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_447.java
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package com.fishercoder.solutions;
import java.util.HashMap;
import java.util.Map;
/**Given n points in the plane that are all pairwise distinct, a "boomerang" is a tuple of points (i, j, k) such that the distance between i and j equals the distance between i and k (the order of the tuple matters).
Find the number of boomerangs. You may assume that n will be at most 500 and coordinates of points are all in the range [-10000, 10000] (inclusive).
Example:
Input:
[[0,0],[1,0],[2,0]]
Output:
2
Explanation:
The two boomerangs are [[1,0],[0,0],[2,0]] and [[1,0],[2,0],[0,0]]*/
public class _447 {
/**Looked at these two posts: https://discuss.leetcode.com/topic/66587/clean-java-solution-o-n-2-166ms and
* https://discuss.leetcode.com/topic/66521/share-my-straightforward-solution-with-hashmap-o-n-2, basically,
* have a HashMap, key is the distance, value is the number of points that are this distance apart to this point.
* Note: we clear up this map every time after we traverse one point with the rest of the other points.
*
* Time complexity: O(n^2)
* Space complexity: O(n)*/
public int numberOfBoomerangs(int[][] points) {
int result = 0;
if (points == null || points.length == 0 || points[0].length == 0) {
return result;
}
int totalPts = points.length;
Map<Long, Integer> map = new HashMap();
for (int i = 0; i < totalPts; i++) {
for (int j = 0; j < totalPts; j++) {
if (i == j) {
continue;
}
long d = calcDistance(points[i], points[j]);
map.put(d, map.getOrDefault(d, 0) + 1);
}
for (int val : map.values()) {
result += val * (val - 1);
}
map.clear();
}
return result;
}
private long calcDistance(int[] p1, int[] p2) {
long x = p2[0] - p1[0];
long y = p2[1] - p1[1];
return x * x + y * y;
}
public static void main(String... args) {
_447 test = new _447();
// int[][] points = new int[][]{
// {0,0},
// {1,0},
// {2,0},
// };
// [[3,6],[7,5],[3,5],[6,2],[9,1],[2,7],[0,9],[0,6],[2,6]], should return 10
int[][] points = new int[][] { { 3, 6 }, { 7, 5 }, { 3, 5 }, { 6, 2 }, { 9, 1 }, { 2, 7 },
{ 0, 9 }, { 0, 6 }, { 2, 6 }, };
// [[0,0],[1,0],[-1,0],[0,1],[0,-1]] should return 20
System.out.println(test.numberOfBoomerangs(points));
}
}