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50 | 50 |
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51 | 51 | <!-- 这里可写通用的实现逻辑 -->
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52 | 52 |
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| 53 | +**方法一:分类讨论** |
| 54 | + |
| 55 | +我们记要删除的区间为 $[x, y)$,遍历区间列表,对于每个区间 $[a, b)$,有以下三种情况: |
| 56 | + |
| 57 | +- $a \geq y$ 或 $b \leq x$,表示该区间与要删除的区间没有交集,直接将该区间加入答案; |
| 58 | +- $a \lt x$,$b \gt y$,表示该区间与要删除的区间有交集,将该区间分成两个区间加入答案; |
| 59 | +- $a \geq x$,$b \leq y$,表示该区间被要删除的区间完全覆盖,不加入答案。 |
| 60 | + |
| 61 | +时间复杂度 $O(n)$,空间复杂度 $O(1)$。其中 $n$ 为区间列表的长度。 |
| 62 | + |
53 | 63 | <!-- tabs:start -->
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54 | 64 |
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55 | 65 | ### **Python3**
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56 | 66 |
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57 | 67 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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58 | 68 |
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59 | 69 | ```python
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60 |
| - |
| 70 | +class Solution: |
| 71 | + def removeInterval(self, intervals: List[List[int]], toBeRemoved: List[int]) -> List[List[int]]: |
| 72 | + x, y = toBeRemoved |
| 73 | + ans = [] |
| 74 | + for a, b in intervals: |
| 75 | + if a >= y or b <= x: |
| 76 | + ans.append([a, b]) |
| 77 | + else: |
| 78 | + if a < x: |
| 79 | + ans.append([a, x]) |
| 80 | + if b > y: |
| 81 | + ans.append([y, b]) |
| 82 | + return ans |
61 | 83 | ```
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62 | 84 |
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63 | 85 | ### **Java**
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64 | 86 |
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65 | 87 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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66 | 88 |
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67 | 89 | ```java
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| 90 | +class Solution { |
| 91 | + public List<List<Integer>> removeInterval(int[][] intervals, int[] toBeRemoved) { |
| 92 | + int x = toBeRemoved[0], y = toBeRemoved[1]; |
| 93 | + List<List<Integer>> ans = new ArrayList<>(); |
| 94 | + for (var e : intervals) { |
| 95 | + int a = e[0], b = e[1]; |
| 96 | + if (a >= y || b <= x) { |
| 97 | + ans.add(Arrays.asList(a, b)); |
| 98 | + } else { |
| 99 | + if (a < x) { |
| 100 | + ans.add(Arrays.asList(a, x)); |
| 101 | + } |
| 102 | + if (b > y) { |
| 103 | + ans.add(Arrays.asList(y, b)); |
| 104 | + } |
| 105 | + } |
| 106 | + } |
| 107 | + return ans; |
| 108 | + } |
| 109 | +} |
| 110 | +``` |
| 111 | + |
| 112 | +### **C++** |
| 113 | + |
| 114 | +```cpp |
| 115 | +class Solution { |
| 116 | +public: |
| 117 | + vector<vector<int>> removeInterval(vector<vector<int>>& intervals, vector<int>& toBeRemoved) { |
| 118 | + int x = toBeRemoved[0], y = toBeRemoved[1]; |
| 119 | + vector<vector<int>> ans; |
| 120 | + for (auto& e : intervals) { |
| 121 | + int a = e[0], b = e[1]; |
| 122 | + if (a >= y || b <= x) { |
| 123 | + ans.push_back(e); |
| 124 | + } else { |
| 125 | + if (a < x) { |
| 126 | + ans.push_back({a, x}); |
| 127 | + } |
| 128 | + if (b > y) { |
| 129 | + ans.push_back({y, b}); |
| 130 | + } |
| 131 | + } |
| 132 | + } |
| 133 | + return ans; |
| 134 | + } |
| 135 | +}; |
| 136 | +``` |
68 | 137 |
|
| 138 | +### **Go** |
| 139 | +
|
| 140 | +```go |
| 141 | +func removeInterval(intervals [][]int, toBeRemoved []int) (ans [][]int) { |
| 142 | + x, y := toBeRemoved[0], toBeRemoved[1] |
| 143 | + for _, e := range intervals { |
| 144 | + a, b := e[0], e[1] |
| 145 | + if a >= y || b <= x { |
| 146 | + ans = append(ans, e) |
| 147 | + } else { |
| 148 | + if a < x { |
| 149 | + ans = append(ans, []int{a, x}) |
| 150 | + } |
| 151 | + if b > y { |
| 152 | + ans = append(ans, []int{y, b}) |
| 153 | + } |
| 154 | + } |
| 155 | + } |
| 156 | + return |
| 157 | +} |
69 | 158 | ```
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70 | 159 |
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71 | 160 | ### **...**
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