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feat: add solutions to lcci problem: No.10.01
* Add solutions to lcci problem: No.10.01.Sorted Merge * Add new lc problem
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Diff for: ‎lcci/10.01.Sorted Merge/README.md

+58-2
Original file line numberDiff line numberDiff line change
@@ -34,15 +34,38 @@ B = [2,5,6], n = 3
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```python
37-
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class Solution:
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def merge(self, A: List[int], m: int, B: List[int], n: int) -> None:
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"""
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Do not return anything, modify A in-place instead.
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"""
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i, j = m - 1, n - 1
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for k in range(len(A) - 1, -1, -1):
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if j < 0 or (i >= 0 and A[i] >= B[j]):
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A[k] = A[i]
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i -= 1
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else:
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A[k] = B[j]
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j -= 1
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```
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### **Java**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```java
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class Solution {
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public void merge(int[] A, int m, int[] B, int n) {
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int i = m - 1, j = n - 1;
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for (int k = A.length - 1; k >= 0; --k) {
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if (j < 0 || (i >= 0 && A[i] >= B[j])) {
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A[k] = A[i--];
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} else {
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A[k] = B[j--];
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}
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}
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}
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}
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```
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### **JavaScript**
@@ -114,6 +137,39 @@ impl Solution {
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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void merge(vector<int>& A, int m, vector<int>& B, int n) {
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int i = m - 1, j = n - 1;
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for (int k = A.size() - 1; k >= 0; --k)
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{
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if (j < 0 || (i >= 0 && A[i] >= B[j])) A[k] = A[i--];
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else A[k] = B[j--];
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}
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}
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};
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```
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### **Go**
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```go
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func merge(A []int, m int, B []int, n int) {
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i, j := m-1, n-1
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for k := len(A) - 1; k >= 0; k-- {
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if j < 0 || (i >= 0 && A[i] >= B[j]) {
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A[k] = A[i]
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i--
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} else {
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A[k] = B[j]
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j--
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}
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}
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}
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```
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### **...**
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```

Diff for: ‎lcci/10.01.Sorted Merge/README_EN.md

+58-2
Original file line numberDiff line numberDiff line change
@@ -29,13 +29,36 @@ B = [2,5,6], n = 3
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### **Python3**
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```python
32-
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class Solution:
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def merge(self, A: List[int], m: int, B: List[int], n: int) -> None:
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"""
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Do not return anything, modify A in-place instead.
36+
"""
37+
i, j = m - 1, n - 1
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for k in range(len(A) - 1, -1, -1):
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if j < 0 or (i >= 0 and A[i] >= B[j]):
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A[k] = A[i]
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i -= 1
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else:
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A[k] = B[j]
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j -= 1
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```
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### **Java**
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```java
38-
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class Solution {
51+
public void merge(int[] A, int m, int[] B, int n) {
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int i = m - 1, j = n - 1;
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for (int k = A.length - 1; k >= 0; --k) {
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if (j < 0 || (i >= 0 && A[i] >= B[j])) {
55+
A[k] = A[i--];
56+
} else {
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A[k] = B[j--];
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}
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}
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}
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}
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```
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### **JavaScript**
@@ -107,6 +130,39 @@ impl Solution {
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}
108131
```
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### **C++**
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```cpp
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class Solution {
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public:
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void merge(vector<int>& A, int m, vector<int>& B, int n) {
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int i = m - 1, j = n - 1;
140+
for (int k = A.size() - 1; k >= 0; --k)
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{
142+
if (j < 0 || (i >= 0 && A[i] >= B[j])) A[k] = A[i--];
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else A[k] = B[j--];
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}
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}
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};
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```
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### **Go**
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```go
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func merge(A []int, m int, B []int, n int) {
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i, j := m-1, n-1
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for k := len(A) - 1; k >= 0; k-- {
155+
if j < 0 || (i >= 0 && A[i] >= B[j]) {
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A[k] = A[i]
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i--
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} else {
159+
A[k] = B[j]
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j--
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}
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}
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}
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```
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110166
### **...**
111167

112168
```

