feat: add solutions to lc problem: No.3141 (doocs#2775)

Author: yanglbme

solution/0100-0199/0165.Compare Version Numbers/README_EN.md

@@ -6,14 +6,9 @@
 
 ## Description
 
-<p>Given two version numbers,&nbsp;<code>version1</code> and <code>version2</code>, compare them.</p>
+<p>Given two <strong>version strings</strong>,&nbsp;<code>version1</code> and <code>version2</code>, compare them. A version string consists of <strong>revisions</strong> separated by dots <code>&#39;.&#39;</code>. The <strong>value of the revision</strong> is its <strong>integer conversion</strong> ignoring leading zeros.</p>
 
-<ul>
-</ul>
-
-<p>Version numbers consist of <strong>one or more revisions</strong> joined by a dot&nbsp;<code>&#39;.&#39;</code>. Each revision&nbsp;consists of <strong>digits</strong>&nbsp;and may contain leading <strong>zeros</strong>. Every revision contains <strong>at least one character</strong>. Revisions are <strong>0-indexed from left to right</strong>, with the leftmost revision being revision 0, the next revision being revision 1, and so on. For example&nbsp;<code>2.5.33</code>&nbsp;and&nbsp;<code>0.1</code>&nbsp;are valid version numbers.</p>
-
-<p>To compare version numbers, compare their revisions in <strong>left-to-right order</strong>. Revisions are compared using their&nbsp;<strong>integer value ignoring any leading zeros</strong>. This means that revisions&nbsp;<code>1</code>&nbsp;and&nbsp;<code>001</code>&nbsp;are considered&nbsp;<strong>equal</strong>. If a version number does not specify a revision at an index, then&nbsp;<strong>treat the revision as&nbsp;<code>0</code></strong>. For example, version&nbsp;<code>1.0</code> is less than version&nbsp;<code>1.1</code>&nbsp;because their revision 0s are the same, but their revision 1s are&nbsp;<code>0</code>&nbsp;and&nbsp;<code>1</code>&nbsp;respectively, and&nbsp;<code>0 &lt; 1</code>.</p>
+<p>To compare version strings, compare their revision values in <strong>left-to-right order</strong>. If one of the version strings has fewer revisions, treat the missing revision values as <code>0</code>.</p>
 
 <p><em>Return the following:</em></p>
 
@@ -26,27 +21,39 @@
 <p>&nbsp;</p>
 <p><strong class="example">Example 1:</strong></p>
 
-<pre>
-<strong>Input:</strong> version1 = &quot;1.01&quot;, version2 = &quot;1.001&quot;
-<strong>Output:</strong> 0
-<strong>Explanation:</strong> Ignoring leading zeroes, both &quot;01&quot; and &quot;001&quot; represent the same integer &quot;1&quot;.
-</pre>
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">version1 = &quot;1.2&quot;, version2 = &quot;1.10&quot;</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">-1</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>version1&#39;s second revision is &quot;2&quot; and version2&#39;s second revision is &quot;10&quot;: 2 &lt; 10, so version1 &lt; version2.</p>
+</div>
 
 <p><strong class="example">Example 2:</strong></p>
 
-<pre>
-<strong>Input:</strong> version1 = &quot;1.0&quot;, version2 = &quot;1.0.0&quot;
-<strong>Output:</strong> 0
-<strong>Explanation:</strong> version1 does not specify revision 2, which means it is treated as &quot;0&quot;.
-</pre>
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">version1 = &quot;1.01&quot;, version2 = &quot;1.001&quot;</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">0</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>Ignoring leading zeroes, both &quot;01&quot; and &quot;001&quot; represent the same integer &quot;1&quot;.</p>
+</div>
 
 <p><strong class="example">Example 3:</strong></p>
 
-<pre>
-<strong>Input:</strong> version1 = &quot;0.1&quot;, version2 = &quot;1.1&quot;
-<strong>Output:</strong> -1
-<strong>Explanation:</strong> version1&#39;s revision 0 is &quot;0&quot;, while version2&#39;s revision 0 is &quot;1&quot;. 0 &lt; 1, so version1 &lt; version2.
-</pre>
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">version1 = &quot;1.0&quot;, version2 = &quot;1.0.0.0&quot;</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">0</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>version1 has less revisions, which means every missing revision are treated as &quot;0&quot;.</p>
+</div>
 
