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1140-stone-game-ii/README.md

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+<h2><a href="https://leetcode.com/problems/stone-game-ii/">1140. Stone Game II</a></h2><h3>Medium</h3><hr><div><p>Alice and Bob continue their&nbsp;games with piles of stones.&nbsp; There are a number of&nbsp;piles&nbsp;<strong>arranged in a row</strong>, and each pile has a positive integer number of stones&nbsp;<code>piles[i]</code>.&nbsp; The objective of the game is to end with the most&nbsp;stones.&nbsp;</p>
+
+<p>Alice&nbsp;and Bob take turns, with Alice starting first.&nbsp; Initially, <code>M = 1</code>.</p>
+
+<p>On each player's turn, that player&nbsp;can take <strong>all the stones</strong> in the <strong>first</strong> <code>X</code> remaining piles, where <code>1 &lt;= X &lt;= 2M</code>.&nbsp; Then, we set&nbsp;<code>M = max(M, X)</code>.</p>
+
+<p>The game continues until all the stones have been taken.</p>
+
+<p>Assuming Alice and Bob play optimally, return the maximum number of stones Alice&nbsp;can get.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre><strong>Input:</strong> piles = [2,7,9,4,4]
+<strong>Output:</strong> 10
+<strong>Explanation:</strong>  If Alice takes one pile at the beginning, Bob takes two piles, then Alice takes 2 piles again. Alice can get 2 + 4 + 4 = 10 piles in total. If Alice takes two piles at the beginning, then Bob can take all three piles left. In this case, Alice get 2 + 7 = 9 piles in total. So we return 10 since it's larger. 
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre><strong>Input:</strong> piles = [1,2,3,4,5,100]
+<strong>Output:</strong> 104
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= piles.length &lt;= 100</code></li>
+	<li><code>1 &lt;= piles[i]&nbsp;&lt;= 10<sup>4</sup></code></li>
+</ul>
+</div>