feat: add solution to lc problem: No.1412

No.1412.Find the Quiet Students in All Exams

Author: yanglbme

solution/1400-1499/1412.Find the Quiet Students in All Exams/README.md

@@ -97,7 +97,34 @@ Result 表：
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+with t as (
+    select
+        *,
+        rank() over(
+            partition by exam_id
+            order by
+                score desc
+        ) rk1,
+        rank() over(
+            partition by exam_id
+            order by
+                score asc
+        ) rk2
+    from
+        Exam
+)
+select
+    t.student_id,
+    student_name
+from
+    t
+    join Student s on t.student_id = s.student_id
+group by
+    t.student_id
+having
+    sum(rk1 = 1) = 0
+    and sum(rk2 = 1) = 0;
 ```
 
 <!-- tabs:end -->

solution/1400-1499/1412.Find the Quiet Students in All Exams/README_EN.md

@@ -94,7 +94,34 @@ So, we only return the information of Student 2.
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+with t as (
+    select
+        *,
+        rank() over(
+            partition by exam_id
+            order by
+                score desc
+        ) rk1,
+        rank() over(
+            partition by exam_id
+            order by
+                score asc
+        ) rk2
+    from
+        Exam
+)
+select
+    t.student_id,
+    student_name
+from
+    t
+    join Student s on t.student_id = s.student_id
+group by
+    t.student_id
+having
+    sum(rk1 = 1) = 0
+    and sum(rk2 = 1) = 0;
 ```
 
 <!-- tabs:end -->

solution/1400-1499/1412.Find the Quiet Students in All Exams/Solution.sql

@@ -0,0 +1,28 @@
+# Write your MySQL query statement below
+with t as (
+    select
+        *,
+        rank() over(
+            partition by exam_id
+            order by
+                score desc
+        ) rk1,
+        rank() over(
+            partition by exam_id
+            order by
+                score asc
+        ) rk2
+    from
+        Exam
+)
+select
+    t.student_id,
+    student_name
+from
+    t
+    join Student s on t.student_id = s.student_id
+group by
+    t.student_id
+having
+    sum(rk1 = 1) = 0
+    and sum(rk2 = 1) = 0;