给定一个整数 n,生成所有由 1 ... n 为节点所组成的 二叉搜索树 。
示例:
输入:3 输出: [ [1,null,3,2], [3,2,null,1], [3,1,null,null,2], [2,1,3], [1,null,2,null,3] ] 解释: 以上的输出对应以下 5 种不同结构的二叉搜索树: 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3
提示:
0 <= n <= 8
/**
* Definition for a binary tree node.
* class TreeNode {
* val: number
* left: TreeNode | null
* right: TreeNode | null
* constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
* }
*/
function generateTrees(n: number): Array<TreeNode | null> {
if (n == 0) return [];
return helper(1, n);
};
function helper (start: number, end: number): Array<TreeNode | null> {
let ans = [];
if (start > end) {
ans.push(null);
return ans;
}
for (let i = start; i <= end; i++) {
let lefts = helper(start, i - 1);
let rights = helper(i + 1, end);
for (let left of lefts) {
for (let right of rights) {
let root = new TreeNode(i);
root.left = left;
root.right = right;
ans.push(root);
}
}
}
return ans;
}