need to retain the diffirent methods as they make the problem solving easy

Author: sagarrepogit

problem_july_24.js

@@ -0,0 +1,74 @@
+// question 22
+//reverse a array
+let arr=[1,2,3,4,5]
+console.log("this is the initial array"+arr)
+let first=0
+let last =arr.length-1
+while(first<last){
+    let temp=arr[first]
+    arr[first]=arr[last]
+    arr[last]=temp
+    first++
+    last--
+}
+console.log("this is the updated array"+arr)
+
+//question 23
+//reverse a string
+// reversing a string in the javascript is not as easy as reversing the array in the javascript
+//because the string is immutable in nature that means that we cannot reverse the string directly by converting that
+//string into the array  and then after you join it that is how the javascript is reversing the string
+
+//1st method (by using methods)
+let sidha = "JavaScript";
+let ulta = sidha.split("").reverse().join()
+console.log(ulta)
+
+//2nd method(manual one)
+let karnahai=""
+for(let i=sidha.length-1;i>=0;i--){
+    karnahai+=sidha[i]+","
+
+}
+console.log(karnahai)
+
+//question 24
+// a function that will merge two arrays and return the result as a new array
+// in order to this question there are basically three ways in which i will solve the
+//problem
+let arr1=[1,2,3]
+let arr2=[4,5,6]
+//1st method with the use of spread operator very easy
+let res=[...arr1,...arr2]
+console.log(res)
+//second by using the concat method
+let jodo= arr1.concat(arr2)
+console.log(jodo)
+//manual method
+function jodna_hai(arr1, arr2){
+let dono=[]
+for(let element of arr1){
+    dono.push(element)
+}
+for(let element of arr2){
+    dono.push(element)
+}
+return dono
+}
+let milgya=jodna_hai(arr1,arr2)
+console.log(milgya)
+
+//question 25
+// Create a function that will receive two arrays and will
+//  return an array with elements that are in the first array but not in the second
+// this will use the .inlude() method
+function ekarray(arr1,arr2){
+    let result=[]
+    for(let el of arr1){
+        if(!arr2.includes(el)){
+            result.push(el)
+        }
+    }return result
+}
+console.log(ekarray(arr1,arr2))
+