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54c4475 · Sep 27, 2023

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题目描述

现给定一个函数 fn ,一个参数数组 args 和一个以毫秒为单位的超时时间 t ,返回一个取消函数 cancelFn

在经过 t 毫秒的延迟后,应该调用 fn 函数,并将 args 作为参数传递。除非t 毫秒的延迟过程中,在 cancelT 毫秒时调用了 cancelFn。并且在这种情况下,fn 函数不应该被调用。

示例 1:

输入:fn = (x) => x * 5, args = [2], t = 20, cancelT = 50
输出:[{"time": 20, "returned": 10}]
解释:
const cancel = cancellable((x) => x * 5, [2], 20); // fn(2) 在 t=20ms 时被调用
setTimeout(cancel, 50);

取消操作被安排在延迟了 cancelT(50毫秒)后进行,这发生在 fn(2) 在20毫秒时执行之后。

示例 2:

输入:fn = (x) => x**2, args = [2], t = 100, cancelT = 50
输出:[]
解释:
const cancel = cancellable((x) => x**2, [2], 100); // fn(2) 没被调用
setTimeout(cancel, 50);

取消操作被安排在延迟了 cancelT(50毫秒)后进行,这发生在 fn(2) 在100毫秒时执行之前,导致 fn(2) 从未被调用。

示例 3:

输入:fn = (x1, x2) => x1 * x2, args = [2,4], t = 30, cancelTime = 100
输出:[{"time": 30, "returned": 8}]
解释:
const cancel = cancellable((x1, x2) => x1 * x2, [2,4], 30); // fn(2,4) 在 t=30ms 时被调用
setTimeout(cancel, 100);

取消操作被安排在延迟了 cancelT(100毫秒)后进行,这发生在 fn(2,4) 在30毫秒时执行之后。

 

提示:

  • fn 是一个函数
  • args 是一个有效的 JSON 数组
  • 1 <= args.length <= 10
  • 20 <= t <= 1000
  • 10 <= cancelT <= 1000

解法

TypeScript

function cancellable(fn: Function, args: any[], t: number): Function {
    const timer = setTimeout(() => fn(...args), t);
    return () => {
        clearTimeout(timer);
    };
}

/**
 *  const result = []
 *
 *  const fn = (x) => x * 5
 *  const args = [2], t = 20, cancelT = 50
 *
 *  const start = performance.now()
 *
 *  const log = (...argsArr) => {
 *      const diff = Math.floor(performance.now() - start);
 *      result.push({"time": diff, "returned": fn(...argsArr))
 *  }
 *
 *  const cancel = cancellable(log, args, t);
 *
 *  const maxT = Math.max(t, cancelT)
 *
 *  setTimeout(() => {
 *     cancel()
 *  }, cancelT)
 *
 *  setTimeout(() => {
 *     console.log(result) // [{"time":20,"returned":10}]
 *  }, maxT + 15)
 */

JavaScript

/**
 * @param {Function} fn
 * @param {Array} args
 * @param {number} t
 * @return {Function}
 */
var cancellable = function (fn, args, t) {
    const timer = setTimeout(() => fn(...args), t);
    return () => {
        clearTimeout(timer);
    };
};

/**
 *  const result = []
 *
 *  const fn = (x) => x * 5
 *  const args = [2], t = 20, cancelT = 50
 *
 *  const start = performance.now()
 *
 *  const log = (...argsArr) => {
 *      const diff = Math.floor(performance.now() - start);
 *      result.push({"time": diff, "returned": fn(...argsArr))
 *  }
 *
 *  const cancel = cancellable(log, args, t);
 *
 *  const maxT = Math.max(t, cancelT)
 *
 *  setTimeout(() => {
 *     cancel()
 *  }, cancelT)
 *
 *  setTimeout(() => {
 *     console.log(result) // [{"time":20,"returned":10}]
 *  }, maxT + 15)
 */