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33 | 33 |
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34 | 34 | <!-- 这里可写通用的实现逻辑 -->
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35 | 35 |
|
| 36 | +二分查找。 |
| 37 | + |
36 | 38 | <!-- tabs:start -->
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37 | 39 |
|
38 | 40 | ### **Python3**
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39 | 41 |
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40 | 42 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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41 | 43 |
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42 | 44 | ```python
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43 |
| - |
| 45 | +class Solution: |
| 46 | + def arraysIntersection(self, arr1: List[int], arr2: List[int], arr3: List[int]) -> List[int]: |
| 47 | + def find(arr, val): |
| 48 | + left, right = 0, len(arr) - 1 |
| 49 | + while left < right: |
| 50 | + mid = (left + right) >> 1 |
| 51 | + if arr[mid] >= val: |
| 52 | + right = mid |
| 53 | + else: |
| 54 | + left = mid + 1 |
| 55 | + return arr[left] == val |
| 56 | + |
| 57 | + res = [] |
| 58 | + for num in arr1: |
| 59 | + if find(arr2, num) and find(arr3, num): |
| 60 | + res.append(num) |
| 61 | + return res |
44 | 62 | ```
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45 | 63 |
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46 | 64 | ### **Java**
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47 | 65 |
|
48 | 66 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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49 | 67 |
|
50 | 68 | ```java
|
| 69 | +class Solution { |
| 70 | + public List<Integer> arraysIntersection(int[] arr1, int[] arr2, int[] arr3) { |
| 71 | + List<Integer> res = new ArrayList<>(); |
| 72 | + for (int num : arr1) { |
| 73 | + if (find(arr2, num) && find(arr3, num)) { |
| 74 | + res.add(num); |
| 75 | + } |
| 76 | + } |
| 77 | + return res; |
| 78 | + } |
| 79 | + |
| 80 | + private boolean find(int[] arr, int val) { |
| 81 | + int left = 0, right = arr.length - 1; |
| 82 | + while (left < right) { |
| 83 | + int mid = (left + right) >> 1; |
| 84 | + if (arr[mid] >= val) { |
| 85 | + right = mid; |
| 86 | + } else { |
| 87 | + left = mid + 1; |
| 88 | + } |
| 89 | + } |
| 90 | + return arr[left] == val; |
| 91 | + } |
| 92 | +} |
| 93 | +``` |
| 94 | + |
| 95 | +### **C++** |
| 96 | + |
| 97 | +```cpp |
| 98 | +class Solution { |
| 99 | +public: |
| 100 | + vector<int> arraysIntersection(vector<int>& arr1, vector<int>& arr2, vector<int>& arr3) { |
| 101 | + vector<int> res; |
| 102 | + for (int num : arr1) { |
| 103 | + if (find(arr2, num) && find(arr3, num)) { |
| 104 | + res.push_back(num); |
| 105 | + } |
| 106 | + } |
| 107 | + return res; |
| 108 | + } |
| 109 | + |
| 110 | +private: |
| 111 | + bool find(vector<int>& arr, int val) { |
| 112 | + int left = 0, right = arr.size() - 1; |
| 113 | + while (left < right) { |
| 114 | + int mid = left + right >> 1; |
| 115 | + if (arr[mid] >= val) { |
| 116 | + right = mid; |
| 117 | + } else { |
| 118 | + left = mid + 1; |
| 119 | + } |
| 120 | + } |
| 121 | + return arr[left] == val; |
| 122 | + } |
| 123 | +}; |
| 124 | +``` |
51 | 125 |
|
| 126 | +### **Go** |
| 127 | +
|
| 128 | +```go |
| 129 | +func arraysIntersection(arr1 []int, arr2 []int, arr3 []int) []int { |
| 130 | + var res []int |
| 131 | + for _, num := range arr1 { |
| 132 | + if find(arr2, num) && find(arr3, num) { |
| 133 | + res = append(res, num) |
| 134 | + } |
| 135 | + } |
| 136 | + return res |
| 137 | +} |
| 138 | +
|
| 139 | +func find(arr []int, val int) bool { |
| 140 | + left, right := 0, len(arr)-1 |
| 141 | + for left < right { |
| 142 | + mid := (left + right) >> 1 |
| 143 | + if arr[mid] >= val { |
| 144 | + right = mid |
| 145 | + } else { |
| 146 | + left = mid + 1 |
| 147 | + } |
| 148 | + } |
| 149 | + return arr[left] == val |
| 150 | +} |
52 | 151 | ```
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53 | 152 |
|
54 | 153 | ### **...**
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