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| 1 | +/** |
| 2 | + * Question Link: https://leetcode.com/problems/detect-squares/ |
| 3 | + * Primary idea: Use hashmap to track points having the same x and y and calculate all possible results |
| 4 | + * |
| 5 | + * Time Complexity: add - O(1), count - O(n) |
| 6 | + * Space Complexity: O(n) |
| 7 | + * |
| 8 | + */ |
| 9 | + |
| 10 | +class DetectSquares { |
| 11 | + |
| 12 | + private var xPoints = [Int: [Int: Int]]() |
| 13 | + private var yPoints = [Int: [Int: Int]]() |
| 14 | + |
| 15 | + init() { } |
| 16 | + |
| 17 | + func add(_ point: [Int]) { |
| 18 | + let x = point[0], y = point[1] |
| 19 | + |
| 20 | + xPoints[x, default: [y: 0]][y, default: 0] += 1 |
| 21 | + yPoints[y, default: [x: 0]][x, default: 0] += 1 |
| 22 | + } |
| 23 | + |
| 24 | + func count(_ point: [Int]) -> Int { |
| 25 | + let x = point[0], y = point[1] |
| 26 | + |
| 27 | + guard let xEqualPoints = xPoints[x], let yEqualPoints = yPoints[y] else { |
| 28 | + return 0 |
| 29 | + } |
| 30 | + |
| 31 | + var res = 0 |
| 32 | + |
| 33 | + for (yEqualPointX, firstPointsCount) in yEqualPoints { |
| 34 | + if x == yEqualPointX { |
| 35 | + continue |
| 36 | + } |
| 37 | + let sideLength = abs(x - yEqualPointX) |
| 38 | + // check bottom square |
| 39 | + if let secondPointCount = xEqualPoints[y - sideLength] { |
| 40 | + if let thirdPointCount = xPoints[yEqualPointX]?[y - sideLength] { |
| 41 | + res += firstPointsCount * secondPointCount * thirdPointCount |
| 42 | + } |
| 43 | + } |
| 44 | + if let secondPointCount = xEqualPoints[y + sideLength] { |
| 45 | + if let thirdPointCount = xPoints[yEqualPointX]?[y + sideLength] { |
| 46 | + res += firstPointsCount * secondPointCount * thirdPointCount |
| 47 | + } |
| 48 | + } |
| 49 | + } |
| 50 | + |
| 51 | + return res |
| 52 | + } |
| 53 | +} |
| 54 | + |
| 55 | +/** |
| 56 | + * Your DetectSquares object will be instantiated and called as such: |
| 57 | + * let obj = DetectSquares() |
| 58 | + * obj.add(point) |
| 59 | + * let ret_2: Int = obj.count(point) |
| 60 | + */ |
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