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BidirectionalCollection.swift
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//===----------------------------------------------------------------------===//
//
// This source file is part of the Swift.org open source project
//
// Copyright (c) 2014 - 2017 Apple Inc. and the Swift project authors
// Licensed under Apache License v2.0 with Runtime Library Exception
//
// See https://swift.org/LICENSE.txt for license information
// See https://swift.org/CONTRIBUTORS.txt for the list of Swift project authors
//
//===----------------------------------------------------------------------===//
/// A type that provides subscript access to its elements, with bidirectional
/// index traversal.
///
/// In most cases, it's best to ignore this protocol and use the
/// `BidirectionalCollection` protocol instead, because it has a more complete
/// interface.
@available(*, deprecated, message: "it will be removed in Swift 4.0. Please use 'BidirectionalCollection' instead")
public typealias BidirectionalIndexable = _BidirectionalIndexable
public protocol _BidirectionalIndexable : _Indexable {
// FIXME(ABI)#22 (Recursive Protocol Constraints): there is no reason for this protocol
// to exist apart from missing compiler features that we emulate with it.
// rdar://problem/20531108
//
// This protocol is almost an implementation detail of the standard
// library.
/// Returns the position immediately before the given index.
///
/// - Parameter i: A valid index of the collection. `i` must be greater than
/// `startIndex`.
/// - Returns: The index value immediately before `i`.
func index(before i: Index) -> Index
/// Replaces the given index with its predecessor.
///
/// - Parameter i: A valid index of the collection. `i` must be greater than
/// `startIndex`.
func formIndex(before i: inout Index)
}
/// A collection that supports backward as well as forward traversal.
///
/// Bidirectional collections offer traversal backward from any valid index,
/// not including a collection's `startIndex`. Bidirectional collections can
/// therefore offer additional operations, such as a `last` property that
/// provides efficient access to the last element and a `reversed()` method
/// that presents the elements in reverse order. In addition, bidirectional
/// collections have more efficient implementations of some sequence and
/// collection methods, such as `suffix(_:)`.
///
/// Conforming to the BidirectionalCollection Protocol
/// ==================================================
///
/// To add `BidirectionalProtocol` conformance to your custom types, implement
/// the `index(before:)` method in addition to the requirements of the
/// `Collection` protocol.
///
/// Indices that are moved forward and backward in a bidirectional collection
/// move by the same amount in each direction. That is, for any index `i` into
/// a bidirectional collection `c`:
///
/// - If `i >= c.startIndex && i < c.endIndex`,
/// `c.index(before: c.index(after: i)) == i`.
/// - If `i > c.startIndex && i <= c.endIndex`
/// `c.index(after: c.index(before: i)) == i`.
public protocol BidirectionalCollection : _BidirectionalIndexable, Collection
where SubSequence: BidirectionalCollection, Indices: BidirectionalCollection {
// TODO: swift-3-indexing-model - replaces functionality in BidirectionalIndex
/// Returns the position immediately before the given index.
///
/// - Parameter i: A valid index of the collection. `i` must be greater than
/// `startIndex`.
/// - Returns: The index value immediately before `i`.
func index(before i: Index) -> Index
/// Replaces the given index with its predecessor.
///
/// - Parameter i: A valid index of the collection. `i` must be greater than
/// `startIndex`.
func formIndex(before i: inout Index)
/// A sequence that can represent a contiguous subrange of the collection's
/// elements.
associatedtype SubSequence = BidirectionalSlice<Self>
/// A type that represents the indices that are valid for subscripting the
/// collection, in ascending order.
associatedtype Indices = DefaultBidirectionalIndices<Self>
/// The indices that are valid for subscripting the collection, in ascending
/// order.
///
/// A collection's `indices` property can hold a strong reference to the
/// collection itself, causing the collection to be non-uniquely referenced.
/// If you mutate the collection while iterating over its indices, a strong
/// reference can cause an unexpected copy of the collection. To avoid the
/// unexpected copy, use the `index(after:)` method starting with
/// `startIndex` to produce indices instead.
///
/// var c = MyFancyCollection([10, 20, 30, 40, 50])
/// var i = c.startIndex
/// while i != c.endIndex {
/// c[i] /= 5
/// i = c.index(after: i)
/// }
/// // c == MyFancyCollection([2, 4, 6, 8, 10])
var indices: Indices { get }
// TODO: swift-3-indexing-model: tests.
/// The last element of the collection.
///
/// If the collection is empty, the value of this property is `nil`.
///
/// let numbers = [10, 20, 30, 40, 50]
/// if let lastNumber = numbers.last {
/// print(lastNumber)
/// }
/// // Prints "50"
///
/// - Complexity: O(1)
var last: Iterator.Element? { get }
/// Accesses a contiguous subrange of the collection's elements.
///
/// The accessed slice uses the same indices for the same elements as the
/// original collection uses. Always use the slice's `startIndex` property
/// instead of assuming that its indices start at a particular value.
///
/// This example demonstrates getting a slice of an array of strings, finding
/// the index of one of the strings in the slice, and then using that index
/// in the original array.
///
/// let streets = ["Adams", "Bryant", "Channing", "Douglas", "Evarts"]
/// let streetsSlice = streets[2 ..< streets.endIndex]
/// print(streetsSlice)
/// // Prints "["Channing", "Douglas", "Evarts"]"
///
/// let index = streetsSlice.index(of: "Evarts") // 4
/// print(streets[index!])
