leetcode 177,178

Author: LjyYano

lcof/面试题03. 数组中重复的数字/README.md

@@ -35,7 +35,8 @@ class Solution:
                 if num == nums[num]:
                     return num
                 nums[i], nums[num] = nums[num], nums[i]
-
+                num = nums[i]
+        return -1
 ```
 
 ### **Java**
@@ -96,4 +97,4 @@ func findRepeatNumber(nums []int) int {
 ```
 
 ```
-<!-- tabs:end -->
+<!-- tabs:end -->

lcof/面试题03. 数组中重复的数字/Solution.py

@@ -5,3 +5,5 @@ def findRepeatNumber(self, nums: List[int]) -> int:
                 if num == nums[num]:
                     return num
                 nums[i], nums[num] = nums[num], nums[i]
+                num = nums[i]
+        return -1

solution/0100-0199/0175.Combine Two Tables/README.md

@@ -46,23 +46,10 @@ AddressId 是上表主键
 
 <!-- tabs:start -->
 
-### **Python3**
-<!-- 这里可写当前语言的特殊实现逻辑 -->
+### **SQL**
 
-```python
-
-```
-
-### **Java**
-<!-- 这里可写当前语言的特殊实现逻辑 -->
-
-```java
-
-```
-
-### **...**
 ```
-
+select p.FirstName, p.LastName, a.City, a.State from Person p left join Address a on p.PersonId = a.PersonId;
 ```
 
 <!-- tabs:end -->

solution/0100-0199/0175.Combine Two Tables/README_EN.md

@@ -76,24 +76,12 @@ FirstName, LastName, City, State
 
 ## Solutions
 
-
 <!-- tabs:start -->
 
-### **Python3**
-
-```python
+### **SQL**
 
 ```
-
-### **Java**
-
-```java
-
-```
-
-### **...**
-```
-
+select p.FirstName, p.LastName, a.City, a.State from Person p left join Address a on p.PersonId = a.PersonId;
 ```
 
 <!-- tabs:end -->

solution/0100-0199/0176.Second Highest Salary/README.md

@@ -32,21 +32,8 @@
 
 <!-- tabs:start -->
 
-### **Python3**
-<!-- 这里可写当前语言的特殊实现逻辑 -->
+### **SQL**
 
-```python
-
-```
-
-### **Java**
-<!-- 这里可写当前语言的特殊实现逻辑 -->
-
-```java
-
-```
-
-### **sql**
 ```
 select (select distinct Salary from Employee order by Salary desc limit 1 offset 1) as 
 SecondHighestSalary;

solution/0100-0199/0176.Second Highest Salary/README_EN.md

@@ -53,19 +53,8 @@
 
 <!-- tabs:start -->
 
-### **Python3**
+### **SQL**
 
-```python
-
-```
-
-### **Java**
-
-```java
-
-```
-
-### **sql**
 ```
 select (select distinct Salary from Employee order by Salary desc limit 1 offset 1) as 
 SecondHighestSalary;

solution/0100-0199/0177.Nth Highest Salary/README.md

@@ -32,21 +32,8 @@
 
 <!-- tabs:start -->
 
-### **Python3**
-<!-- 这里可写当前语言的特殊实现逻辑 -->
+### **SQL**
 
-```python
-
-```
-
-### **Java**
-<!-- 这里可写当前语言的特殊实现逻辑 -->
-
-```java
-
-```
-
-### **sql**
 ```
 CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
 BEGIN

solution/0100-0199/0177.Nth Highest Salary/README_EN.md

@@ -53,19 +53,8 @@
 
 <!-- tabs:start -->
 
-### **Python3**
+### **SQL**
 
-```python
-
-```
-
-### **Java**
-
-```java
-
-```
-
-### **sql**
 ```
 CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
 BEGIN

solution/0100-0199/0178.Rank Scores/README.md

@@ -40,26 +40,14 @@
 
 <!-- tabs:start -->
 
-### **Python3**
-<!-- 这里可写当前语言的特殊实现逻辑 -->
+### **SQL**
 
-```python
-
-```
-
-### **Java**
-<!-- 这里可写当前语言的特殊实现逻辑 -->
-
-```java
-
-```
-
-### **sql**
 ```
 select
     Score,
     (select count(*) from (select distinct Score s from Scores) tmp where s>=Score) Rank
 from Scores order by Rank;
+
 ```
 
 <!-- tabs:end -->

solution/0100-0199/0178.Rank Scores/README_EN.md

@@ -69,24 +69,14 @@
 
 <!-- tabs:start -->
 
-### **Python3**
+### **SQL**
 
-```python
-
-```
-
-### **Java**
-
-```java
-
-```
-
-### **sql**
 ```
 select
     Score,
     (select count(*) from (select distinct Score s from Scores) tmp where s>=Score) Rank
 from Scores order by Rank;
+
 ```
 
 <!-- tabs:end -->