feat: add solutions to lc problems: No.1173,1174

* No.1173.Immediate Food Delivery I
* No.1174.Immediate Food Delivery II

Author: yanglbme

solution/1100-1199/1173.Immediate Food Delivery I/README.md

@@ -63,7 +63,14 @@ Delivery 表:
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+select
+    round(
+        sum(if(order_date = customer_pref_delivery_date, 1, 0)) / count(1) * 100,
+        2
+    ) as immediate_percentage
+from
+    Delivery;
 ```
 
 <!-- tabs:end -->

solution/1100-1199/1173.Immediate Food Delivery I/README_EN.md

@@ -59,7 +59,14 @@ Delivery table:
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+select
+    round(
+        sum(if(order_date = customer_pref_delivery_date, 1, 0)) / count(1) * 100,
+        2
+    ) as immediate_percentage
+from
+    Delivery;
 ```
 
 <!-- tabs:end -->

solution/1100-1199/1173.Immediate Food Delivery I/Solution.sql

@@ -0,0 +1,8 @@
+# Write your MySQL query statement below
+select
+    round(
+        sum(if(order_date = customer_pref_delivery_date, 1, 0)) / count(1) * 100,
+        2
+    ) as immediate_percentage
+from
+    Delivery;

solution/1100-1199/1174.Immediate Food Delivery II/README.md

@@ -67,7 +67,30 @@ Result 表：
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+select
+    round(
+        sum(
+            if(
+                t1.order_date = t1.customer_pref_delivery_date,
+                1,
+                0
+            )
+        ) / count(1) * 100,
+        2
+    ) as immediate_percentage
+from
+    Delivery t1
+    right join (
+        select
+            customer_id,
+            min(order_date) as order_date
+        from
+            Delivery
+        group by
+            customer_id
+    ) t2 on t1.customer_id = t2.customer_id
+    and t1.order_date = t2.order_date
 ```
 
 <!-- tabs:end -->

solution/1100-1199/1174.Immediate Food Delivery II/README_EN.md

@@ -67,7 +67,30 @@ Hence, half the customers have immediate first orders.
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+select
+    round(
+        sum(
+            if(
+                t1.order_date = t1.customer_pref_delivery_date,
+                1,
+                0
+            )
+        ) / count(1) * 100,
+        2
+    ) as immediate_percentage
+from
+    Delivery t1
+    right join (
+        select
+            customer_id,
+            min(order_date) as order_date
+        from
+            Delivery
+        group by
+            customer_id
+    ) t2 on t1.customer_id = t2.customer_id
+    and t1.order_date = t2.order_date
 ```
 
 <!-- tabs:end -->

solution/1100-1199/1174.Immediate Food Delivery II/Solution.sql

@@ -0,0 +1,24 @@
+# Write your MySQL query statement below
+select
+    round(
+        sum(
+            if(
+                t1.order_date = t1.customer_pref_delivery_date,
+                1,
+                0
+            )
+        ) / count(1) * 100,
+        2
+    ) as immediate_percentage
+from
+    Delivery t1
+    right join (
+        select
+            customer_id,
+            min(order_date) as order_date
+        from
+            Delivery
+        group by
+            customer_id
+    ) t2 on t1.customer_id = t2.customer_id
+    and t1.order_date = t2.order_date