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Solution2.java
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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
private SegmentTree tree;
private int[] nums;
private static int[] d = new int[1010];
public TreeNode constructMaximumBinaryTree(int[] nums) {
int n = nums.length;
this.nums = nums;
tree = new SegmentTree(nums);
for (int i = 0; i < n; ++i) {
d[nums[i]] = i + 1;
}
return dfs(1, n);
}
private TreeNode dfs(int l, int r) {
if (l > r) {
return null;
}
int val = tree.query(1, l, r);
TreeNode root = new TreeNode(val);
root.left = dfs(l, d[val] - 1);
root.right = dfs(d[val] + 1, r);
return root;
}
}
class Node {
int l;
int r;
int v;
}
class SegmentTree {
Node[] tr;
int[] nums;
public SegmentTree(int[] nums) {
int n = nums.length;
this.nums = nums;
tr = new Node[n << 2];
for (int i = 0; i < tr.length; ++i) {
tr[i] = new Node();
}
build(1, 1, n);
}
private void build(int u, int l, int r) {
tr[u].l = l;
tr[u].r = r;
if (l == r) {
tr[u].v = nums[l - 1];
return;
}
int mid = (l + r) >> 1;
build(u << 1, l, mid);
build(u << 1 | 1, mid + 1, r);
pushup(u);
}
public int query(int u, int l, int r) {
if (tr[u].l >= l && tr[u].r <= r) {
return tr[u].v;
}
int mid = (tr[u].l + tr[u].r) >> 1;
int v = 0;
if (l <= mid) {
v = query(u << 1, l, r);
}
if (r > mid) {
v = Math.max(v, query(u << 1 | 1, l, r));
}
return v;
}
private void pushup(int u) {
tr[u].v = Math.max(tr[u << 1].v, tr[u << 1 | 1].v);
}
}