feat: add sql solutions to lc problems: No.1517,1623,1635 (doocs#1097)

* No.1517.Find Users With Valid E-Mails
* No.1623.All Valid Triplets That Can Represent a Country
* No.1635.Hopper Company Queries I

Author: yanglbme

.prettierignore

@@ -21,4 +21,5 @@ node_modules/
 /solution/1400-1499/1484.Group Sold Products By The Date/Solution.sql
 /solution/1500-1599/1511.Customer Order Frequency
 /solution/1600-1699/1613.Find the Missing IDs/Solution.sql
+/solution/1600-1699/1635.Hopper Company Queries I/Solution.sql
 /solution/1700-1799/1767.Find the Subtasks That Did Not Execute/Solution.sql

solution/1500-1599/1517.Find Users With Valid E-Mails/README.md

@@ -68,12 +68,17 @@ user_id （用户 ID）是该表的主键。
 
 <!-- 这里可写通用的实现逻辑 -->
 
+**方法一：REGEXP 正则匹配**
+
 <!-- tabs:start -->
 
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT *
+FROM Users
+WHERE mail REGEXP '^[a-zA-Z][a-zA-Z0-9_.-]*@leetcode[.]com$';
 ```
 
 <!-- tabs:end -->

solution/1500-1599/1517.Find Users With Valid E-Mails/README_EN.md

@@ -72,7 +72,10 @@ The mail of user 7 starts with a period.
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT *
+FROM Users
+WHERE mail REGEXP '^[a-zA-Z][a-zA-Z0-9_.-]*@leetcode[.]com$';
 ```
 
 <!-- tabs:end -->

solution/1500-1599/1517.Find Users With Valid E-Mails/Solution.sql

@@ -0,0 +1,4 @@
+# Write your MySQL query statement below
+SELECT *
+FROM Users
+WHERE mail REGEXP '^[a-zA-Z][a-zA-Z0-9_.-]*@leetcode[.]com$';

solution/1600-1699/1623.All Valid Triplets That Can Represent a Country/README.md

@@ -125,7 +125,22 @@ SchoolA</code> table:
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    a.student_name AS member_A,
+    b.student_name AS member_B,
+    c.student_name AS member_C
+FROM
+    SchoolA AS a,
+    SchoolB AS b,
+    SchoolC AS c
+WHERE
+    a.student_name != b.student_name
+    AND a.student_name != c.student_name
+    AND b.student_name != c.student_name
+    AND a.student_id != b.student_id
+    AND a.student_id != c.student_id
+    AND b.student_id != c.student_id;
 ```
 
 <!-- tabs:end -->

solution/1600-1699/1623.All Valid Triplets That Can Represent a Country/README_EN.md

@@ -117,7 +117,22 @@ Let us see all the possible triplets.
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    a.student_name AS member_A,
+    b.student_name AS member_B,
+    c.student_name AS member_C
+FROM
+    SchoolA AS a,
+    SchoolB AS b,
+    SchoolC AS c
+WHERE
+    a.student_name != b.student_name
+    AND a.student_name != c.student_name
+    AND b.student_name != c.student_name
+    AND a.student_id != b.student_id
+    AND a.student_id != c.student_id
+    AND b.student_id != c.student_id;
 ```
 
 <!-- tabs:end -->

solution/1600-1699/1623.All Valid Triplets That Can Represent a Country/Solution.sql

@@ -0,0 +1,16 @@
+# Write your MySQL query statement below
+SELECT
+    a.student_name AS member_A,
+    b.student_name AS member_B,
+    c.student_name AS member_C
+FROM
+    SchoolA AS a,
+    SchoolB AS b,
+    SchoolC AS c
+WHERE
+    a.student_name != b.student_name
+    AND a.student_name != c.student_name
+    AND b.student_name != c.student_name
+    AND a.student_id != b.student_id
+    AND a.student_id != c.student_id
+    AND b.student_id != c.student_id;

solution/1600-1699/1635.Hopper Company Queries I/README.md

@@ -161,7 +161,36 @@ ride_id是该表的主键。
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+WITH
+    recursive Months AS (
+        SELECT
+            1 AS month
+        UNION ALL
+        SELECT
+            month + 1
+        FROM Months
+        WHERE month < 12
+    ),
+    Ride AS (
+        SELECT month(requested_at) AS month, count(1) AS cnt
+        FROM
+            Rides AS r
+            JOIN AcceptedRides AS a
+                ON r.ride_id = a.ride_id AND year(requested_at) = 2020
+        GROUP BY month
+    )
+SELECT
+    m.month,
+    count(driver_id) AS active_drivers,
+    ifnull(r.cnt, 0) AS accepted_rides
+FROM
+    Months AS m
+    LEFT JOIN Drivers AS d
+        ON (m.month >= month(d.join_date) AND year(d.join_date) = 2020)
+        OR year(d.join_date) < 2020
+    LEFT JOIN Ride AS r ON m.month = r.month
+GROUP BY month;
 ```
 
 <!-- tabs:end -->

solution/1600-1699/1635.Hopper Company Queries I/README_EN.md

@@ -157,7 +157,36 @@ By the end of December --> six active drivers (10, 8, 5, 7, 4, 1) and one acc
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+WITH
+    recursive Months AS (
+        SELECT
+            1 AS month
+        UNION ALL
+        SELECT
+            month + 1
+        FROM Months
+        WHERE month < 12
+    ),
+    Ride AS (
+        SELECT month(requested_at) AS month, count(1) AS cnt
+        FROM
+            Rides AS r
+            JOIN AcceptedRides AS a
+                ON r.ride_id = a.ride_id AND year(requested_at) = 2020
+        GROUP BY month
+    )
+SELECT
+    m.month,
+    count(driver_id) AS active_drivers,
+    ifnull(r.cnt, 0) AS accepted_rides
+FROM
+    Months AS m
+    LEFT JOIN Drivers AS d
+        ON (m.month >= month(d.join_date) AND year(d.join_date) = 2020)
+        OR year(d.join_date) < 2020
+    LEFT JOIN Ride AS r ON m.month = r.month
+GROUP BY month;
 ```
 
 <!-- tabs:end -->

solution/1600-1699/1635.Hopper Company Queries I/Solution.sql

@@ -0,0 +1,30 @@
+# Write your MySQL query statement below
+WITH
+    recursive Months AS (
+        SELECT
+            1 AS month
+        UNION ALL
+        SELECT
+            month + 1
+        FROM Months
+        WHERE month < 12
+    ),
+    Ride AS (
+        SELECT month(requested_at) AS month, count(1) AS cnt
+        FROM
+            Rides AS r
+            JOIN AcceptedRides AS a
+                ON r.ride_id = a.ride_id AND year(requested_at) = 2020
+        GROUP BY month
+    )
+SELECT
+    m.month,
+    count(driver_id) AS active_drivers,
+    ifnull(r.cnt, 0) AS accepted_rides
+FROM
+    Months AS m
+    LEFT JOIN Drivers AS d
+        ON (m.month >= month(d.join_date) AND year(d.join_date) = 2020)
+        OR year(d.join_date) < 2020
+    LEFT JOIN Ride AS r ON m.month = r.month
+GROUP BY month;