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SerializeandDeserializeBST.java
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package com.fishercoder.solutions;
import com.fishercoder.common.classes.TreeNode;
import java.util.LinkedList;
import java.util.Queue;
/**
* Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.
Design an algorithm to serialize and deserialize a binary search tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary search tree can be serialized to a string and this string can be deserialized to the original tree structure.
The encoded string should be as compact as possible.
Note: Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.
*/
public class SerializeandDeserializeBST {
// Encodes a tree to a single string.
public String serialize(TreeNode root) {
Queue<TreeNode> queue = new LinkedList<>();
StringBuilder stringBuilder = new StringBuilder();
if (root == null) return stringBuilder.toString();
queue.offer(root);
while (!queue.isEmpty()) {
int size = queue.size();
for (int i = 0; i < size; i++) {
TreeNode curr = queue.poll();
if (curr == null) {
stringBuilder.append("# ");
} else {
stringBuilder.append(curr.val + " ");
queue.offer(curr.left);
queue.offer(curr.right);
}
}
}
return stringBuilder.toString();
}
// Decodes your encoded data to tree.
public TreeNode deserialize(String data) {
if (data == null || data.length() == 0) return null;
String[] nodes = data.split(" ");
TreeNode root = new TreeNode(Integer.valueOf(nodes[0]));
Queue<TreeNode> queue = new LinkedList<>();
queue.offer(root);
for (int i = 1; i < nodes.length; i++) {
TreeNode curr = queue.poll();
if (!nodes[i].equals("#")) {
curr.left = new TreeNode(Integer.valueOf(nodes[i]));
queue.offer(curr.left);
}
if (!nodes[++i].equals("#")) {
curr.right = new TreeNode(Integer.valueOf(nodes[i]));
queue.offer(curr.right);
}
}
return root;
}
}