                 "solution/0500-0599/0578.Get Highest Answer Rate Question/Solution.sql",
+                "solution/0600-0699/0610.Triangle Judgement/Solution.sql",
                 "solution/0600-0699/0618.Students Report By Geography/Solution.sql",
                 "solution/0600-0699/0626.Exchange Seats/Solution.sql",
                 "solution/1000-1099/1098.Unpopular Books/Solution.sql",

solution/0600-0699/0610.Triangle Judgement/README.md

@@ -53,12 +53,20 @@ Triangle 表:
 
 <!-- 这里可写通用的实现逻辑 -->
 
+**方法一：if 语句 + 三角形判断条件**
+
+三条边能否构成三角形的条件是：任意两边之和大于第三边。因此，我们可以使用 `if` 语句来判断是否满足这个条件，如果满足则返回 `Yes`，否则返回 `No`。
+
 <!-- tabs:start -->
 
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    *,
+    if(x + y > z AND x + z > y AND y + z > x, 'Yes', 'No') AS triangle
+FROM Triangle;
 ```
 
 <!-- tabs:end -->

solution/0600-0699/0610.Triangle Judgement/README_EN.md

@@ -54,7 +54,11 @@ Triangle table:
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    *,
+    if(x + y > z AND x + z > y AND y + z > x, 'Yes', 'No') AS triangle
+FROM Triangle;
 ```
 
 <!-- tabs:end -->

solution/0600-0699/0610.Triangle Judgement/Solution.sql

@@ -0,0 +1,5 @@
+# Write your MySQL query statement below
+SELECT
+    *,
+    if(x + y > z AND x + z > y AND y + z > x, 'Yes', 'No') AS triangle
+FROM Triangle;