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| 1 | +#!/usr/bin/python3 |
| 2 | +# -*- coding: utf-8 -*- |
| 3 | +''' |
| 4 | +AC |
| 5 | +''' |
| 6 | + |
| 7 | +import time |
| 8 | + |
| 9 | + |
| 10 | +# Definition for an interval. |
| 11 | +class Interval: |
| 12 | + def __init__(self, s=0, e=0): |
| 13 | + self.start = s |
| 14 | + self.end = e |
| 15 | + |
| 16 | + |
| 17 | +class Solution: |
| 18 | + def merge(self, intervals): |
| 19 | + """ |
| 20 | + :type intervals: List[Interval] |
| 21 | + :rtype: List[Interval] |
| 22 | + """ |
| 23 | + out_t = [] |
| 24 | + intervals.sort(key=lambda x: x.start) |
| 25 | + for val in intervals: |
| 26 | + if not out_t or val.start > out_t[-1].end: |
| 27 | + out_t.append(val) |
| 28 | + else: |
| 29 | + out_t[-1].end = max(val.end,out_t[-1].end) |
| 30 | + return out_t |
| 31 | + |
| 32 | + |
| 33 | +if __name__ == "__main__": |
| 34 | + |
| 35 | + t0 = time.perf_counter() |
| 36 | + |
| 37 | + test_list = [[[1, 3], [15, 18], [2, 6], [8, 10]], [[1, 4], [10, 15], |
| 38 | + [2, 12]], []] |
| 39 | + answer_list = [[[1, 6], [8, 10], [15, 18]], [[1, 15]], []] |
| 40 | + test = Solution() |
| 41 | + for i in range(len(test_list)): |
| 42 | + test_par = [] |
| 43 | + for list_t in test_list[i]: |
| 44 | + test_par.append(Interval(list_t[0], list_t[1])) |
| 45 | + out_t = test.merge(test_par) |
| 46 | + out_tt = [] |
| 47 | + for out_interval in out_t: |
| 48 | + out_tt.append([out_interval.start, out_interval.end]) |
| 49 | + if out_tt == answer_list[i]: |
| 50 | + print("\033[1;32;40m Pass \033[0m") |
| 51 | + else: |
| 52 | + print( |
| 53 | + "\033[1;31;40m Fail!!\033[0m\033[0;34;40m out \"%s\" should \"%s\" by \"%.50s\" " |
| 54 | + % (out_tt, answer_list[i], test_list[i])) |
| 55 | + |
| 56 | + print("\nRun Time is %f s" % (time.perf_counter() - t0)) |
| 57 | +''' |
| 58 | + def merge(self, intervals): |
| 59 | + """ |
| 60 | + :type intervals: List[Interval] |
| 61 | + :rtype: List[Interval] |
| 62 | + """ |
| 63 | + n = len(intervals) |
| 64 | + starts = [] |
| 65 | + ends = [] |
| 66 | + for i in range(n): |
| 67 | + starts.append(intervals[i].start) |
| 68 | + ends.append(intervals[i].end) |
| 69 | + |
| 70 | + starts.sort(); |
| 71 | + ends.sort(); |
| 72 | + res = [] |
| 73 | + j=0 |
| 74 | + for i in range(n): |
| 75 | + if i == n - 1 or starts[i + 1] > ends[i]: |
| 76 | + res.append([starts[j], ends[i]]) |
| 77 | + j = i + 1; |
| 78 | + return res; |
| 79 | +
|
| 80 | +class Solution: |
| 81 | + def merge(self, intervals): |
| 82 | + intervals.sort(key=lambda x: x.start) |
| 83 | +
|
| 84 | + merged = [] |
| 85 | + for interval in intervals: |
| 86 | + # if the list of merged intervals is empty or if the current |
| 87 | + # interval does not overlap with the previous, simply append it. |
| 88 | + if not merged or merged[-1].end < interval.start: |
| 89 | + merged.append(interval) |
| 90 | + else: |
| 91 | + # otherwise, there is overlap, so we merge the current and previous |
| 92 | + # intervals. |
| 93 | + merged[-1].end = max(merged[-1].end, interval.end) |
| 94 | + |
| 95 | + return merged |
| 96 | +''' |
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