chore: update lc problems: No.0279~No.0283 (doocs#1141)

Author: thinkasany

solution/0200-0299/0279.Perfect Squares/README.md

@@ -15,16 +15,16 @@
 <p><strong>示例&nbsp;1：</strong></p>
 
 <pre>
-<strong>输入：</strong>n = <code>12</code>
+<strong>输入：</strong>n = 12
 <strong>输出：</strong>3 
-<strong>解释：</strong><code>12 = 4 + 4 + 4</code></pre>
+<strong>解释：</strong>12 = 4 + 4 + 4</pre>
 
 <p><strong>示例 2：</strong></p>
 
 <pre>
-<strong>输入：</strong>n = <code>13</code>
+<strong>输入：</strong>n = 13
 <strong>输出：</strong>2
-<strong>解释：</strong><code>13 = 4 + 9</code></pre>
+<strong>解释：</strong>13 = 4 + 9</pre>
 
 &nbsp;
 

solution/0200-0299/0280.Wiggle Sort/README.md

@@ -15,7 +15,7 @@
 <p><strong>示例 1:</strong></p>
 
 <pre>
-<strong>输入：</strong><code>nums = [3,5,2,1,6,4]</code>
+<strong>输入：</strong>nums = [3,5,2,1,6,4]
 <strong>输出：</strong>[3,5,1,6,2,4]
 <strong>解释：</strong>[1,6,2,5,3,4]也是有效的答案</pre>
 

solution/0200-0299/0281.Zigzag Iterator/README.md

@@ -14,10 +14,10 @@
 v1 = [1,2]
 v2 = [3,4,5,6] 
 
-<strong>输出:</strong> <code>[1,3,2,4,5,6]
+<strong>输出:</strong> [1,3,2,4,5,6]
 
-<strong>解析:</strong></code>&nbsp;通过连续调用 <em>next</em> 函数直到 <em>hasNext</em> 函数返回 <code>false，</code>
-&nbsp;    <em>next</em> 函数返回值的次序应依次为: <code>[1,3,2,4,5,6]。</code></pre>
+<strong>解析:</strong>&nbsp;通过连续调用 <em>next</em> 函数直到 <em>hasNext</em> 函数返回 false，
+&nbsp;    <em>next</em> 函数返回值的次序应依次为: [1,3,2,4,5,6]。</pre>
 
 <p><strong>拓展：</strong>假如给你&nbsp;<code>k</code>&nbsp;个一维向量呢？你的代码在这种情况下的扩展性又会如何呢?</p>
 
@@ -29,7 +29,7 @@ v2 = [3,4,5,6]
 [4,5,6,7]
 [8,9]
 
-<strong>输出: </strong><code>[1,4,8,2,5,9,3,6,7]</code>.
+<strong>输出: </strong>[1,4,8,2,5,9,3,6,7].
 </pre>
 
 ## 解法

solution/0200-0299/0282.Expression Add Operators/README.md

@@ -15,23 +15,23 @@
 <p><strong>示例 1:</strong></p>
 
 <pre>
-<strong>输入:</strong> <code>num = </code>"123", target = 6
+<strong>输入:</strong> num = "123", target = 6
 <strong>输出: </strong>["1+2+3", "1*2*3"] 
 <strong>解释: </strong>“1*2*3” 和 “1+2+3” 的值都是6。
 </pre>
 
 <p><strong>示例&nbsp;2:</strong></p>
 
 <pre>
-<strong>输入:</strong> <code>num = </code>"232", target = 8
+<strong>输入:</strong> num = "232", target = 8
 <strong>输出: </strong>["2*3+2", "2+3*2"]
 <strong>解释:</strong> “2*3+2” 和 “2+3*2” 的值都是8。
 </pre>
 
 <p><strong>示例 3:</strong></p>
 
 <pre>
-<strong>输入:</strong> <code>num = </code>"3456237490", target = 9191
+<strong>输入:</strong> num = "3456237490", target = 9191
 <strong>输出: </strong>[]
 <strong>解释: </strong>表达式 “3456237490” 无法得到 9191 。
 </pre>

solution/0200-0299/0283.Move Zeroes/README.md

@@ -15,15 +15,15 @@
 <p><strong>示例 1:</strong></p>
 
 <pre>
-<strong>输入:</strong> nums = <code>[0,1,0,3,12]</code>
-<strong>输出:</strong> <code>[1,3,12,0,0]</code>
+<strong>输入:</strong> nums = [0,1,0,3,12]
+<strong>输出:</strong> [1,3,12,0,0]
 </pre>
 
 <p><strong>示例 2:</strong></p>
 
 <pre>
-<strong>输入:</strong> nums = <code>[0]</code>
-<strong>输出:</strong> <code>[0]</code></pre>
+<strong>输入:</strong> nums = [0]
+<strong>输出:</strong> [0]</pre>
 
 <p>&nbsp;</p>
 

solution/config.py

@@ -4,6 +4,11 @@
     30,
     33,
     34,
+    279,
+    280,
+    281,
+    282,
+    283,
     375,
     465,
     638,