 <p>&nbsp;</p>
 <p><strong>Constraints:</strong></p>

solution/0800-0899/0857.Minimum Cost to Hire K Workers/README.md

@@ -10,7 +10,7 @@
 
 <p>有 <code>n</code>&nbsp;名工人。&nbsp;给定两个数组&nbsp;<code>quality</code>&nbsp;和&nbsp;<code>wage</code>&nbsp;，其中，<code>quality[i]</code>&nbsp;表示第&nbsp;<code>i</code>&nbsp;名工人的工作质量，其最低期望工资为&nbsp;<code>wage[i]</code>&nbsp;。</p>
 
-<p>现在我们想雇佣&nbsp;<code>k</code>&nbsp;名工人组成一个<em>工资组。</em>在雇佣&nbsp;一组 <code>k</code>&nbsp;名工人时，我们必须按照下述规则向他们支付工资：</p>
+<p>现在我们想雇佣&nbsp;<code>k</code>&nbsp;名工人组成一个&nbsp;<strong>工资组</strong><em>。</em>在雇佣&nbsp;一组 <code>k</code>&nbsp;名工人时，我们必须按照下述规则向他们支付工资：</p>
 
 <ol>
 	<li>对工资组中的每名工人，应当按其工作质量与同组其他工人的工作质量的比例来支付工资。</li>
@@ -24,14 +24,14 @@
 <ol>
 </ol>
 
-<p><strong>示例 1：</strong></p>
+<p><strong class="example">示例 1：</strong></p>
 
 <pre>
 <strong>输入： </strong>quality = [10,20,5], wage = [70,50,30], k = 2
 <strong>输出： </strong>105.00000
 <strong>解释：</strong> 我们向 0 号工人支付 70，向 2 号工人支付 35。</pre>
 
-<p><strong>示例 2：</strong></p>
+<p><strong class="example">示例 2：</strong></p>
 
 <pre>
 <strong>输入： </strong>quality = [3,1,10,10,1], wage = [4,8,2,2,7], k = 3

solution/0800-0899/0857.Minimum Cost to Hire K Workers/README_EN.md

@@ -8,11 +8,11 @@
 
 <p>There are <code>n</code> workers. You are given two integer arrays <code>quality</code> and <code>wage</code> where <code>quality[i]</code> is the quality of the <code>i<sup>th</sup></code> worker and <code>wage[i]</code> is the minimum wage expectation for the <code>i<sup>th</sup></code> worker.</p>
 
-<p>We want to hire exactly <code>k</code> workers to form a paid group. To hire a group of <code>k</code> workers, we must pay them according to the following rules:</p>
+<p>We want to hire exactly <code>k</code> workers to form a <strong>paid group</strong>. To hire a group of <code>k</code> workers, we must pay them according to the following rules:</p>
 
 <ol>
-	<li>Every worker in the paid group should be paid in the ratio of their quality compared to other workers in the paid group.</li>
 	<li>Every worker in the paid group must be paid at least their minimum wage expectation.</li>
+	<li>In the group, each worker&#39;s pay must be directly proportional to their quality. This means if a worker&rsquo;s quality is double that of another worker in the group, then they must be paid twice as much as the other worker.</li>
 </ol>
 
 <p>Given the integer <code>k</code>, return <em>the least amount of money needed to form a paid group satisfying the above conditions</em>. Answers within <code>10<sup>-5</sup></code> of the actual answer will be accepted.</p>

solution/1100-1199/1112.Highest Grade For Each Student/README.md

@@ -25,8 +25,6 @@ grade 不会为 NULL。</pre>
 
 <p>编写解决方案，找出每位学生获得的最高成绩和它所对应的科目，若科目成绩并列，取&nbsp;<code>course_id</code>&nbsp;最小的一门。查询结果需按&nbsp;<code>student_id</code>&nbsp;增序进行排序。</p>
 
