feat: update lc problems (doocs#2243)

Author: yanglbme

solution/0000-0099/0080.Remove Duplicates from Sorted Array II/README.md

@@ -46,7 +46,7 @@ for (int i = 0; i < len; i++) {
 <pre>
 <strong>输入：</strong>nums = [0,0,1,1,1,1,2,3,3]
 <strong>输出：</strong>7, nums = [0,0,1,1,2,3,3]
-<strong>解释：</strong>函数应返回新长度 length = <strong><code>7</code></strong>, 并且原数组的前五个元素被修改为&nbsp;<strong><code>0, 0, 1, 1, 2, 3, 3</code></strong>。不需要考虑数组中超出新长度后面的元素。
+<strong>解释：</strong>函数应返回新长度 length = <strong><code>7</code></strong>, 并且原数组的前七个元素被修改为&nbsp;<strong><code>0, 0, 1, 1, 2, 3, 3</code></strong>。不需要考虑数组中超出新长度后面的元素。
 </pre>
 
 <p>&nbsp;</p>

solution/0100-0199/0139.Word Break/README.md

@@ -6,7 +6,7 @@
 
 <!-- 这里写题目描述 -->
 
-<p>给你一个字符串 <code>s</code> 和一个字符串列表 <code>wordDict</code> 作为字典。请你判断是否可以利用字典中出现的单词拼接出 <code>s</code> 。</p>
+<p>给你一个字符串 <code>s</code> 和一个字符串列表 <code>wordDict</code> 作为字典。如果可以利用字典中出现的一个或多个单词拼接出 <code>s</code>&nbsp;则返回 <code>true</code>。</p>
 
 <p><strong>注意：</strong>不要求字典中出现的单词全部都使用，并且字典中的单词可以重复使用。</p>
 

solution/0100-0199/0153.Find Minimum in Rotated Sorted Array/README.md

@@ -34,7 +34,7 @@
 <pre>
 <strong>输入：</strong>nums = [4,5,6,7,0,1,2]
 <strong>输出：</strong>0
-<strong>解释：</strong>原数组为 [0,1,2,4,5,6,7] ，旋转 4 次得到输入数组。
+<strong>解释：</strong>原数组为 [0,1,2,4,5,6,7] ，旋转 3 次得到输入数组。
 </pre>
 
 <p><strong>示例 3：</strong></p>

solution/0300-0399/0320.Generalized Abbreviation/README.md

@@ -10,6 +10,7 @@
 
 <ul>
 	<li>例如，<code>"abcde"</code> 可以缩写为：
+
     <ul>
     	<li><code>"a3e"</code>（<code>"bcd"</code> 变为 <code>"3"</code> ）</li>
     	<li><code>"1bcd1"</code>（<code>"a"</code> 和 <code>"e"</code> 都变为 <code>"1"</code>）<meta charset="UTF-8" /></li>
@@ -23,6 +24,7 @@
     	<li><meta charset="UTF-8" /><code>"22de"</code>&nbsp;(<code>"ab"</code> 变为&nbsp;<code>"2"</code>&nbsp;，&nbsp;<code>"bc"</code>&nbsp;变为&nbsp;<code>"2"</code>) &nbsp;是无效的，因为被选择的字符串是重叠的</li>
     </ul>
     </li>
+
 </ul>
 
 <p>给你一个字符串&nbsp;<code>word</code> ，返回&nbsp;<em>一个由</em>&nbsp;<code>word</code> 的<em>所有可能 <strong>广义缩写词</strong> 组成的列表</em>&nbsp;。按 <strong>任意顺序</strong> 返回答案。</p>

solution/0300-0399/0320.Generalized Abbreviation/README_EN.md

@@ -8,6 +8,7 @@
 
 <ul>
 	<li>For example, <code>&quot;abcde&quot;</code> can be abbreviated into:
+
     <ul>
     	<li><code>&quot;a3e&quot;</code> (<code>&quot;bcd&quot;</code> turned into <code>&quot;3&quot;</code>)</li>
     	<li><code>&quot;1bcd1&quot;</code> (<code>&quot;a&quot;</code> and <code>&quot;e&quot;</code> both turned into <code>&quot;1&quot;</code>)</li>
@@ -21,6 +22,7 @@
     	<li><code>&quot;22de&quot;</code> (<code>&quot;ab&quot;</code> turned into <code>&quot;2&quot;</code> and <code>&quot;bc&quot;</code> turned into <code>&quot;2&quot;</code>) is invalid as the substring chosen overlap.</li>
     </ul>
     </li>
+
 </ul>
 
