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51 | 51 |
|
52 | 52 | <!-- 这里可写通用的实现逻辑 -->
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53 | 53 |
|
| 54 | +**方法一:栈** |
| 55 | + |
| 56 | +我们用一个栈 $stk$ 来保存当前的计算结果和操作符,用一个变量 $sign$ 保存当前的符号,变量 $ans$ 保存最终的计算结果。 |
| 57 | + |
| 58 | +接下来,我们遍历字符串 $s$ 的每一个字符: |
| 59 | + |
| 60 | +- 如果当前字符是数字,那么我们用一个循环将后面的连续数字都读进来,然后用当前的符号将其加或者减到 $ans$ 中。 |
| 61 | +- 如果当前字符是 `'+'`,我们修改变量 $sign$ 为正号。 |
| 62 | +- 如果当前字符是 `'-'`,我们修改变量 $sign$ 为负号。 |
| 63 | +- 如果当前字符是 `'('`,我们把当前的 $ans$ 和 $sign$ 入栈,并分别置空置 1,重新开始计算新的 $ans$ 和 $sign$。 |
| 64 | +- 如果当前字符是 `')'`,我们弹出栈顶的两个元素,一个是操作符,一个是括号前计算好的数字,我们将当前的数字乘上操作符,再加上之前的数字,作为新的 $ans$。 |
| 65 | + |
| 66 | +遍历完字符串 $s$ 之后,我们返回 $ans$。 |
| 67 | + |
| 68 | +时间复杂度 $O(n)$,空间复杂度 $O(n)$。其中 $n$ 是字符串 $s$ 的长度。 |
| 69 | + |
54 | 70 | <!-- tabs:start -->
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55 | 71 |
|
56 | 72 | ### **Python3**
|
57 | 73 |
|
58 | 74 | <!-- 这里可写当前语言的特殊实现逻辑 -->
|
59 | 75 |
|
60 | 76 | ```python
|
61 |
| - |
| 77 | +class Solution: |
| 78 | + def calculate(self, s: str) -> int: |
| 79 | + stk = [] |
| 80 | + ans, sign = 0, 1 |
| 81 | + i, n = 0, len(s) |
| 82 | + while i < n: |
| 83 | + if s[i].isdigit(): |
| 84 | + x = 0 |
| 85 | + j = i |
| 86 | + while j < n and s[j].isdigit(): |
| 87 | + x = x * 10 + int(s[j]) |
| 88 | + j += 1 |
| 89 | + ans += sign * x |
| 90 | + i = j - 1 |
| 91 | + elif s[i] == "+": |
| 92 | + sign = 1 |
| 93 | + elif s[i] == "-": |
| 94 | + sign = -1 |
| 95 | + elif s[i] == "(": |
| 96 | + stk.append(ans) |
| 97 | + stk.append(sign) |
| 98 | + ans, sign = 0, 1 |
| 99 | + elif s[i] == ")": |
| 100 | + ans = stk.pop() * ans + stk.pop() |
| 101 | + i += 1 |
| 102 | + return ans |
62 | 103 | ```
|
63 | 104 |
|
64 | 105 | ### **Java**
|
65 | 106 |
|
66 | 107 | <!-- 这里可写当前语言的特殊实现逻辑 -->
|
67 | 108 |
|
68 | 109 | ```java
|
| 110 | +class Solution { |
| 111 | + public int calculate(String s) { |
| 112 | + Deque<Integer> stk = new ArrayDeque<>(); |
| 113 | + int sign = 1; |
| 114 | + int ans = 0; |
| 115 | + int n = s.length(); |
| 116 | + for (int i = 0; i < n; ++i) { |
| 117 | + char c = s.charAt(i); |
| 118 | + if (Character.isDigit(c)) { |
| 119 | + int j = i; |
| 120 | + int x = 0; |
| 121 | + while (j < n && Character.isDigit(s.charAt(j))) { |
| 122 | + x = x * 10 + s.charAt(j) - '0'; |
| 123 | + j++; |
| 124 | + } |
| 125 | + ans += sign * x; |
| 126 | + i = j - 1; |
| 127 | + } else if (c == '+') { |
| 128 | + sign = 1; |
| 129 | + } else if (c == '-') { |
| 130 | + sign = -1; |
| 131 | + } else if (c == '(') { |
| 132 | + stk.push(ans); |
| 133 | + stk.push(sign); |
| 134 | + ans = 0; |
| 135 | + sign = 1; |
| 136 | + } else if (c == ')') { |
| 137 | + ans = stk.pop() * ans + stk.pop(); |
| 138 | + } |
| 139 | + } |
| 140 | + return ans; |
| 141 | + } |
| 142 | +} |
| 143 | +``` |
| 144 | + |
| 145 | +### **C++** |
| 146 | + |
| 147 | +```cpp |
| 148 | +class Solution { |
| 149 | +public: |
| 150 | + int calculate(string s) { |
| 151 | + stack<int> stk; |
| 152 | + int ans = 0, sign = 1; |
| 153 | + int n = s.size(); |
| 154 | + for (int i = 0; i < n; ++i) { |
| 155 | + if (isdigit(s[i])) { |
| 156 | + int x = 0; |
| 157 | + int j = i; |
| 158 | + while (j < n && isdigit(s[j])) { |
| 159 | + x = x * 10 + (s[j] - '0'); |
| 160 | + ++j; |
| 161 | + } |
| 162 | + ans += sign * x; |
| 163 | + i = j - 1; |
| 164 | + } else if (s[i] == '+') { |
| 165 | + sign = 1; |
| 166 | + } else if (s[i] == '-') { |
| 167 | + sign = -1; |