-<p>以 <strong>任意顺序</strong> 返回结果表。</p>
-
 <p>查询结果格式如下所示。</p>
 
 <p>&nbsp;</p>

solution/2000-2099/2077.Paths in Maze That Lead to Same Room/README.md

@@ -8,7 +8,7 @@
 
 <!-- 这里写题目描述 -->
 
-<p>迷宫由 <code>n</code> 个从 <code>1</code> 到 <code>n</code> 的房间组成，有些房间由走廊连接。给定一个二维整数数组 <code>corridors</code>，其中 <code>corridors[i] = [room1<sub>i</sub>, room2<sub>i</sub>]</code>&nbsp;表示有一条走廊连接 <code>room1<sub>i</sub></code> 和<code>room2<sub>i</sub></code>，允许迷宫中的一个人从 <code>room1<sub>i</sub></code> 到 <code>room1<sub>i</sub></code> ，<strong>反之亦然</strong>。</p>
+<p>迷宫由 <code>n</code> 个从 <code>1</code> 到 <code>n</code> 的房间组成，有些房间由走廊连接。给定一个二维整数数组 <code>corridors</code>，其中 <code>corridors[i] = [room1<sub>i</sub>, room2<sub>i</sub>]</code>&nbsp;表示有一条走廊连接 <code>room1<sub>i</sub></code> 和<code>room2<sub>i</sub></code>，允许迷宫中的一个人从 <code>room1<sub>i</sub></code> 到 <code>room2<sub>i</sub></code> ，<strong>反之亦然</strong>。</p>
 
 <p>迷宫的设计者想知道迷宫有多让人困惑。迷宫的&nbsp;<strong>混乱分数&nbsp;</strong>是&nbsp;<strong>长度为 3</strong> 的不同的环的数量。</p>
 

solution/2100-2199/2105.Watering Plants II/README.md

@@ -14,11 +14,9 @@
 
 <ul>
 	<li>&nbsp;Alice 按 <strong>从左到右</strong> 的顺序给植物浇水，从植物 <code>0</code> 开始。Bob 按 <strong>从右到左</strong> 的顺序给植物浇水，从植物 <code>n - 1</code> 开始。他们 <strong>同时</strong> 给植物浇水。</li>
-	<li>如果没有足够的水 <strong>完全</strong> 浇灌下一株植物，他 / 她会立即重新灌满浇水罐。</li>
-	<li>不管植物需要多少水，浇水所耗费的时间都是一样的。</li>
-	<li><strong>不能</strong> 提前重新灌满水罐。</li>
-	<li>每株植物都可以由 Alice 或者 Bob 来浇水。</li>
-	<li>如果 Alice 和 Bob 到达同一株植物，那么当前水罐中水更多的人会给这株植物浇水。如果他俩水量相同，那么 Alice 会给这株植物浇水。</li>
+	<li>无论需要多少水，为每株植物浇水所需的时间都是相同的。</li>
+	<li>如果 Alice/Bob 水罐中的水足以 <strong>完全</strong> 灌溉植物，他们 <strong>必须</strong> 给植物浇水。否则，他们 <strong>首先</strong>（立即）重新装满罐子，然后给植物浇水。</li>
+	<li>如果 Alice 和 Bob 到达同一株植物，那么当前水罐中水 <strong>更多</strong> 的人会给这株植物浇水。如果他俩水量相同，那么 Alice 会给这株植物浇水。</li>
 </ul>
 
 <p>给你一个下标从 <strong>0</strong> 开始的整数数组 <code>plants</code> ，数组由 <code>n</code> 个整数组成。其中，<code>plants[i]</code> 为第 <code>i</code> 株植物需要的水量。另有两个整数 <code>capacityA</code> 和&nbsp;<code>capacityB</code> 分别表示 Alice 和 Bob 水罐的容量。返回两人浇灌所有植物过程中重新灌满水罐的 <strong>次数</strong> 。</p>

solution/2500-2599/2563.Count the Number of Fair Pairs/README.md

@@ -32,7 +32,7 @@
 <pre>
 <b>输入：</b>nums = [1,7,9,2,5], lower = 11, upper = 11
 <b>输出：</b>1
-<b>解释：</b>只有单个公平数对：(2,9) 。
+<b>解释：</b>只有单个公平数对：(2,3) 。
 </pre>
 
 <p>&nbsp;</p>