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LjyYanoLjyYano
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LeetCode 500~600 mysql
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33 files changed

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Diff for: ‎solution/0500-0599/0550.Game Play Analysis IV/README.md

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### **SQL**
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```
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(select round(count(distinct (b.player_id)) / (select count(distinct (player_id)) from Activity), 2) as fraction
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from Activity a
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left join (select player_id, min(event_date) as first_date from Activity group by player_id) as b
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on a.player_id = b.player_id and datediff(a.event_date, b.first_date) = 1)
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```
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0550.Game Play Analysis IV/README_EN.md

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### **SQL**
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```
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(select round(count(distinct (b.player_id)) / (select count(distinct (player_id)) from Activity), 2) as fraction
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from Activity a
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left join (select player_id, min(event_date) as first_date from Activity group by player_id) as b
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on a.player_id = b.player_id and datediff(a.event_date, b.first_date) = 1)
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```
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0550.Game Play Analysis IV/Solution.sql

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(select round(count(distinct (b.player_id)) / (select count(distinct (player_id)) from Activity), 2) as fraction
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from Activity a
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left join (select player_id, min(event_date) as first_date from Activity group by player_id) as b
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on a.player_id = b.player_id and datediff(a.event_date, b.first_date) = 1)

Diff for: ‎solution/0500-0599/0570.Managers with at Least 5 Direct Reports/README.md

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### **SQL**
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```
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SELECT Name
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FROM Employee
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WHERE Id IN
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(SELECT ManagerId
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FROM Employee
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GROUP BY ManagerId
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HAVING count(*) >= 5)
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```
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0570.Managers with at Least 5 Direct Reports/README_EN.md

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@@ -14,7 +14,13 @@ None
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### **SQL**
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```
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SELECT Name
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FROM Employee
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WHERE Id IN
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(SELECT ManagerId
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FROM Employee
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GROUP BY ManagerId
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HAVING count(*) >= 5)
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```
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0570.Managers with at Least 5 Direct Reports/Solution.sql

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SELECT Name
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FROM Employee
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WHERE Id IN
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(SELECT ManagerId
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FROM Employee
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GROUP BY ManagerId
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HAVING count(*) >= 5)

Diff for: ‎solution/0500-0599/0574.Winning Candidate/README.md

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@@ -16,7 +16,14 @@ None
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### **SQL**
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```
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SELECT Name
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FROM Candidate,
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(SELECT CandidateId,
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count(*) AS total
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FROM Vote
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GROUP BY CandidateId
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ORDER BY total DESC limit 1) AS tmp
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WHERE Candidate.id = tmp.CandidateId
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```
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0574.Winning Candidate/README_EN.md

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@@ -14,7 +14,14 @@ None
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### **SQL**
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```
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SELECT Name
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FROM Candidate,
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(SELECT CandidateId,
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count(*) AS total
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FROM Vote
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GROUP BY CandidateId
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ORDER BY total DESC limit 1) AS tmp
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WHERE Candidate.id = tmp.CandidateId
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```
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0574.Winning Candidate/Solution.sql

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SELECT Name
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FROM Candidate,
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(SELECT CandidateId,
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count(*) AS total
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FROM Vote
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GROUP BY CandidateId
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ORDER BY total DESC limit 1) AS tmp
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WHERE Candidate.id = tmp.CandidateId