 <p>Given a string <code>word</code>, return <em>a list of all the possible <strong>generalized abbreviations</strong> of</em> <code>word</code>. Return the answer in <strong>any order</strong>.</p>

solution/0300-0399/0375.Guess Number Higher or Lower II/README.md

@@ -27,21 +27,21 @@
 <strong>输出：</strong>16
 <strong>解释：</strong>制胜策略如下：
 - 数字范围是 [1,10] 。你先猜测数字为 7 。
-&nbsp;   - 如果这是我选中的数字，你的总费用为 0 。否则，你需要支付 7 。
+&nbsp;   - 如果这是我选中的数字，你的总费用为 $0 。否则，你需要支付 $7 。
 &nbsp;   - 如果我的数字更大，则下一步需要猜测的数字范围是 [8,10] 。你可以猜测数字为 9 。
-&nbsp;       - 如果这是我选中的数字，你的总费用为 7 。否则，你需要支付 9 。
-&nbsp;       - 如果我的数字更大，那么这个数字一定是 10 。你猜测数字为 10 并赢得游戏，总费用为 7 + 9 = 16 。
-&nbsp;       - 如果我的数字更小，那么这个数字一定是 8 。你猜测数字为 8 并赢得游戏，总费用为 7 + 9 = 16 。
+&nbsp;       - 如果这是我选中的数字，你的总费用为 $7 。否则，你需要支付 $9 。
+&nbsp;       - 如果我的数字更大，那么这个数字一定是 10 。你猜测数字为 10 并赢得游戏，总费用为 $7 + $9 = $16 。
+&nbsp;       - 如果我的数字更小，那么这个数字一定是 8 。你猜测数字为 8 并赢得游戏，总费用为 $7 + $9 = $16 。
 &nbsp;   - 如果我的数字更小，则下一步需要猜测的数字范围是 [1,6] 。你可以猜测数字为 3 。
-&nbsp;       - 如果这是我选中的数字，你的总费用为 7 。否则，你需要支付 3 。
+&nbsp;       - 如果这是我选中的数字，你的总费用为 $7 。否则，你需要支付 $3 。
 &nbsp;       - 如果我的数字更大，则下一步需要猜测的数字范围是 [4,6] 。你可以猜测数字为 5 。
-&nbsp;           - 如果这是我选中的数字，你的总费用为 7 + 3 = 10 。否则，你需要支付 5 。
-&nbsp;           - 如果我的数字更大，那么这个数字一定是 6 。你猜测数字为 6 并赢得游戏，总费用为 7 + 3 + 5 = 15 。
-&nbsp;           - 如果我的数字更小，那么这个数字一定是 4 。你猜测数字为 4 并赢得游戏，总费用为 7 + 3 + 5 = 15 。
+&nbsp;           - 如果这是我选中的数字，你的总费用为 $7 + $3 = $10 。否则，你需要支付 $5 。
+&nbsp;           - 如果我的数字更大，那么这个数字一定是 6 。你猜测数字为 6 并赢得游戏，总费用为 $7 + $3 + $5 = $15 。
+&nbsp;           - 如果我的数字更小，那么这个数字一定是 4 。你猜测数字为 4 并赢得游戏，总费用为 $7 + $3 + $5 = $15 。
 &nbsp;       - 如果我的数字更小，则下一步需要猜测的数字范围是 [1,2] 。你可以猜测数字为 1 。
-&nbsp;           - 如果这是我选中的数字，你的总费用为 7 + 3 = 10 。否则，你需要支付 1 。
-&nbsp;           - 如果我的数字更大，那么这个数字一定是 2 。你猜测数字为 2 并赢得游戏，总费用为 7 + 3 + 1 = 11 。
-在最糟糕的情况下，你需要支付 16 。因此，你只需要 16 就可以确保自己赢得游戏。
+&nbsp;           - 如果这是我选中的数字，你的总费用为 $7 + $3 = $10 。否则，你需要支付 $1 。
+&nbsp;           - 如果我的数字更大，那么这个数字一定是 2 。你猜测数字为 2 并赢得游戏，总费用为 $7 + $3 + $1 = $11 。
+在最糟糕的情况下，你需要支付 $16 。因此，你只需要 $16 就可以确保自己赢得游戏。
 </pre>
 
