feat: add solutions to lc problems: No.1398,1407

* No.1398.Customers Who Bought Products A and B but Not C
* No.1407.Top Travellers

Author: yanglbme

solution/1300-1399/1398.Customers Who Bought Products A and B but Not C/README.md

@@ -86,7 +86,19 @@ Result table:
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+select
+    o.customer_id,
+    c.customer_name
+from
+    orders o
+    left join customers c on o.customer_id = c.customer_id
+group by
+    customer_id
+having
+    sum(if(product_name = 'A', 1, 0)) > 0
+    and sum(if(product_name = 'B', 1, 0)) > 0
+    and sum(if(product_name = 'C', 1, 0)) = 0
 ```
 
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solution/1300-1399/1398.Customers Who Bought Products A and B but Not C/README_EN.md

@@ -84,7 +84,19 @@ Orders table:
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+select
+    o.customer_id,
+    c.customer_name
+from
+    orders o
+    left join customers c on o.customer_id = c.customer_id
+group by
+    customer_id
+having
+    sum(if(product_name = 'A', 1, 0)) > 0
+    and sum(if(product_name = 'B', 1, 0)) > 0
+    and sum(if(product_name = 'C', 1, 0)) = 0
 ```
 
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solution/1300-1399/1398.Customers Who Bought Products A and B but Not C/Solution.sql

@@ -0,0 +1,13 @@
+# Write your MySQL query statement below
+select
+    o.customer_id,
+    c.customer_name
+from
+    orders o
+    left join customers c on o.customer_id = c.customer_id
+group by
+    customer_id
+having
+    sum(if(product_name = 'A', 1, 0)) > 0
+    and sum(if(product_name = 'B', 1, 0)) > 0
+    and sum(if(product_name = 'C', 1, 0)) = 0

solution/1400-1499/1407.Top Travellers/README.md

@@ -108,4 +108,19 @@ ORDER BY
     name;
 ```
 
+```sql
+# Write your MySQL query statement below
+select
+    name,
+    sum(ifnull(distance, 0)) travelled_distance
+from
+    Users u
+    left join Rides r on u.id = r.user_id
+group by
+(u.id)
+order by
+    travelled_distance desc,
+    name asc;
+```
+
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solution/1400-1499/1407.Top Travellers/README_EN.md

@@ -108,4 +108,19 @@ ORDER BY
     name;
 ```
 
+```sql
+# Write your MySQL query statement below
+select
+    name,
+    sum(ifnull(distance, 0)) travelled_distance
+from
+    Users u
+    left join Rides r on u.id = r.user_id
+group by
+(u.id)
+order by
+    travelled_distance desc,
+    name asc;
+```
+
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