Diff for: ‎lcci/10.01.Sorted Merge/Solution.cpp

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@@ -0,0 +1,11 @@
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class Solution {
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public:
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void merge(vector<int>& A, int m, vector<int>& B, int n) {
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int i = m - 1, j = n - 1;
5+
for (int k = A.size() - 1; k >= 0; --k)
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{
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if (j < 0 || (i >= 0 && A[i] >= B[j])) A[k] = A[i--];
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else A[k] = B[j--];
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}
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}
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};

Diff for: ‎lcci/10.01.Sorted Merge/Solution.go

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Original file line numberDiff line numberDiff line change
@@ -0,0 +1,12 @@
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func merge(A []int, m int, B []int, n int) {
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i, j := m-1, n-1
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for k := len(A) - 1; k >= 0; k-- {
4+
if j < 0 || (i >= 0 && A[i] >= B[j]) {
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A[k] = A[i]
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i--
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} else {
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A[k] = B[j]
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j--
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}
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}
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}

Diff for: ‎lcci/10.01.Sorted Merge/Solution.java

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Original file line numberDiff line numberDiff line change
@@ -0,0 +1,12 @@
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class Solution {
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public void merge(int[] A, int m, int[] B, int n) {
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int i = m - 1, j = n - 1;
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for (int k = A.length - 1; k >= 0; --k) {
5+
if (j < 0 || (i >= 0 && A[i] >= B[j])) {
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A[k] = A[i--];
7+
} else {
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A[k] = B[j--];
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}
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}
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}
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}

Diff for: ‎lcci/10.01.Sorted Merge/Solution.py

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Original file line numberDiff line numberDiff line change
@@ -0,0 +1,13 @@
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class Solution:
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def merge(self, A: List[int], m: int, B: List[int], n: int) -> None:
3+
"""
4+
Do not return anything, modify A in-place instead.
5+
"""
6+
i, j = m - 1, n - 1
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for k in range(len(A) - 1, -1, -1):
8+
if j < 0 or (i >= 0 and A[i] >= B[j]):
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A[k] = A[i]
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i -= 1
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else:
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A[k] = B[j]
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j -= 1

Diff for: ‎solution/2300-2399/2345.Finding the Number of Visible Mountains/README.md