 <p><strong>示例 2：</strong></p>
@@ -59,9 +59,9 @@
 <strong>输出：</strong>1
 <strong>解释：</strong>有两个可能的数字 1 和 2 。
 - 你可以先猜 1 。
-&nbsp;   - 如果这是我选中的数字，你的总费用为 0 。否则，你需要支付 1 。
-&nbsp;   - 如果我的数字更大，那么这个数字一定是 2 。你猜测数字为 2 并赢得游戏，总费用为 1 。
-最糟糕的情况下，你需要支付 1 。
+&nbsp;   - 如果这是我选中的数字，你的总费用为 $0 。否则，你需要支付 $1 。
+&nbsp;   - 如果我的数字更大，那么这个数字一定是 2 。你猜测数字为 2 并赢得游戏，总费用为 $1 。
+最糟糕的情况下，你需要支付 $1 。
 </pre>
 
 <p>&nbsp;</p>

solution/0300-0399/0375.Guess Number Higher or Lower II/README_EN.md

@@ -24,21 +24,21 @@
 <strong>Output:</strong> 16
 <strong>Explanation:</strong> The winning strategy is as follows:
 - The range is [1,10]. Guess 7.
-&nbsp;   - If this is my number, your total is 0. Otherwise, you pay 7.
+&nbsp;   - If this is my number, your total is $0. Otherwise, you pay $7.
 &nbsp;   - If my number is higher, the range is [8,10]. Guess 9.
-&nbsp;       - If this is my number, your total is 7. Otherwise, you pay 9.
-&nbsp;       - If my number is higher, it must be 10. Guess 10. Your total is 7 + 9 = 16.
-&nbsp;       - If my number is lower, it must be 8. Guess 8. Your total is 7 + 9 = 16.
+&nbsp;       - If this is my number, your total is $7. Otherwise, you pay $9.
+&nbsp;       - If my number is higher, it must be 10. Guess 10. Your total is $7 + $9 = $16.
+&nbsp;       - If my number is lower, it must be 8. Guess 8. Your total is $7 + $9 = $16.
 &nbsp;   - If my number is lower, the range is [1,6]. Guess 3.
-&nbsp;       - If this is my number, your total is 7. Otherwise, you pay 3.
+&nbsp;       - If this is my number, your total is $7. Otherwise, you pay $3.
 &nbsp;       - If my number is higher, the range is [4,6]. Guess 5.
-&nbsp;           - If this is my number, your total is 7 + 3 = 10. Otherwise, you pay 5.
-&nbsp;           - If my number is higher, it must be 6. Guess 6. Your total is 7 + 3 + 5 = 15.
-&nbsp;           - If my number is lower, it must be 4. Guess 4. Your total is 7 + 3 + 5 = 15.
+&nbsp;           - If this is my number, your total is $7 + $3 = $10. Otherwise, you pay $5.
+&nbsp;           - If my number is higher, it must be 6. Guess 6. Your total is $7 + $3 + $5 = $15.
+&nbsp;           - If my number is lower, it must be 4. Guess 4. Your total is $7 + $3 + $5 = $15.
 &nbsp;       - If my number is lower, the range is [1,2]. Guess 1.
-&nbsp;           - If this is my number, your total is 7 + 3 = 10. Otherwise, you pay 1.
-&nbsp;           - If my number is higher, it must be 2. Guess 2. Your total is 7 + 3 + 1 = 11.
-The worst case in all these scenarios is that you pay 16. Hence, you only need 16 to guarantee a win.
+&nbsp;           - If this is my number, your total is $7 + $3 = $10. Otherwise, you pay $1.
+&nbsp;           - If my number is higher, it must be 2. Guess 2. Your total is $7 + $3 + $1 = $11.
+The worst case in all these scenarios is that you pay $16. Hence, you only need $16 to guarantee a win.
 </pre>
 
