Using slicing technique checking for palindrome

Author: avais umar

Palindrome_Checker.py

@@ -1,50 +1,15 @@
-# AUTHOR: ekbalba
-# DESCRIPTION: A simple script which checks if a given phrase is a Palindrome
-# PALINDROME: A word, phrase, or sequence that reads the same backward as forward
 
-samplePhrase = "A man, a plan, a cat, a ham, a yak, a yam, a hat, a canal-Panama!"  
-# givenPhrase = ""
-# phrase = ""
-
-givenPhrase = input("\nPlease input a phrase:(Press ENTER to use the sample phrase) ") #takes a phrase for input
-
-#if nothing in given as input then the sample phrase is stored in the variable phrase otherwise the given phrase if stored
-if givenPhrase == "":
-    print("\nThe sample phrase is: {0}".format(samplePhrase))
-    phrase = samplePhrase 
-else:
-    phrase = givenPhrase
-
-phrase = ''.join([c for c in phrase.lower() if c.isalpha() or c.isdigit()]) #converting all the characters of the phrase to the lowercase
-
-length_ = len(phrase) #returns the length of string
-bol_ = True
-
-# check using two pointers, one at beginning
-# other at the end. Use only half of the list.
-for items in range(length_ // 2):
-    if phrase[items] != phrase[length_ - 1 - items]:  
-        print("\nSorry, The given phrase is not a Palindrome.")
-        bol_ = False
-        break
-
-if bol_ == True:
-    print("\nWow!, The phrase is a Palindrome!")
-    
-    
-    
-    
 
 
 """
-Method #2:
 
-A simple mmethod is , to reverse the string and and compare with original string.
+A simple method is , to reverse the string and and compare with original string.
 If both are same that's means string is palindrome otherwise else. 
 """
+phrase=input()
 if phrase==phrase[::-1]:#slicing technique
     """phrase[::-1] this code is for reverse a string very smartly """
 
-    print("\nBy Method 2: Wow!, The phrase is a Palindrome!")
+    print("\n Wow!, The phrase is a Palindrome!")
 else:
-    print("\nBy Method 2: Sorry, The given phrase is not a Palindrome.")
+    print("\n Sorry, The given phrase is not a Palindrome.")