Diff for: ‎solution/0500-0599/0577.Employee Bonus/README.md

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@@ -13,23 +13,16 @@ None
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<!-- tabs:start -->
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### **Python3**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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### **SQL**
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```python
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21-
```
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### **Java**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
25-
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```java
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```
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### **...**
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```
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SELECT name,
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bonus
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FROM Employee e
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LEFT JOIN Bonus b
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ON e.empId = b.empId
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WHERE (b.bonus < 1000
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OR b.bonus is null)
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```
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<!-- tabs:end -->
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0577.Employee Bonus/README_EN.md

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@@ -11,21 +11,16 @@ None
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<!-- tabs:start -->
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### **Python3**
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### **SQL**
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```python
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```
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### **Java**
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```java
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```
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### **...**
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```
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SELECT name,
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bonus
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FROM Employee e
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LEFT JOIN Bonus b
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ON e.empId = b.empId
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WHERE (b.bonus < 1000
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OR b.bonus is null)
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```
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<!-- tabs:end -->
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0577.Employee Bonus/Solution.sql

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SELECT name,
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bonus
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FROM Employee e
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LEFT JOIN Bonus b
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ON e.empId = b.empId
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WHERE (b.bonus < 1000
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OR b.bonus is null)

Diff for: ‎solution/0500-0599/0579.Find Cumulative Salary of an Employee/README.md

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### **SQL**
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```
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SELECT
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E1.id,
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E1.month,
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(IFNULL(E1.salary, 0) + IFNULL(E2.salary, 0) + IFNULL(E3.salary, 0)) AS Salary
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FROM
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(SELECT
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id, MAX(month) AS month
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FROM
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Employee
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GROUP BY id
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HAVING COUNT(*) > 1) AS maxmonth
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LEFT JOIN
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Employee E1 ON (maxmonth.id = E1.id
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AND maxmonth.month > E1.month)
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LEFT JOIN
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Employee E2 ON (E2.id = E1.id
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AND E2.month = E1.month - 1)
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LEFT JOIN
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Employee E3 ON (E3.id = E1.id
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AND E3.month = E1.month - 2)
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ORDER BY id ASC , month DESC
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```
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0579.Find Cumulative Salary of an Employee/README_EN.md

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### **SQL**
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```
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SELECT
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E1.id,
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E1.month,
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(IFNULL(E1.salary, 0) + IFNULL(E2.salary, 0) + IFNULL(E3.salary, 0)) AS Salary
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FROM
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(SELECT
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id, MAX(month) AS month
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FROM
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Employee
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GROUP BY id
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HAVING COUNT(*) > 1) AS maxmonth
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LEFT JOIN
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Employee E1 ON (maxmonth.id = E1.id
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AND maxmonth.month > E1.month)
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LEFT JOIN
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Employee E2 ON (E2.id = E1.id
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AND E2.month = E1.month - 1)
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LEFT JOIN
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Employee E3 ON (E3.id = E1.id
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AND E3.month = E1.month - 2)
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ORDER BY id ASC , month DESC
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```
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0579.Find Cumulative Salary of an Employee/Solution.sql

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SELECT
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E1.id,
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E1.month,
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(IFNULL(E1.salary, 0) + IFNULL(E2.salary, 0) + IFNULL(E3.salary, 0)) AS Salary
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FROM
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(SELECT
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id, MAX(month) AS month
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FROM
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Employee
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GROUP BY id
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HAVING COUNT(*) > 1) AS maxmonth
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LEFT JOIN
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Employee E1 ON (maxmonth.id = E1.id
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AND maxmonth.month > E1.month)
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LEFT JOIN
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Employee E2 ON (E2.id = E1.id
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AND E2.month = E1.month - 1)
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LEFT JOIN
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Employee E3 ON (E3.id = E1.id
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AND E3.month = E1.month - 2)
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ORDER BY id ASC , month DESC

Diff for: ‎solution/0500-0599/0580.Count Student Number in Departments/README.md

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@@ -13,23 +13,20 @@ None
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<!-- tabs:start -->
1515

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### **Python3**
17-
<!-- 这里可写当前语言的特殊实现逻辑 -->
16+
### **SQL**
1817

19-
```python
20-
21-
```
22-
23-
### **Java**
24-
<!-- 这里可写当前语言的特殊实现逻辑 -->
25-
26-
```java
27-
28-
```
29-
30-
### **...**
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```
32-
19+
SELECT dept_name,
20+
ifnull(total,
21+
0) AS student_number
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FROM department
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LEFT JOIN
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(SELECT dept_id,
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count(*) AS total
26+
FROM student
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GROUP BY dept_id) tmp
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ON department.dept_id = tmp.dept_id
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ORDER BY tmp.total desc
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```
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<!-- tabs:end -->
32+
<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0580.Count Student Number in Departments/README_EN.md

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@@ -11,21 +11,20 @@ None
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<!-- tabs:start -->
1313

14-
### **Python3**
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### **SQL**
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```python
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```
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### **Java**
21-
22-
```java
23-
24-
```
25-
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### **...**
2716
```
28-
17+
SELECT dept_name,
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ifnull(total,
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0) AS student_number
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FROM department
21+
LEFT JOIN
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(SELECT dept_id,
23+
count(*) AS total
24+
FROM student
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GROUP BY dept_id) tmp
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ON department.dept_id = tmp.dept_id
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ORDER BY tmp.total desc
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```
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<!-- tabs:end -->
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0580.Count Student Number in Departments/Solution.sql

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SELECT dept_name,
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ifnull(total,
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0) AS student_number
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FROM department
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LEFT JOIN
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(SELECT dept_id,
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count(*) AS total
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FROM student
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GROUP BY dept_id) tmp
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ON department.dept_id = tmp.dept_id
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ORDER BY tmp.total desc

Diff for: ‎solution/0500-0599/0584.Find Customer Referee/README.md

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### **SQL**
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1818
```
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SELECT name
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FROM customer
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WHERE referee_id != 2
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OR referee_id is null
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```
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0584.Find Customer Referee/README_EN.md

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### **SQL**
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```
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SELECT name
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FROM customer
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WHERE referee_id != 2
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OR referee_id is null
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```
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<!-- tabs:end -->

Diff for: ‎solution/0500-0599/0584.Find Customer Referee/Solution.sql

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SELECT name
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FROM customer
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WHERE referee_id != 2
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OR referee_id is null

Diff for: ‎solution/0500-0599/0586.Customer Placing the Largest Number of Orders/README.md

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### **SQL**
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1818
```
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19+
SELECT customer_number
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FROM
21+
(SELECT customer_number,
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count(*) AS total
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FROM orders
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GROUP BY customer_number
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ORDER BY total DESC limit 1) tmp
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```
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<!-- tabs:end -->

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