feat: update lc problem (doocs#1522)

Author: yanglbme

solution/0900-0999/0928.Minimize Malware Spread II/README.md

@@ -24,8 +24,8 @@
 <p><strong>示例 1：</strong></p>
 
 <pre>
-<strong>输出：</strong>graph = [[1,1,0],[1,1,0],[0,0,1]], initial = [0,1]
-<strong>输入：</strong>0
+<strong>输入：</strong>graph = [[1,1,0],[1,1,0],[0,0,1]], initial = [0,1]
+<strong>输出：</strong>0
 </pre>
 
 <p><strong>示例 2：</strong></p>

solution/2700-2799/2715.Timeout Cancellation/README.md

@@ -6,53 +6,52 @@
 
 <!-- 这里写题目描述 -->
 
-<p>Given a function <code>fn</code>, an array of&nbsp;arguments&nbsp;<code>args</code>, and a timeout&nbsp;<code>t</code>&nbsp;in milliseconds, return a cancel function <code>cancelFn</code>.</p>
+<p>现给定一个函数 <code>fn</code>&nbsp;，一个参数数组 <code>args</code> 和一个以毫秒为单位的超时时间 <code>t</code> ，返回一个取消函数 <code>cancelFn</code> 。</p>
 
-<p>After a delay of&nbsp;<code>t</code>,&nbsp;<code>fn</code>&nbsp;should be called with <code>args</code> passed as parameters <strong>unless</strong> <code>cancelFn</code> was invoked before the delay of <code>t</code> milliseconds elapses, specifically at <code>cancelT</code>&nbsp;ms.&nbsp;In that case,&nbsp;<code>fn</code> should never be called.</p>
+<p>在经过 <code>t</code> 毫秒的延迟后，应该调用 <code>fn</code> 函数，并将 <code>args</code> 作为参数传递。<strong>除非</strong> 在 <code>t</code> 毫秒的延迟过程中，在 <code>cancelT</code> 毫秒时调用了 <code>cancelFn</code>。并且在这种情况下，<code>fn</code> 函数不应该被调用。</p>
 
-<p>&nbsp;</p>
-<p><strong class="example">Example 1:</strong></p>
+<p><strong class="example">示例 1:</strong></p>
 
 <pre>
-<strong>Input:</strong> fn = (x) =&gt; x * 5, args = [2], t = 20, cancelT = 50
-<strong>Output:</strong> [{&quot;time&quot;: 20, &quot;returned&quot;: 10}]
-<strong>Explanation:</strong> 
-const cancel = cancellable((x) =&gt; x * 5, [2], 20); // fn(2) called at t=20ms
+<b>输入：</b>fn = (x) =&gt; x * 5, args = [2], t = 20, cancelT = 50
+<b>输出：</b>[{"time": 20, "returned": 10}]
+<b>解释：</b>
+const cancel = cancellable((x) =&gt; x * 5, [2], 20); // fn(2) 在 t=20ms 时被调用
 setTimeout(cancel, 50);
 
-The cancellation was scheduled to occur after a delay of cancelT (50ms), which happened after the execution of fn(2) at 20ms.
-</pre>
+取消操作被安排在延迟了 cancelT（50毫秒）后进行，这发生在 fn(2) 在20毫秒时执行之后。</pre>
 
-<p><strong class="example">Example 2:</strong></p>
+<p><strong class="example">示例 2：</strong></p>
 
 <pre>
-<strong>Input:</strong> fn = (x) =&gt; x**2, args = [2], t = 100, cancelT = 50 
-<strong>Output:</strong> []
-<strong>Explanation:</strong> 
-const cancel = cancellable((x) =&gt; x**2, [2], 100); // fn(2) not called
+<b>输入：</b>fn = (x) =&gt; x**2, args = [2], t = 100, cancelT = 50
+<b>输出：</b>[]
+<b>解释：</b>
+const cancel = cancellable((x) =&gt; x**2, [2], 100); // fn(2) 没被调用
 setTimeout(cancel, 50);
 
-The cancellation was scheduled to occur after a delay of cancelT (50ms), which happened before the execution of fn(2) at 100ms, resulting in fn(2) never being called.
+取消操作被安排在延迟了 cancelT（50毫秒）后进行，这发生在 fn(2) 在100毫秒时执行之前，导致 fn(2) 从未被调用。
 </pre>
 
-<p><strong class="example">Example 3:</strong></p>
+<p><strong class="example">示例 3：</strong></p>
 
 <pre>
-<strong>Input:</strong> fn = (x1, x2) =&gt; x1 * x2, args = [2,4], t = 30, cancelT = 100
-<strong>Output:</strong> [{&quot;time&quot;: 30, &quot;returned&quot;: 8}]
-<strong>Explanation:</strong>
-const cancel = cancellable((x1, x2) =&gt; x1 * x2, [2,4], 30); // fn(2,4) called at t=30ms
+<b>输入：</b>fn = (x1, x2) =&gt; x1 * x2, args = [2,4], t = 30, cancelTime = 100
+<b>输出：</b>[{"time": 30, "returned": 8}]
+<b>解释：</b>
+const cancel = cancellable((x1, x2) =&gt; x1 * x2, [2,4], 30); // fn(2,4) 在 t=30ms 时被调用
 setTimeout(cancel, 100);
 
-The cancellation was scheduled to occur after a delay of cancelT (100ms), which happened after the execution of fn(2,4) at 30ms.
+取消操作被安排在延迟了 cancelT（100毫秒）后进行，这发生在 fn(2,4) 在30毫秒时执行之后。
 </pre>
 
 <p>&nbsp;</p>
-<p><strong>Constraints:</strong></p>
+
+<p><strong>提示：</strong></p>
 
 <ul>
-	<li><code>fn is a function</code></li>
-	<li><code>args is a valid JSON array</code></li>
+	<li><code>fn 是一个函数</code></li>
+	<li><code>args 是一个有效的 JSON 数组</code></li>
 	<li><code>1 &lt;= args.length &lt;= 10</code></li>
 	<li><code><font face="monospace">20 &lt;= t &lt;= 1000</font></code></li>
 	<li><code><font face="monospace">10 &lt;= cancelT &lt;= 1000</font></code></li>