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57 | 57 |
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58 | 58 | <!-- 这里可写通用的实现逻辑 -->
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59 | 59 |
|
| 60 | +二分查找。 |
| 61 | + |
60 | 62 | <!-- tabs:start -->
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61 | 63 |
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62 | 64 | ### **Python3**
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63 | 65 |
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64 | 66 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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65 | 67 |
|
66 | 68 | ```python
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67 |
| - |
| 69 | +class Solution: |
| 70 | + def minEatingSpeed(self, piles: List[int], h: int) -> int: |
| 71 | + left, right = 1, max(piles) |
| 72 | + while left < right: |
| 73 | + mid = (left + right) >> 1 |
| 74 | + s = sum((pile + mid - 1) // mid for pile in piles) |
| 75 | + if s <= h: |
| 76 | + right = mid |
| 77 | + else: |
| 78 | + left = mid + 1 |
| 79 | + return left |
68 | 80 | ```
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69 | 81 |
|
70 | 82 | ### **Java**
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71 | 83 |
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72 | 84 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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73 | 85 |
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74 | 86 | ```java
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| 87 | +class Solution { |
| 88 | + public int minEatingSpeed(int[] piles, int h) { |
| 89 | + int mx = 0; |
| 90 | + for (int pile : piles) { |
| 91 | + mx = Math.max(mx, pile); |
| 92 | + } |
| 93 | + int left = 1, right = mx; |
| 94 | + while (left < right) { |
| 95 | + int mid = (left + right) >>> 1; |
| 96 | + int s = 0; |
| 97 | + for (int pile : piles) { |
| 98 | + s += (pile + mid - 1) / mid; |
| 99 | + } |
| 100 | + if (s <= h) { |
| 101 | + right = mid; |
| 102 | + } else { |
| 103 | + left = mid + 1; |
| 104 | + } |
| 105 | + } |
| 106 | + return left; |
| 107 | + } |
| 108 | +} |
| 109 | +``` |
| 110 | + |
| 111 | +### **C++** |
| 112 | + |
| 113 | +```cpp |
| 114 | +class Solution { |
| 115 | +public: |
| 116 | + int minEatingSpeed(vector<int>& piles, int h) { |
| 117 | + int left = 1, right = *max_element(piles.begin(), piles.end()); |
| 118 | + while (left < right) |
| 119 | + { |
| 120 | + int mid = left + right >> 1; |
| 121 | + int s = 0; |
| 122 | + for (int pile : piles) s += (pile + mid - 1) / mid; |
| 123 | + if (s <= h) right = mid; |
| 124 | + else left = mid + 1; |
| 125 | + } |
| 126 | + return left; |
| 127 | + } |
| 128 | +}; |
| 129 | +``` |
| 130 | +
|
| 131 | +### **Go** |
| 132 | +
|
| 133 | +```go |
| 134 | +func minEatingSpeed(piles []int, h int) int { |
| 135 | + mx := 0 |
| 136 | + for _, pile := range piles { |
| 137 | + mx = max(mx, pile) |
| 138 | + } |
| 139 | + left, right := 1, mx |
| 140 | + for left < right { |
| 141 | + mid := (left + right) >> 1 |
| 142 | + s := 0 |
| 143 | + for _, pile := range piles { |
| 144 | + s += (pile + mid - 1) / mid |
| 145 | + } |
| 146 | + if s <= h { |
| 147 | + right = mid |
| 148 | + } else { |
| 149 | + left = mid + 1 |
| 150 | + } |
| 151 | + } |
| 152 | + return left |
| 153 | +} |
| 154 | +
|
| 155 | +func max(a, b int) int { |
| 156 | + if a > b { |
| 157 | + return a |
| 158 | + } |
| 159 | + return b |
| 160 | +} |
| 161 | +``` |
75 | 162 |
|
| 163 | +### **C#** |
| 164 | + |
| 165 | +```cs |
| 166 | +public class Solution { |
| 167 | + public int MinEatingSpeed(int[] piles, int h) { |
| 168 | + int left = 1, right = piles.Max(); |
| 169 | + while (left < right) |
| 170 | + { |
| 171 | + int mid = (left + right) >> 1; |
| 172 | + int s = 0; |
| 173 | + foreach (int pile in piles) |
| 174 | + { |
| 175 | + s += (pile + mid - 1) / mid; |
| 176 | + } |
| 177 | + if (s <= h) |
| 178 | + { |
| 179 | + right = mid; |
| 180 | + } |
| 181 | + else |
| 182 | + { |
| 183 | + left = mid + 1; |
| 184 | + } |
| 185 | + } |
| 186 | + return left; |
| 187 | + } |
| 188 | +} |
76 | 189 | ```
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77 | 190 |
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78 | 191 | ### **...**
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