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_179.java
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package com.fishercoder.solutions;
import java.util.Arrays;
import java.util.Comparator;
/**
* Given a list of non negative integers, arrange them such that they form the largest number.
For example, given [3, 30, 34, 5, 9], the largest formed number is 9534330.
Note: The result may be very large, so you need to return a string instead of an integer.
*/
public class _179 {
public String largestNumber(int[] num) {
if (num.length == 0)
return "";
if (num.length == 1)
return Integer.toString(num[0]);
String[] str = new String[num.length];
for (int i = 0; i < num.length; i++)
str[i] = Integer.toString(num[i]);
Arrays.sort(str, new StringComparator());
StringBuilder sb = new StringBuilder("");
for (int i = num.length - 1; i >= 0; i--)
sb.append(str[i]);
if (sb.charAt(0) == '0')
return "0";
return sb.toString();
}
class StringComparator implements Comparator<String> {
public int compare(String s1, String s2) {
if (s1.length() == 0 && s2.length() == 0)
return 0;
if (s2.length() == 0)
return 1;
if (s1.length() == 0)
return -1;
for (int i = 0; i < s1.length() && i < s2.length(); i++) {
if (s1.charAt(i) > s2.charAt(i)) {
return 1;
} else if (s1.charAt(i) < s2.charAt(i)) {
return -1;
}
}
if (s1.length() == s2.length())
return 0;
if (s1.length() > s2.length()) {
if (s1.charAt(0) < s1.charAt(s2.length()))
return 1;
else if (s1.charAt(0) > s1.charAt(s2.length()))
return -1;
else
return compare(s1.substring(s2.length()), s2);
} else {
if (s2.charAt(0) < s2.charAt(s1.length()))
return -1;
else if (s2.charAt(0) > s2.charAt(s1.length()))
return 1;
else
return compare(s1, s2.substring(s1.length()));
}
}
}
}