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18 | 18 |
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19 | 19 | <!-- 这里可写通用的实现逻辑 -->
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20 | 20 |
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| 21 | +**方法一:模拟** |
| 22 | + |
| 23 | +按照题意模拟即可。 |
| 24 | + |
| 25 | +时间复杂度 $O(n)$,忽略答案的空间消耗,空间复杂度 $O(1)$。其中 $n$ 为数组 `nums` 的长度。 |
| 26 | + |
21 | 27 | <!-- tabs:start -->
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22 | 28 |
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23 | 29 | ### **Python3**
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24 | 30 |
|
25 | 31 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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26 | 32 |
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27 | 33 | ```python
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28 |
| - |
| 34 | +class Solution: |
| 35 | + def findMissingRanges(self, nums: List[int], lower: int, upper: int) -> List[str]: |
| 36 | + def f(a, b): |
| 37 | + return str(a) if a == b else f'{a}->{b}' |
| 38 | + |
| 39 | + n = len(nums) |
| 40 | + if n == 0: |
| 41 | + return [f(lower, upper)] |
| 42 | + ans = [] |
| 43 | + if nums[0] > lower: |
| 44 | + ans.append(f(lower, nums[0] - 1)) |
| 45 | + for a, b in pairwise(nums): |
| 46 | + if b - a > 1: |
| 47 | + ans.append(f(a + 1, b - 1)) |
| 48 | + if nums[-1] < upper: |
| 49 | + ans.append(f(nums[-1] + 1, upper)) |
| 50 | + return ans |
29 | 51 | ```
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30 | 52 |
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31 | 53 | ### **Java**
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32 | 54 |
|
33 | 55 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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34 | 56 |
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35 | 57 | ```java
|
| 58 | +class Solution { |
| 59 | + public List<String> findMissingRanges(int[] nums, int lower, int upper) { |
| 60 | + int n = nums.length; |
| 61 | + List<String> ans = new ArrayList<>(); |
| 62 | + if (n == 0) { |
| 63 | + ans.add(f(lower, upper)); |
| 64 | + return ans; |
| 65 | + } |
| 66 | + if (nums[0] > lower) { |
| 67 | + ans.add(f(lower, nums[0] - 1)); |
| 68 | + } |
| 69 | + for (int i = 1; i < n; ++i) { |
| 70 | + int a = nums[i - 1], b = nums[i]; |
| 71 | + if (b - a > 1) { |
| 72 | + ans.add(f(a + 1, b - 1)); |
| 73 | + } |
| 74 | + } |
| 75 | + if (nums[n - 1] < upper) { |
| 76 | + ans.add(f(nums[n - 1] + 1, upper)); |
| 77 | + } |
| 78 | + return ans; |
| 79 | + } |
| 80 | + |
| 81 | + private String f(int a, int b) { |
| 82 | + return a == b ? a + "" : a + "->" + b; |
| 83 | + } |
| 84 | +} |
| 85 | +``` |
| 86 | + |
| 87 | +### **C++** |
| 88 | + |
| 89 | +```cpp |
| 90 | +class Solution { |
| 91 | +public: |
| 92 | + vector<string> findMissingRanges(vector<int>& nums, int lower, int upper) { |
| 93 | + auto f = [](int a, int b) { |
| 94 | + return a == b ? to_string(a) : to_string(a) + "->" + to_string(b); |
| 95 | + }; |
| 96 | + int n = nums.size(); |
| 97 | + vector<string> ans; |
| 98 | + if (n == 0) { |
| 99 | + ans.emplace_back(f(lower, upper)); |
| 100 | + return ans; |
| 101 | + } |
| 102 | + if (nums[0] > lower) { |
| 103 | + ans.emplace_back(f(lower, nums[0] - 1)); |
| 104 | + } |
| 105 | + for (int i = 1; i < n; ++i) { |
| 106 | + int a = nums[i - 1], b = nums[i]; |
| 107 | + if (b - a > 1) { |
| 108 | + ans.emplace_back(f(a + 1, b - 1)); |
| 109 | + } |
| 110 | + } |
| 111 | + if (nums[n - 1] < upper) { |
| 112 | + ans.emplace_back(f(nums[n - 1] + 1, upper)); |
| 113 | + } |
| 114 | + return ans; |
| 115 | + } |
| 116 | +}; |
| 117 | +``` |
36 | 118 |
|
| 119 | +### **Go** |
| 120 | +
|
| 121 | +```go |
| 122 | +func findMissingRanges(nums []int, lower int, upper int) (ans []string) { |
| 123 | + f := func(a, b int) string { |
| 124 | + if a == b { |
| 125 | + return strconv.Itoa(a) |
| 126 | + } |
| 127 | + return strconv.Itoa(a) + "->" + strconv.Itoa(b) |
| 128 | + } |
| 129 | + n := len(nums) |
| 130 | + if n == 0 { |
| 131 | + ans = append(ans, f(lower, upper)) |
| 132 | + return |
| 133 | + } |
| 134 | + if nums[0] > lower { |
| 135 | + ans = append(ans, f(lower, nums[0]-1)) |
| 136 | + } |
| 137 | + for i := 1; i < n; i++ { |
| 138 | + a, b := nums[i-1], nums[i] |
| 139 | + if b-a > 1 { |
| 140 | + ans = append(ans, f(a+1, b-1)) |
| 141 | + } |
| 142 | + } |
| 143 | + if nums[n-1] < upper { |
| 144 | + ans = append(ans, f(nums[n-1]+1, upper)) |
| 145 | + } |
| 146 | + return |
| 147 | +} |
37 | 148 | ```
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38 | 149 |
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39 | 150 | ### **...**
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