feat: add sql solutions to lc problems: No.2142,2173 (doocs#1124)

* No.2142.The Number of Passengers in Each Bus I
* No.2173.Longest Winning Streak

Author: yanglbme

solution/2100-2199/2142.The Number of Passengers in Each Bus I/README.md

@@ -95,7 +95,17 @@ Passengers 表:
 <!-- 这里可写当前语言的特殊实现逻辑 -->
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    bus_id,
+    count(passenger_id) - lag(count(passenger_id), 1, 0) OVER (
+        ORDER BY b.arrival_time
+    ) AS passengers_cnt
+FROM
+    Buses AS b
+    LEFT JOIN Passengers AS p ON p.arrival_time <= b.arrival_time
+GROUP BY 1
+ORDER BY 1;
 ```
 
 <!-- tabs:end -->

solution/2100-2199/2142.The Number of Passengers in Each Bus I/README_EN.md

@@ -92,7 +92,17 @@ Passengers table:
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    bus_id,
+    count(passenger_id) - lag(count(passenger_id), 1, 0) OVER (
+        ORDER BY b.arrival_time
+    ) AS passengers_cnt
+FROM
+    Buses AS b
+    LEFT JOIN Passengers AS p ON p.arrival_time <= b.arrival_time
+GROUP BY 1
+ORDER BY 1;
 ```
 
 <!-- tabs:end -->

solution/2100-2199/2142.The Number of Passengers in Each Bus I/Solution.sql

@@ -0,0 +1,11 @@
+# Write your MySQL query statement below
+SELECT
+    bus_id,
+    count(passenger_id) - lag(count(passenger_id), 1, 0) OVER (
+        ORDER BY b.arrival_time
+    ) AS passengers_cnt
+FROM
+    Buses AS b
+    LEFT JOIN Passengers AS p ON p.arrival_time <= b.arrival_time
+GROUP BY 1
+ORDER BY 1;

solution/2100-2199/2173.Longest Winning Streak/README.md

@@ -88,7 +88,28 @@ Player 3:
 <!-- 这里可写当前语言的特殊实现逻辑 -->
 
 ```sql
-
+# Write your MySQL query statement below
+WITH
+    S AS (
+        SELECT
+            *,
+            row_number() OVER (
+                PARTITION BY player_id
+                ORDER BY match_day
+            ) - row_number() OVER (
+                PARTITION BY player_id, result
+                ORDER BY match_day
+            ) AS rk
+        FROM Matches
+    ),
+    T AS (
+        SELECT player_id, sum(result = 'Win') AS s
+        FROM S
+        GROUP BY player_id, rk
+    )
+SELECT player_id, max(s) AS longest_streak
+FROM T
+GROUP BY player_id;
 ```
 
 <!-- tabs:end -->

solution/2100-2199/2173.Longest Winning Streak/README_EN.md

@@ -81,7 +81,28 @@ The longest winning streak was 1 match.
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+WITH
+    S AS (
+        SELECT
+            *,
+            row_number() OVER (
+                PARTITION BY player_id
+                ORDER BY match_day
+            ) - row_number() OVER (
+                PARTITION BY player_id, result
+                ORDER BY match_day
+            ) AS rk
+        FROM Matches
+    ),
+    T AS (
+        SELECT player_id, sum(result = 'Win') AS s
+        FROM S
+        GROUP BY player_id, rk
+    )
+SELECT player_id, max(s) AS longest_streak
+FROM T
+GROUP BY player_id;
 ```
 
 <!-- tabs:end -->

solution/2100-2199/2173.Longest Winning Streak/Solution.sql

@@ -0,0 +1,22 @@
+# Write your MySQL query statement below
+WITH
+    S AS (
+        SELECT
+            *,
+            row_number() OVER (
+                PARTITION BY player_id
+                ORDER BY match_day
+            ) - row_number() OVER (
+                PARTITION BY player_id, result
+                ORDER BY match_day
+            ) AS rk
+        FROM Matches
+    ),
+    T AS (
+        SELECT player_id, sum(result = 'Win') AS s
+        FROM S
+        GROUP BY player_id, rk
+    )
+SELECT player_id, max(s) AS longest_streak
+FROM T
+GROUP BY player_id;