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| 1 | +/** |
| 2 | + * [993] Cousins in Binary Tree |
| 3 | + * |
| 4 | + * In a binary tree, the root node is at depth 0, and children of each depth k node are at depth k+1. |
| 5 | + * |
| 6 | + * Two nodes of a binary tree are cousins if they have the same depth, but have different parents. |
| 7 | + * |
| 8 | + * We are given the root of a binary tree with unique values, and the values x and y of two different nodes in the tree. |
| 9 | + * |
| 10 | + * Return true if and only if the nodes corresponding to the values x and y are cousins. |
| 11 | + * |
| 12 | + * |
| 13 | + * |
| 14 | + * Example 1:<br /> |
| 15 | + * <img alt="" src="https://assets.leetcode.com/uploads/2019/02/12/q1248-01.png" style="width: 180px; height: 160px;" /> |
| 16 | + * |
| 17 | + * |
| 18 | + * Input: root = <span id="example-input-1-1">[1,2,3,4]</span>, x = <span id="example-input-1-2">4</span>, y = <span id="example-input-1-3">3</span> |
| 19 | + * Output: <span id="example-output-1">false</span> |
| 20 | + * |
| 21 | + * |
| 22 | + * <div> |
| 23 | + * Example 2:<br /> |
| 24 | + * <img alt="" src="https://assets.leetcode.com/uploads/2019/02/12/q1248-02.png" style="width: 201px; height: 160px;" /> |
| 25 | + * |
| 26 | + * |
| 27 | + * Input: root = <span id="example-input-2-1">[1,2,3,null,4,null,5]</span>, x = <span id="example-input-2-2">5</span>, y = <span id="example-input-2-3">4</span> |
| 28 | + * Output: <span id="example-output-2">true</span> |
| 29 | + * |
| 30 | + * |
| 31 | + * <div> |
| 32 | + * Example 3: |
| 33 | + * |
| 34 | + * <img alt="" src="https://assets.leetcode.com/uploads/2019/02/13/q1248-03.png" style="width: 156px; height: 160px;" /> |
| 35 | + * |
| 36 | + * |
| 37 | + * Input: root = <span id="example-input-3-1">[1,2,3,null,4]</span>, x = 2, y = 3 |
| 38 | + * Output: <span id="example-output-3">false</span> |
| 39 | + * |
| 40 | + * |
| 41 | + * </div> |
| 42 | + * </div> |
| 43 | + * |
| 44 | + * Note: |
| 45 | + * |
| 46 | + * <ol> |
| 47 | + * The number of nodes in the tree will be between 2 and 100. |
| 48 | + * Each node has a unique integer value from 1 to 100. |
| 49 | + * </ol> |
| 50 | + * |
| 51 | + * <div> |
| 52 | + * <div> |
| 53 | + * <div> </div> |
| 54 | + * </div> |
| 55 | + * </div> |
| 56 | + */ |
| 57 | +pub struct Solution {} |
| 58 | +use crate::util::tree::{TreeNode, to_tree}; |
| 59 | + |
| 60 | +// problem: https://leetcode.com/problems/cousins-in-binary-tree/ |
| 61 | +// discuss: https://leetcode.com/problems/cousins-in-binary-tree/discuss/?currentPage=1&orderBy=most_votes&query= |
| 62 | + |
| 63 | +// submission codes start here |
| 64 | + |
| 65 | +// Definition for a binary tree node. |
| 66 | +// #[derive(Debug, PartialEq, Eq)] |
| 67 | +// pub struct TreeNode { |
| 68 | +// pub val: i32, |
| 69 | +// pub left: Option<Rc<RefCell<TreeNode>>>, |
| 70 | +// pub right: Option<Rc<RefCell<TreeNode>>>, |
| 71 | +// } |
| 72 | +// |
| 73 | +// impl TreeNode { |
| 74 | +// #[inline] |
| 75 | +// pub fn new(val: i32) -> Self { |
| 76 | +// TreeNode { |
| 77 | +// val, |
| 78 | +// left: None, |
| 79 | +// right: None |
| 80 | +// } |
| 81 | +// } |
| 82 | +// } |
| 83 | +use std::rc::Rc; |
| 84 | +use std::cell::{RefCell, Ref}; |
| 85 | + |
| 86 | +impl Solution { |
| 87 | + pub fn is_cousins(root: Option<Rc<RefCell<TreeNode>>>, x: i32, y: i32) -> bool { |
| 88 | + if x == y || root.is_none() { |
| 89 | + return false; |
| 90 | + } |
| 91 | + |
| 92 | + let x_result: Option<(i32, i32)> = Solution::find_depth_and_parent(&root, x, 0); |
| 93 | + let y_result: Option<(i32, i32)> = Solution::find_depth_and_parent(&root, y, 0); |
| 94 | + |
| 95 | + if x_result.is_none() || y_result.is_none() { |
| 96 | + return false; |
| 97 | + } |
| 98 | + |
| 99 | + let x_result = x_result.unwrap(); |
| 100 | + let y_result = y_result.unwrap(); |
| 101 | + |
| 102 | + if x_result.0 == y_result.0 && x_result.1 != y_result.1 { |
| 103 | + return true; |
| 104 | + } |
| 105 | + |
| 106 | + false |
| 107 | + } |
| 108 | + |
| 109 | + fn find_depth_and_parent(root: &Option<Rc<RefCell<TreeNode>>>, x: i32, depth: i32) -> Option<(i32, i32)> { |
| 110 | + let mut result = None; |
| 111 | + // TODO 太丑了 |
| 112 | + if let Some(inner) = root { |
| 113 | + let val = inner.borrow().val; |
| 114 | + if let Some(l) = &inner.borrow().left { |
| 115 | + if *(&l.borrow().val) == x { |
| 116 | + result = Some((depth, val)); |
| 117 | + } |
| 118 | + } |
| 119 | + if result.is_none() { |
| 120 | + if let Some(r) = &inner.borrow().right { |
| 121 | + if *(&r.borrow().val) == x { |
| 122 | + result = Some((depth, val)); |
| 123 | + } |
| 124 | + } |
| 125 | + } |
| 126 | + if result.is_none() { |
| 127 | + result = Solution::find_depth_and_parent(&inner.borrow().left, x, depth + 1); |
| 128 | + } |
| 129 | + if result.is_none() { |
| 130 | + result = Solution::find_depth_and_parent(&inner.borrow().right, x, depth + 1); |
| 131 | + } |
| 132 | + } |
| 133 | + return result; |
| 134 | + } |
| 135 | +} |
| 136 | + |
| 137 | +// submission codes end |
| 138 | + |
| 139 | +#[cfg(test)] |
| 140 | +mod tests { |
| 141 | + use super::*; |
| 142 | + |
| 143 | + #[test] |
| 144 | + fn test_993() { |
| 145 | + let root = to_tree(vec![Some(1),Some(2),Some(3), Some(4)]); |
| 146 | + let answer = Solution::is_cousins(root, 4, 3); |
| 147 | + assert!(!answer); |
| 148 | + |
| 149 | + let root = to_tree(vec![Some(1),Some(2),Some(3), None, Some(4), None, Some(5)]); |
| 150 | + let answer = Solution::is_cousins(root, 4, 5); |
| 151 | + assert!(answer); |
| 152 | + |
| 153 | + let root = to_tree(vec![Some(1),Some(2),Some(3), None, Some(4), None, Some(5)]); |
| 154 | + let answer = Solution::is_cousins(root, 2, 3); |
| 155 | + assert!(!answer); |
| 156 | + } |
| 157 | +} |
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