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# [2345. Finding the Number of Visible Mountains](https://leetcode.cn/problems/finding-the-number-of-visible-mountains)
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[English Version](/solution/2300-2399/2345.Finding%20the%20Number%20of%20Visible%20Mountains/README_EN.md)
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## 题目描述
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<!-- 这里写题目描述 -->
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<p>You are given a <strong>0-indexed</strong> 2D integer array <code>peaks</code> where <code>peaks[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> states that mountain <code>i</code> has a peak at coordinates <code>(x<sub>i</sub>, y<sub>i</sub>)</code>. A mountain can be described as a right-angled isosceles triangle, with its base along the <code>x</code>-axis and a right angle at its peak. More formally, the <strong>gradients</strong> of ascending and descending the mountain are <code>1</code> and <code>-1</code> respectively.</p>
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<p>A mountain is considered <strong>visible</strong> if its peak does not lie within another mountain (including the border of other mountains).</p>
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<p>Return <em>the number of visible mountains</em>.</p>
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<p>&nbsp;</p>
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<p><strong>Example 1:</strong></p>
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<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/2300-2399/2345.Finding%20the%20Number%20of%20Visible%20Mountains/images/ex1.png" style="width: 402px; height: 210px;" />
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<pre>
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<strong>Input:</strong> peaks = [[2,2],[6,3],[5,4]]
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<strong>Output:</strong> 2
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<strong>Explanation:</strong> The diagram above shows the mountains.
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- Mountain 0 is visible since its peak does not lie within another mountain or its sides.
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- Mountain 1 is not visible since its peak lies within the side of mountain 2.
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- Mountain 2 is visible since its peak does not lie within another mountain or its sides.
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There are 2 mountains that are visible.</pre>
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<p><strong>Example 2:</strong></p>
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<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/2300-2399/2345.Finding%20the%20Number%20of%20Visible%20Mountains/images/ex2new1.png" style="width: 300px; height: 180px;" />
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<pre>
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<strong>Input:</strong> peaks = [[1,3],[1,3]]
31+
<strong>Output:</strong> 0
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<strong>Explanation:</strong> The diagram above shows the mountains (they completely overlap).
33+
Both mountains are not visible since their peaks lie within each other.
34+
</pre>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
38+
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<ul>
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<li><code>1 &lt;= peaks.length &lt;= 10<sup>5</sup></code></li>
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<li><code>peaks[i].length == 2</code></li>
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<li><code>1 &lt;= x<sub>i</sub>, y<sub>i</sub> &lt;= 10<sup>5</sup></code></li>
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</ul>
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## 解法
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<!-- 这里可写通用的实现逻辑 -->
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<!-- tabs:start -->
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### **Python3**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```python
57+
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```
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### **Java**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
63+
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```java
65+
66+
```
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### **TypeScript**
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```ts
71+
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```
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### **...**
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```
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```
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<!-- tabs:end -->

Diff for: ‎solution/2300-2399/2345.Finding the Number of Visible Mountains/README_EN.md

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# [2345. Finding the Number of Visible Mountains](https://leetcode.com/problems/finding-the-number-of-visible-mountains)
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[中文文档](/solution/2300-2399/2345.Finding%20the%20Number%20of%20Visible%20Mountains/README.md)
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## Description
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<p>You are given a <strong>0-indexed</strong> 2D integer array <code>peaks</code> where <code>peaks[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> states that mountain <code>i</code> has a peak at coordinates <code>(x<sub>i</sub>, y<sub>i</sub>)</code>. A mountain can be described as a right-angled isosceles triangle, with its base along the <code>x</code>-axis and a right angle at its peak. More formally, the <strong>gradients</strong> of ascending and descending the mountain are <code>1</code> and <code>-1</code> respectively.</p>
8+
9+
<p>A mountain is considered <strong>visible</strong> if its peak does not lie within another mountain (including the border of other mountains).</p>
10+
11+
<p>Return <em>the number of visible mountains</em>.</p>
12+
13+
<p>&nbsp;</p>
14+
<p><strong>Example 1:</strong></p>
15+
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/2300-2399/2345.Finding%20the%20Number%20of%20Visible%20Mountains/images/ex1.png" style="width: 402px; height: 210px;" />
16+
<pre>
17+
<strong>Input:</strong> peaks = [[2,2],[6,3],[5,4]]
18+
<strong>Output:</strong> 2
19+
<strong>Explanation:</strong> The diagram above shows the mountains.
20+
- Mountain 0 is visible since its peak does not lie within another mountain or its sides.
21+
- Mountain 1 is not visible since its peak lies within the side of mountain 2.
22+
- Mountain 2 is visible since its peak does not lie within another mountain or its sides.
23+
There are 2 mountains that are visible.</pre>
24+
25+
<p><strong>Example 2:</strong></p>
26+
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/2300-2399/2345.Finding%20the%20Number%20of%20Visible%20Mountains/images/ex2new1.png" style="width: 300px; height: 180px;" />
27+
<pre>
28+
<strong>Input:</strong> peaks = [[1,3],[1,3]]
29+
<strong>Output:</strong> 0
30+
<strong>Explanation:</strong> The diagram above shows the mountains (they completely overlap).
31+
Both mountains are not visible since their peaks lie within each other.
32+
</pre>
33+
34+
<p>&nbsp;</p>
35+
<p><strong>Constraints:</strong></p>
36+
37+
<ul>
38+
<li><code>1 &lt;= peaks.length &lt;= 10<sup>5</sup></code></li>
39+
<li><code>peaks[i].length == 2</code></li>
40+
<li><code>1 &lt;= x<sub>i</sub>, y<sub>i</sub> &lt;= 10<sup>5</sup></code></li>
41+
</ul>
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43+
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## Solutions
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<!-- tabs:start -->
47+
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### **Python3**
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50+
```python
51+
52+
```
53+
54+
### **Java**
55+
56+
```java
57+
58+
```
59+
60+
### **TypeScript**
61+
62+
```ts
63+
64+
```
65+
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### **...**
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```
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```
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<!-- tabs:end -->

Diff for: ‎solution/2300-2399/2345.Finding the Number of Visible Mountains/images/ex1.png

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Diff for: ‎solution/2300-2399/2345.Finding the Number of Visible Mountains/images/ex2new1.png

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