how-do-you-reverse-a-string-in-place-in-javascript

Author: wakidurrahman

problems/how-do-you-reverse-a-string.js

@@ -0,0 +1,134 @@
+/**
+ * https://stackoverflow.com/questions/958908/how-do-you-reverse-a-string-in-place-in-javascript
+ * *** How do you reverse a string in-place in JavaScript?
+ *
+ * *** How do you reverse a string in-place in JavaScript when it is passed to a function with a return statement,
+ * without using built-in functions (.reverse(), .charAt() etc.)?
+ * *** Write a function that accepts a string input and returns a reversed copy.
+ */
+
+/**
+ *
+ * Answers
+ *
+ */
+
+function reverse(s) {
+  return s.split("").reverse().join("");
+}
+
+function reverse(s) {
+  return [...s].reverse().join("");
+}
+
+String.prototype.reverse_string = function () {
+  return this.split("").reverse().join("");
+};
+
+String.prototype.reverse_string = function () {
+  var s = "";
+  var i = this.length;
+  while (i > 0) {
+    s += this.substring(i - 1, i);
+    i--;
+  }
+  return s;
+};
+
+/**
+ * Detailed analysis and ten different ways to reverse a string and their performance details.
+ * https://eddmann.com/posts/ten-ways-to-reverse-a-string-in-javascript/
+ */
+
+// Implementation 1:
+function reverse(s) {
+  var o = "";
+  for (var i = s.length - 1; i >= 0; i--) o += s[i];
+  return o;
+}
+//   Implementation 2:
+function reverse(s) {
+  var o = [];
+  for (var i = s.length - 1, j = 0; i >= 0; i--, j++) o[j] = s[i];
+  return o.join("");
+}
+//   Implementation 3:
+
+function reverse(s) {
+  var o = [];
+  for (var i = 0, len = s.length; i <= len; i++) o.push(s.charAt(len - i));
+  return o.join("");
+}
+// Implementation 4:
+
+function reverse(s) {
+  return s.split("").reverse().join("");
+}
+// Implementation 5:
+
+function reverse(s) {
+  var i = s.length,
+    o = "";
+  while (i > 0) {
+    o += s.substring(i - 1, i);
+    i--;
+  }
+  return o;
+}
+// Implementation 6:
+
+function reverse(s) {
+  for (var i = s.length - 1, o = ""; i >= 0; o += s[i--]) {}
+  return o;
+}
+// Implementation 7:
+
+function reverse(s) {
+  return s === "" ? "" : reverse(s.substr(1)) + s.charAt(0);
+}
+// Implementation 8:
+
+function reverse(s) {
+  function rev(s, len, o) {
+    return len === 0 ? o : rev(s, --len, (o += s[len]));
+  }
+  return rev(s, s.length, "");
+}
+// Implementation 9:
+
+function reverse(s) {
+  s = s.split("");
+  var len = s.length,
+    halfIndex = Math.floor(len / 2) - 1,
+    tmp;
+
+  for (var i = 0; i <= halfIndex; i++) {
+    tmp = s[len - i - 1];
+    s[len - i - 1] = s[i];
+    s[i] = tmp;
+  }
+  return s.join("");
+}
+// Implementation 10
+
+function reverse(s) {
+  if (s.length < 2) return s;
+  var halfIndex = Math.ceil(s.length / 2);
+  return reverse(s.substr(halfIndex)) + reverse(s.substr(0, halfIndex));
+}
+// Implementation 11
+
+var reverser = function (str) {
+  let string = str.split("");
+
+  for (i = 0; i < string.length; i++) {
+    debugger;
+    string.splice(i, 0, string.pop());
+  }
+  console.log(string.join());
+};
+reverser("abcdef");
+
+
+// Implementation 12
+const reverse = str => Array.from(str).reverse().join('');