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| 1 | +const set = new Set(); |
| 2 | + |
| 3 | +set.add(1); |
| 4 | +console.log(set.values()); // outputs @Iterator |
| 5 | +console.log(set.has(1)); // outputs true |
| 6 | +console.log(set.size); // outputs 1 |
| 7 | + |
| 8 | +set.add(2); |
| 9 | +console.log(set.values()); // outputs [1, 2] |
| 10 | +console.log(set.has(2)); // true |
| 11 | +console.log(set.size); // 2 |
| 12 | + |
| 13 | +set.delete(1); |
| 14 | +console.log(set.values()); // outputs [2] |
| 15 | + |
| 16 | +set.delete(2); |
| 17 | +console.log(set.values()); // outputs [] |
| 18 | + |
| 19 | +const setA = new Set(); |
| 20 | +setA.add(1); |
| 21 | +setA.add(2); |
| 22 | +setA.add(3); |
| 23 | + |
| 24 | +const setB = new Set(); |
| 25 | +setB.add(2); |
| 26 | +setB.add(3); |
| 27 | +setB.add(4); |
| 28 | + |
| 29 | +// --------- Union ---------- |
| 30 | +const union = (set1, set2) => { |
| 31 | + const unionAb = new Set(); |
| 32 | + set1.forEach(value => unionAb.add(value)); |
| 33 | + set2.forEach(value => unionAb.add(value)); |
| 34 | + return unionAb; |
| 35 | +}; |
| 36 | +console.log(union(setA, setB)); |
| 37 | + |
| 38 | +// --------- Intersection ---------- |
| 39 | +const intersection = (set1, set2) => { |
| 40 | + const intersectionSet = new Set(); |
| 41 | + set1.forEach(value => { |
| 42 | + if (set2.has(value)) { |
| 43 | + intersectionSet.add(value); |
| 44 | + } |
| 45 | + }); |
| 46 | + return intersectionSet; |
| 47 | +}; |
| 48 | +console.log(intersection(setA, setB)); |
| 49 | + |
| 50 | +// alternative - works on FF only |
| 51 | +// console.log(new Set([x for (x of setA) if (setB.has(x))])); |
| 52 | + |
| 53 | +// --------- Difference ---------- |
| 54 | +const difference = (set1, set2) => { |
| 55 | + const differenceSet = new Set(); |
| 56 | + set1.forEach(value => { |
| 57 | + if (!set2.has(value)) { |
| 58 | + differenceSet.add(value); |
| 59 | + } |
| 60 | + }); |
| 61 | + return differenceSet; |
| 62 | +}; |
| 63 | +console.log(difference(setA, setB)); |
| 64 | + |
| 65 | +// alternative - works on FF only |
| 66 | +// console.log(new Set([x for (x of setA) if (!setB.has(x))])); |
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