/// // Prints "Evarts"
///
/// - Parameter bounds: A range of the collection's indices. The bounds of
/// the range must be valid indices of the collection.
subscript(bounds: Range<Index>) -> SubSequence { get }
}
/// Default implementation for bidirectional collections.
extension _BidirectionalIndexable {
@inline(__always)
public func formIndex(before i: inout Index) {
i = index(before: i)
}
public func index(_ i: Index, offsetBy n: IndexDistance) -> Index {
if n >= 0 {
return _advanceForward(i, by: n)
}
var i = i
for _ in stride(from: 0, to: n, by: -1) {
formIndex(before: &i)
}
return i
}
public func index(
_ i: Index, offsetBy n: IndexDistance, limitedBy limit: Index
) -> Index? {
if n >= 0 {
return _advanceForward(i, by: n, limitedBy: limit)
}
var i = i
for _ in stride(from: 0, to: n, by: -1) {
if i == limit {
return nil
}
formIndex(before: &i)
}
return i
}
public func distance(from start: Index, to end: Index) -> IndexDistance {
var start = start
var count: IndexDistance = 0
if start < end {
while start != end {
count += 1 as IndexDistance
formIndex(after: &start)
}
}
else if start > end {
while start != end {
count -= 1 as IndexDistance
formIndex(before: &start)
}
}
return count
}
}
/// Supply the default "slicing" `subscript` for `BidirectionalCollection`
/// models that accept the default associated `SubSequence`,
/// `BidirectionalSlice<Self>`.
extension BidirectionalCollection where SubSequence == BidirectionalSlice<Self> {
public subscript(bounds: Range<Index>) -> BidirectionalSlice<Self> {
_failEarlyRangeCheck(bounds, bounds: startIndex..<endIndex)
return BidirectionalSlice(base: self, bounds: bounds)
}
}
extension BidirectionalCollection where SubSequence == Self {
/// Removes and returns the last element of the collection.
///
/// You can use `popLast()` to remove the last element of a collection that
/// might be empty. The `removeLast()` method must be used only on a
/// nonempty collection.
///
/// - Returns: The last element of the collection if the collection has one
/// or more elements; otherwise, `nil`.
///
/// - Complexity: O(1).
/// - SeeAlso: `removeLast()`
public mutating func popLast() -> Iterator.Element? {
guard !isEmpty else { return nil }
let element = last!
self = self[startIndex..<index(before: endIndex)]
return element
}
/// Removes and returns the last element of the collection.
///
/// The collection must not be empty. To remove the last element of a
/// collection that might be empty, use the `popLast()` method instead.
///
/// - Returns: The last element of the collection.
///
/// - Complexity: O(1)
/// - SeeAlso: `popLast()`
@discardableResult
public mutating func removeLast() -> Iterator.Element {
let element = last!
self = self[startIndex..<index(before: endIndex)]
return element
}
/// Removes the given number of elements from the end of the collection.
///
/// - Parameter n: The number of elements to remove. `n` must be greater
/// than or equal to zero, and must be less than or equal to the number of
/// elements in the collection.
///
/// - Complexity: O(1) if the collection conforms to
/// `RandomAccessCollection`; otherwise, O(*n*), where *n* is the length
/// of the collection.
public mutating func removeLast(_ n: Int) {
if n == 0 { return }
_precondition(n >= 0, "number of elements to remove should be non-negative")
_precondition(count >= numericCast(n),
"can't remove more items from a collection than it contains")
self = self[startIndex..<index(endIndex, offsetBy: numericCast(-n))]
}
}
extension BidirectionalCollection {
/// Returns a subsequence containing all but the specified number of final
/// elements.
///
/// If the number of elements to drop exceeds the number of elements in the
/// collection, the result is an empty subsequence.
///
/// let numbers = [1, 2, 3, 4, 5]
/// print(numbers.dropLast(2))
/// // Prints "[1, 2, 3]"
/// print(numbers.dropLast(10))
/// // Prints "[]"
///
/// - Parameter n: The number of elements to drop off the end of the
/// collection. `n` must be greater than or equal to zero.
/// - Returns: A subsequence that leaves off `n` elements from the end.
///
/// - Complexity: O(*n*), where *n* is the number of elements to drop.
public func dropLast(_ n: Int) -> SubSequence {
_precondition(
n >= 0, "Can't drop a negative number of elements from a collection")
let end = index(
endIndex,
offsetBy: numericCast(-n),
limitedBy: startIndex) ?? startIndex
return self[startIndex..<end]
}
/// Returns a subsequence, up to the given maximum length, containing the
/// final elements of the collection.
///
/// If the maximum length exceeds the number of elements in the collection,
/// the result contains the entire collection.
///
/// let numbers = [1, 2, 3, 4, 5]
/// print(numbers.suffix(2))
/// // Prints "[4, 5]"
/// print(numbers.suffix(10))
/// // Prints "[1, 2, 3, 4, 5]"
///
/// - Parameter maxLength: The maximum number of elements to return.
/// `maxLength` must be greater than or equal to zero.
/// - Returns: A subsequence terminating at the end of the collection with at
/// most `maxLength` elements.
///
/// - Complexity: O(*n*), where *n* is equal to `maxLength`.
public func suffix(_ maxLength: Int) -> SubSequence {
_precondition(
maxLength >= 0,
"Can't take a suffix of negative length from a collection")
let start = index(
endIndex,
offsetBy: numericCast(-maxLength),
limitedBy: startIndex) ?? startIndex
return self[start..<endIndex]
}
}