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41 | 41 |
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42 | 42 | <!-- 这里可写通用的实现逻辑 -->
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43 | 43 |
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| 44 | +快速排序 partition 实现。 |
| 45 | + |
44 | 46 | <!-- tabs:start -->
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45 | 47 |
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46 | 48 | ### **Python3**
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47 | 49 |
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48 | 50 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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49 | 51 |
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50 | 52 | ```python
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51 |
| - |
| 53 | +class Solution: |
| 54 | + def findKthLargest(self, nums: List[int], k: int) -> int: |
| 55 | + def quick_sort(left, right, k): |
| 56 | + if left == right: |
| 57 | + return nums[left] |
| 58 | + i, j = left - 1, right + 1 |
| 59 | + x = nums[(left + right) >> 1] |
| 60 | + while i < j: |
| 61 | + while 1: |
| 62 | + i += 1 |
| 63 | + if nums[i] >= x: |
| 64 | + break |
| 65 | + while 1: |
| 66 | + j -= 1 |
| 67 | + if nums[j] <= x: |
| 68 | + break |
| 69 | + if i < j: |
| 70 | + nums[i], nums[j] = nums[j], nums[i] |
| 71 | + if j < k: |
| 72 | + return quick_sort(j + 1, right, k) |
| 73 | + return quick_sort(left, j, k) |
| 74 | + |
| 75 | + n = len(nums) |
| 76 | + return quick_sort(0, n - 1, n - k) |
52 | 77 | ```
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53 | 78 |
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54 | 79 | ### **Java**
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55 | 80 |
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56 | 81 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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57 | 82 |
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58 | 83 | ```java
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| 84 | +class Solution { |
| 85 | + public int findKthLargest(int[] nums, int k) { |
| 86 | + int n = nums.length; |
| 87 | + return quickSort(nums, 0, n - 1, n - k); |
| 88 | + } |
| 89 | + |
| 90 | + private int quickSort(int[] nums, int left, int right, int k) { |
| 91 | + if (left == right) { |
| 92 | + return nums[left]; |
| 93 | + } |
| 94 | + int i = left - 1, j = right + 1; |
| 95 | + int x = nums[(left + right) >>> 1]; |
| 96 | + while (i < j) { |
| 97 | + while (nums[++i] < x); |
| 98 | + while (nums[--j] > x); |
| 99 | + if (i < j) { |
| 100 | + int t = nums[i]; |
| 101 | + nums[i] = nums[j]; |
| 102 | + nums[j] = t; |
| 103 | + } |
| 104 | + } |
| 105 | + if (j < k) { |
| 106 | + return quickSort(nums, j + 1, right, k); |
| 107 | + } |
| 108 | + return quickSort(nums, left, j, k); |
| 109 | + |
| 110 | + } |
| 111 | +} |
| 112 | +``` |
| 113 | + |
| 114 | +### **C++** |
| 115 | + |
| 116 | +```cpp |
| 117 | +class Solution { |
| 118 | +public: |
| 119 | + int findKthLargest(vector<int>& nums, int k) { |
| 120 | + int n = nums.size(); |
| 121 | + return quickSort(nums, 0, n - 1, n - k); |
| 122 | + } |
| 123 | + |
| 124 | + int quickSort(vector<int>& nums, int left, int right, int k) { |
| 125 | + if (left == right) return nums[left]; |
| 126 | + int i = left - 1, j = right + 1; |
| 127 | + int x = nums[left + right >> 1]; |
| 128 | + while (i < j) |
| 129 | + { |
| 130 | + while (nums[++i] < x); |
| 131 | + while (nums[--j] > x); |
| 132 | + if (i < j) swap(nums[i], nums[j]); |
| 133 | + } |
| 134 | + return j < k ? quickSort(nums, j + 1, right, k) : quickSort(nums, left, j, k); |
| 135 | + } |
| 136 | +}; |
| 137 | +``` |
59 | 138 |
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| 139 | +### **Go** |
| 140 | + |
| 141 | +```go |
| 142 | +func findKthLargest(nums []int, k int) int { |
| 143 | + n := len(nums) |
| 144 | + return quickSort(nums, 0, n-1, n-k) |
| 145 | +} |
| 146 | + |
| 147 | +func quickSort(nums []int, left, right, k int) int { |
| 148 | + if left == right { |
| 149 | + return nums[left] |
| 150 | + } |
| 151 | + i, j := left-1, right+1 |
| 152 | + x := nums[(left+right)>>1] |
| 153 | + for i < j { |
| 154 | + for { |
| 155 | + i++ |
| 156 | + if nums[i] >= x { |
| 157 | + break |
| 158 | + } |
| 159 | + } |
| 160 | + for { |
| 161 | + j-- |
| 162 | + if nums[j] <= x { |
| 163 | + break |
| 164 | + } |
| 165 | + } |
| 166 | + if i < j { |
| 167 | + nums[i], nums[j] = nums[j], nums[i] |
| 168 | + } |
| 169 | + } |
| 170 | + if j < k { |
| 171 | + return quickSort(nums, j+1, right, k) |
| 172 | + } |
| 173 | + return quickSort(nums, left, j, k) |
| 174 | +} |
60 | 175 | ```
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61 | 176 |
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62 | 177 | ### **...**
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