| 168 | + } else if (s[i] == '(') { |
| 169 | + stk.push(ans); |
| 170 | + stk.push(sign); |
| 171 | + ans = 0; |
| 172 | + sign = 1; |
| 173 | + } else if (s[i] == ')') { |
| 174 | + ans *= stk.top(); |
| 175 | + stk.pop(); |
| 176 | + ans += stk.top(); |
| 177 | + stk.pop(); |
| 178 | + } |
| 179 | + } |
| 180 | + return ans; |
| 181 | + } |
| 182 | +}; |
| 183 | +``` |
| 184 | +
|
| 185 | +### **Go** |
| 186 | +
|
| 187 | +```go |
| 188 | +func calculate(s string) (ans int) { |
| 189 | + stk := []int{} |
| 190 | + sign := 1 |
| 191 | + n := len(s) |
| 192 | + for i := 0; i < n; i++ { |
| 193 | + switch s[i] { |
| 194 | + case ' ': |
| 195 | + case '+': |
| 196 | + sign = 1 |
| 197 | + case '-': |
| 198 | + sign = -1 |
| 199 | + case '(': |
| 200 | + stk = append(stk, ans) |
| 201 | + stk = append(stk, sign) |
| 202 | + ans, sign = 0, 1 |
| 203 | + case ')': |
| 204 | + ans *= stk[len(stk)-1] |
| 205 | + stk = stk[:len(stk)-1] |
| 206 | + ans += stk[len(stk)-1] |
| 207 | + stk = stk[:len(stk)-1] |
| 208 | + default: |
| 209 | + x := 0 |
| 210 | + j := i |
| 211 | + for ; j < n && '0' <= s[j] && s[j] <= '9'; j++ { |
| 212 | + x = x*10 + int(s[j]-'0') |
| 213 | + } |
| 214 | + ans += sign * x |
| 215 | + i = j - 1 |
| 216 | + } |
| 217 | + } |
| 218 | + return |
| 219 | +} |
| 220 | +``` |
| 221 | + |
| 222 | +### **TypeScript** |
| 223 | + |
| 224 | +```ts |
| 225 | +function calculate(s: string): number { |
| 226 | + const stk: number[] = []; |
| 227 | + let sign = 1; |
| 228 | + let ans = 0; |
| 229 | + const n = s.length; |
| 230 | + for (let i = 0; i < n; ++i) { |
| 231 | + if (s[i] === ' ') { |
| 232 | + continue; |
| 233 | + } |
| 234 | + if (s[i] === '+') { |
| 235 | + sign = 1; |
| 236 | + } else if (s[i] === '-') { |
| 237 | + sign = -1; |
| 238 | + } else if (s[i] === '(') { |
| 239 | + stk.push(ans); |
| 240 | + stk.push(sign); |
| 241 | + ans = 0; |
| 242 | + sign = 1; |
| 243 | + } else if (s[i] === ')') { |
| 244 | + ans *= stk.pop() as number; |
| 245 | + ans += stk.pop() as number; |
| 246 | + } else { |
| 247 | + let x = 0; |
| 248 | + let j = i; |
| 249 | + for (; j < n && !isNaN(Number(s[j])) && s[j] !== ' '; ++j) { |
| 250 | + x = x * 10 + (s[j].charCodeAt(0) - '0'.charCodeAt(0)); |
| 251 | + } |
| 252 | + ans += sign * x; |
| 253 | + i = j - 1; |
| 254 | + } |
| 255 | + } |
| 256 | + return ans; |
| 257 | +} |
| 258 | +``` |
| 259 | + |
| 260 | +### **C#** |
69 | 261 |
|
| 262 | +```cs |
| 263 | +public class Solution { |
| 264 | + public int Calculate(string s) { |
| 265 | + var stk = new Stack<int>(); |
| 266 | + int sign = 1; |
| 267 | + int n = s.Length; |
| 268 | + int ans = 0; |
| 269 | + for (int i = 0; i < n; ++i) { |
| 270 | + if (s[i] == ' ') { |
| 271 | + continue; |
| 272 | + } |
| 273 | + if (s[i] == '+') { |
| 274 | + sign = 1; |
| 275 | + } else if (s[i] == '-') { |
| 276 | + sign = -1; |
| 277 | + } else if (s[i] == '(') { |
| 278 | + stk.Push(ans); |
| 279 | + stk.Push(sign); |
| 280 | + ans = 0; |
| 281 | + sign = 1; |
| 282 | + } else if (s[i] == ')') { |
| 283 | + ans *= stk.Pop(); |
| 284 | + ans += stk.Pop(); |
| 285 | + } else { |
| 286 | + int num = 0; |
| 287 | + while (i < n && char.IsDigit(s[i])) { |
| 288 | + num = num * 10 + s[i] - '0'; |
| 289 | + ++i; |
| 290 | + } |
| 291 | + --i; |
| 292 | + ans += sign * num; |
| 293 | + } |
| 294 | + } |
| 295 | + return ans; |
| 296 | + } |
| 297 | +} |
70 | 298 | ```
|
71 | 299 |
|
72 | 300 | ### **...**
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