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Original file line number | Diff line number | Diff line change |
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""" | ||
In the Combination Sum problem, we are given a list consisting of distinct integers. | ||
We need to find all the combinations whose sum equals to target given. | ||
We can use an element more than one. | ||
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Time complexity(Average Case): O(n!) | ||
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Constraints: | ||
1 <= candidates.length <= 30 | ||
2 <= candidates[i] <= 40 | ||
All elements of candidates are distinct. | ||
1 <= target <= 40 | ||
""" | ||
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def backtrack( | ||
candidates: list, path: list, answer: list, target: int, previous_index: int | ||
) -> None: | ||
""" | ||
A recursive function that searches for possible combinations. Backtracks in case | ||
of a bigger current combination value than the target value. | ||
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Parameters | ||
---------- | ||
previous_index: Last index from the previous search | ||
target: The value we need to obtain by summing our integers in the path list. | ||
answer: A list of possible combinations | ||
path: Current combination | ||
candidates: A list of integers we can use. | ||
""" | ||
if target == 0: | ||
answer.append(path.copy()) | ||
else: | ||
for index in range(previous_index, len(candidates)): | ||
if target >= candidates[index]: | ||
path.append(candidates[index]) | ||
backtrack(candidates, path, answer, target - candidates[index], index) | ||
path.pop(len(path) - 1) | ||
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def combination_sum(candidates: list, target: int) -> list: | ||
""" | ||
>>> combination_sum([2, 3, 5], 8) | ||
[[2, 2, 2, 2], [2, 3, 3], [3, 5]] | ||
>>> combination_sum([2, 3, 6, 7], 7) | ||
[[2, 2, 3], [7]] | ||
>>> combination_sum([-8, 2.3, 0], 1) | ||
Traceback (most recent call last): | ||
... | ||
RecursionError: maximum recursion depth exceeded in comparison | ||
""" | ||
path = [] # type: list[int] | ||
answer = [] # type: list[int] | ||
backtrack(candidates, path, answer, target, 0) | ||
return answer | ||
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def main() -> None: | ||
print(combination_sum([-8, 2.3, 0], 1)) | ||
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if __name__ == "__main__": | ||
import doctest | ||
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doctest.testmod() | ||
main() |
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