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_189.java
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package com.fishercoder.solutions;
import java.util.ArrayList;
import java.util.List;
import static com.fishercoder.solutions._189.Solution2.rotate_naive;
/**
* 189. Rotate Array
*
* Rotate an array of n elements to the right by k steps.
* For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4].
* */
public class _189 {
public static class Solution1 {
public void rotate(int[] nums, int k) {
int len = nums.length;
int[] tmp = new int[len];
for (int i = 0; i < len; i++) {
tmp[(i + k) % len] = nums[i];
}
for (int i = 0; i < len; i++) {
nums[i] = tmp[i];
}
}
}
public static class Solution2 {
/**
* My original idea and got AC'ed.
* One thing to notice is that when k > nums.length, we'll continue to rotate_naive the array, it just becomes k -= nums.length
*/
public static void rotate_naive(int[] nums, int k) {
if (k == 0 || k == nums.length) {
return;
}
if (k > nums.length) {
k -= nums.length;
}
List<Integer> tmp = new ArrayList();
int i = 0;
if (nums.length - k >= 0) {
i = nums.length - k;
for (; i < nums.length; i++) {
tmp.add(nums[i]);
}
} else {
i = nums.length - 1;
for (; i >= 0; i--) {
tmp.add(nums[i]);
}
}
for (i = 0; i < nums.length - k; i++) {
tmp.add(nums[i]);
}
for (i = 0; i < tmp.size(); i++) {
nums[i] = tmp.get(i);
}
}
}
public static void main(String... strings) {
// int k = 1;
// int[] nums = new int[]{1,2,3};
// int[] nums = new int[]{1};
// int[] nums = new int[]{1,2};
// int k = 3;
// int[] nums = new int[]{1,2};
// int k = 2;
// int[] nums = new int[]{1,2};
int k = 4;
int[] nums = new int[]{1, 2, 3};
// int k = 2;
// int[] nums = new int[]{-1};
rotate_naive(nums, k);
}
}