 <p><strong class="example">Example 2:</strong></p>
@@ -56,9 +56,9 @@ The worst case in all these scenarios is that you pay 16. Hence, you only need 1
 <strong>Output:</strong> 1
 <strong>Explanation:</strong>&nbsp;There are two possible numbers, 1 and 2.
 - Guess 1.
-&nbsp;   - If this is my number, your total is 0. Otherwise, you pay 1.
-&nbsp;   - If my number is higher, it must be 2. Guess 2. Your total is 1.
-The worst case is that you pay 1.
+&nbsp;   - If this is my number, your total is $0. Otherwise, you pay $1.
+&nbsp;   - If my number is higher, it must be 2. Guess 2. Your total is $1.
+The worst case is that you pay $1.
 </pre>
 
 <p>&nbsp;</p>

solution/0400-0499/0447.Number of Boomerangs/README.md

@@ -6,7 +6,7 @@
 
 <!-- 这里写题目描述 -->
 
-<p>给定平面上<em>&nbsp;</em><code>n</code><em> </em>对 <strong>互不相同</strong> 的点&nbsp;<code>points</code> ，其中 <code>points[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> 。<strong>回旋镖</strong> 是由点&nbsp;<code>(i, j, k)</code> 表示的元组 ，其中&nbsp;<code>i</code>&nbsp;和&nbsp;<code>j</code>&nbsp;之间的距离和&nbsp;<code>i</code>&nbsp;和&nbsp;<code>k</code>&nbsp;之间的欧式距离相等（<strong>需要考虑元组的顺序</strong>）。</p>
+<p>给定平面上<em>&nbsp;</em><code>n</code><em> </em>对 <strong>互不相同</strong> 的点&nbsp;<code>points</code> ，其中 <code>points[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> 。<strong>回旋镖</strong> 是由点&nbsp;<code>(i, j, k)</code> 表示的元组 ，其中&nbsp;<code>i</code>&nbsp;和&nbsp;<code>j</code>&nbsp;之间的欧式距离和&nbsp;<code>i</code>&nbsp;和&nbsp;<code>k</code>&nbsp;之间的欧式距离相等（<strong>需要考虑元组的顺序</strong>）。</p>
 
 <p>返回平面上所有回旋镖的数量。</p>
 &nbsp;

solution/0400-0499/0465.Optimal Account Balancing/README.md

@@ -6,7 +6,7 @@
 
 <!-- 这里写题目描述 -->
 
-<p>给你一个表示交易的数组 <code>transactions</code> ，其中 <code>transactions[i] = [from<sub>i</sub>, to<sub>i</sub>, amount<sub>i</sub>]</code> 表示 <code>ID = from<sub>i</sub></code> 的人给&nbsp;<code>ID = to<sub>i</sub></code> 的人共计 <code>amount<sub>i</sub> </code> 。</p>
+<p>给你一个表示交易的数组 <code>transactions</code> ，其中 <code>transactions[i] = [from<sub>i</sub>, to<sub>i</sub>, amount<sub>i</sub>]</code> 表示 <code>ID = from<sub>i</sub></code> 的人给&nbsp;<code>ID = to<sub>i</sub></code> 的人共计 <code>amount<sub>i</sub> $</code> 。</p>
 
 <p>请你计算并返回还清所有债务的最小交易笔数。</p>
 
@@ -18,21 +18,21 @@
 <strong>输入：</strong>transactions = [[0,1,10],[2,0,5]]
 <strong>输出：</strong>2
 <strong>解释：</strong>
-#0 给 #1 10 。
-#2 给 #0 5 。
-需要进行两笔交易。一种结清债务的方式是 #1 给 #0 和 #2 各 5 。</pre>
+#0 给 #1 $10 。
+#2 给 #0 $5 。
+需要进行两笔交易。一种结清债务的方式是 #1 给 #0 和 #2 各 $5 。</pre>
 
 <p><strong class="example">示例 2：</strong></p>
 
 <pre>
 <strong>输入：</strong>transactions = [[0,1,10],[1,0,1],[1,2,5],[2,0,5]]
 <strong>输出：</strong>1
 <strong>解释：</strong>
-#0 给 #1 10 。
-#1 给 #0 1 。
-#1 给 #2 5 。
-#2 给 #0 5 。
-因此，#1 只需要给 #0 4 ，所有的债务即可还清。
+#0 给 #1 $10 。
+#1 给 #0 $1 。
+#1 给 #2 $5 。
+#2 给 #0 $5 。
+因此，#1 只需要给 #0 $4 ，所有的债务即可还清。
 </pre>
 
