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14. Questions/leetcode 435 - non-overlapping intervals.py
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+# non-overlapping intervals | leetcode 435 | https://leetcode.com/problems/non-overlapping-intervals
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+# sort by starting times; keep track of latest ending time; always keep interval with min end time
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+
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+class Solution:
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+ def eraseOverlapIntervals(self, intervals: list[list[int]]) -> int:
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+ min_intervals_to_remove = 0
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+ intervals.sort(key = lambda x: x[0])
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+ latest_end = intervals[0][1]
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+ for i in range(1, len(intervals)):
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+ if intervals[i][0] < latest_end:
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+ min_intervals_to_remove += 1
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+ latest_end = min(intervals[i][1], latest_end)
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+ else:
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+ latest_end = intervals[i][1]
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+ return min_intervals_to_remove
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