package com.fishercoder.solutions;

import java.util.ArrayList;
import java.util.List;

/**
 * Numbers can be regarded as product of its factors. For example,

 8 = 2 x 2 x 2;
 = 2 x 4.
 Write a function that takes an integer n and return all possible combinations of its factors.

 Note:
 You may assume that n is always positive.
 Factors should be greater than 1 and less than n.
 Examples:
 input: 1
 output:
 []
 input: 37
 output:
 []
 input: 12
 output:
 [
 [2, 6],
 [2, 2, 3],
 [3, 4]
 ]
 input: 32
 output:
 [
 [2, 16],
 [2, 2, 8],
 [2, 2, 2, 4],
 [2, 2, 2, 2, 2],
 [2, 4, 4],
 [4, 8]
 ]
 */
public class _254 {

    public List<List<Integer>> getFactors(int n) {
        List<List<Integer>> result = new ArrayList<List<Integer>>();
        helper(result, new ArrayList<Integer>(), n, 2);
        return result;
    }

    public void helper(List<List<Integer>> result, List<Integer> item, int n, int start) {
        if (n <= 1) {
            if (item.size() > 1) {
                result.add(new ArrayList<Integer>(item));
            }
            return;
        }

        for (int i = start; i <= n; ++i) {
            if (n % i == 0) {
                item.add(i);
                helper(result, item, n / i, i);
                item.remove(item.size() - 1);
            }
        }
    }

}