 <p>&nbsp;</p>

solution/0400-0499/0465.Optimal Account Balancing/README_EN.md

@@ -4,7 +4,7 @@
 
 ## Description
 
-<p>You are given an array of transactions <code>transactions</code> where <code>transactions[i] = [from<sub>i</sub>, to<sub>i</sub>, amount<sub>i</sub>]</code> indicates that the person with <code>ID = from<sub>i</sub></code> gave <code>amount<sub>i</sub> </code> to the person with <code>ID = to<sub>i</sub></code>.</p>
+<p>You are given an array of transactions <code>transactions</code> where <code>transactions[i] = [from<sub>i</sub>, to<sub>i</sub>, amount<sub>i</sub>]</code> indicates that the person with <code>ID = from<sub>i</sub></code> gave <code>amount<sub>i</sub> $</code> to the person with <code>ID = to<sub>i</sub></code>.</p>
 
 <p>Return <em>the minimum number of transactions required to settle the debt</em>.</p>
 
@@ -15,9 +15,9 @@
 <strong>Input:</strong> transactions = [[0,1,10],[2,0,5]]
 <strong>Output:</strong> 2
 <strong>Explanation:</strong>
-Person #0 gave person #1 10.
-Person #2 gave person #0 5.
-Two transactions are needed. One way to settle the debt is person #1 pays person #0 and #2 5 each.
+Person #0 gave person #1 $10.
+Person #2 gave person #0 $5.
+Two transactions are needed. One way to settle the debt is person #1 pays person #0 and #2 $5 each.
 </pre>
 
 <p><strong class="example">Example 2:</strong></p>
@@ -26,11 +26,11 @@ Two transactions are needed. One way to settle the debt is person #1 pays person
 <strong>Input:</strong> transactions = [[0,1,10],[1,0,1],[1,2,5],[2,0,5]]
 <strong>Output:</strong> 1
 <strong>Explanation:</strong>
-Person #0 gave person #1 10.
-Person #1 gave person #0 1.
-Person #1 gave person #2 5.
-Person #2 gave person #0 5.
-Therefore, person #1 only need to give person #0 4, and all debt is settled.
+Person #0 gave person #1 $10.
+Person #1 gave person #0 $1.
+Person #1 gave person #2 $5.
+Person #2 gave person #0 $5.
+Therefore, person #1 only need to give person #0 $4, and all debt is settled.
 </pre>
 
 <p>&nbsp;</p>

solution/0500-0599/0549.Binary Tree Longest Consecutive Sequence II/README.md

@@ -1,4 +1,4 @@
-# [549. 二叉树中最长的连续序列](https://leetcode.cn/problems/binary-tree-longest-consecutive-sequence-ii)
+# [549. 二叉树最长连续序列 II](https://leetcode.cn/problems/binary-tree-longest-consecutive-sequence-ii)
 
 [English Version](/solution/0500-0599/0549.Binary%20Tree%20Longest%20Consecutive%20Sequence%20II/README_EN.md)
 

solution/0600-0699/0638.Shopping Offers/README_EN.md

@@ -18,21 +18,21 @@
 <pre>
 <strong>Input:</strong> price = [2,5], special = [[3,0,5],[1,2,10]], needs = [3,2]
 <strong>Output:</strong> 14
-<strong>Explanation:</strong> There are two kinds of items, A and B. Their prices are 2 and 5 respectively. 
-In special offer 1, you can pay 5 for 3A and 0B
-In special offer 2, you can pay 10 for 1A and 2B. 
-You need to buy 3A and 2B, so you may pay 10 for 1A and 2B (special offer #2), and 4 for 2A.
+<strong>Explanation:</strong> There are two kinds of items, A and B. Their prices are $2 and $5 respectively. 
+In special offer 1, you can pay $5 for 3A and 0B
+In special offer 2, you can pay $10 for 1A and 2B. 
+You need to buy 3A and 2B, so you may pay $10 for 1A and 2B (special offer #2), and $4 for 2A.
 </pre>
 
 <p><strong class="example">Example 2:</strong></p>
 
 <pre>
 <strong>Input:</strong> price = [2,3,4], special = [[1,1,0,4],[2,2,1,9]], needs = [1,2,1]
 <strong>Output:</strong> 11
-<strong>Explanation:</strong> The price of A is 2, and 3 for B, 4 for C. 
-You may pay 4 for 1A and 1B, and 9 for 2A ,2B and 1C. 
-You need to buy 1A ,2B and 1C, so you may pay 4 for 1A and 1B (special offer #1), and 3 for 1B, 4 for 1C. 
-You cannot add more items, though only 9 for 2A ,2B and 1C.
+<strong>Explanation:</strong> The price of A is $2, and $3 for B, $4 for C. 
+You may pay $4 for 1A and 1B, and $9 for 2A ,2B and 1C. 
+You need to buy 1A ,2B and 1C, so you may pay $4 for 1A and 1B (special offer #1), and $3 for 1B, $4 for 1C. 
+You cannot add more items, though only $9 for 2A ,2B and 1C.
 </pre>
 
 <p>&nbsp;</p>

solution/0600-0699/0679.24 Game/README.md

@@ -12,6 +12,7 @@
 
 <ul>
 	<li>除法运算符 <code>'/'</code> 表示实数除法，而不是整数除法。
+
     <ul>
     	<li>例如，&nbsp;<code>4 /(1 - 2 / 3)= 4 /(1 / 3)= 12</code>&nbsp;。</li>
     </ul>
@@ -26,6 +27,7 @@
     	<li>例如，如果 <code>cards =[1,2,1,2]</code> ，则表达式 <code>“12 + 12”</code> 无效。</li>
     </ul>
     </li>
+
 </ul>
 
 <p>如果可以得到这样的表达式，其计算结果为 <code>24</code> ，则返回 <code>true </code>，否则返回 <code>false</code>&nbsp;。</p>

solution/0600-0699/0679.24 Game/README_EN.md

@@ -10,6 +10,7 @@
 
 <ul>
 	<li>The division operator <code>&#39;/&#39;</code> represents real division, not integer division.
+
     <ul>
     	<li>For example, <code>4 / (1 - 2 / 3) = 4 / (1 / 3) = 12</code>.</li>
     </ul>
@@ -24,6 +25,7 @@
     	<li>For example, if <code>cards = [1, 2, 1, 2]</code>, the expression <code>&quot;12 + 12&quot;</code> is not valid.</li>
     </ul>
     </li>
+
 </ul>
 
 <p>Return <code>true</code> if you can get such expression that evaluates to <code>24</code>, and <code>false</code> otherwise.</p>

solution/0600-0699/0682.Baseball Game/README_EN.md

@@ -10,6 +10,7 @@
 
 <ul>
 	<li>An integer <code>x</code>.
+
     <ul>
     	<li>Record a new score of <code>x</code>.</li>
     </ul>
@@ -29,6 +30,7 @@
     	<li>Invalidate the previous score, removing it from the record.</li>
     </ul>
     </li>
+
 </ul>
 
 <p>Return <em>the sum of all the scores on the record after applying all the operations</em>.</p>

solution/0700-0799/0753.Cracking the Safe/README_EN.md

@@ -10,6 +10,7 @@
 
 <ul>
 	<li>For example, the correct password is <code>&quot;345&quot;</code> and you enter in <code>&quot;012345&quot;</code>:
+
     <ul>
     	<li>After typing <code>0</code>, the most recent <code>3</code> digits is <code>&quot;0&quot;</code>, which is incorrect.</li>
     	<li>After typing <code>1</code>, the most recent <code>3</code> digits is <code>&quot;01&quot;</code>, which is incorrect.</li>
@@ -19,6 +20,7 @@
     	<li>After typing <code>5</code>, the most recent <code>3</code> digits is <code>&quot;345&quot;</code>, which is correct and the safe unlocks.</li>
     </ul>
     </li>
+
 </ul>
 
 <p>Return <em>any string of <strong>minimum length</strong> that will unlock the safe <strong>at some point</strong> of entering it</em>.</p>
@@ -42,7 +44,7 @@
 - &quot;01&quot; is typed in starting from the 1<sup>st</sup> digit.
 - &quot;10&quot; is typed in starting from the 3<sup>rd</sup> digit.
 - &quot;11&quot; is typed in starting from the 2<sup>nd</sup> digit.
-Thus &quot;01100&quot; will unlock the safe. &quot;01100&quot;, &quot;10011&quot;, and &quot;11001&quot; would also unlock the safe.
+Thus &quot;01100&quot; will unlock the safe. &quot;10011&quot;, and &quot;11001&quot; would also unlock the safe.
 </pre>
 
 <p>&nbsp;</p>