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Author: iamnishantchandra

10X/Python/Array/BULB.py

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+'''
+Bulb
+There is a bulb. Just like other bulbs, this bulb can be either ON or OFF at a time. You can provide 3 types of instruction to the bulb-
+
+"ON"-> turn the bulb on.(no matter the previous state)
+"OFF"-> turn the bulb off.(no matter the previous state)
+"Toggle"-> If the bulb was initially on, turn it off. If the bulb was initially off, turn it on.
+You provide the bulb with 'N' number of Queries, each containing either of the above 3 instructions. Count the number of times bulb was turned ON from a OFF position.(ON->OFF)
+
+Note- Intially assume that the bulb was OFF.
+
+Input
+First line of the input contains N, representing the number of instructions. The following N lines contain one of the 3 types of instructions "ON","OFF","Toggle".
+
+Output
+Finally print the number of times the bulb was turned ON from a OFF position.
+
+Example
+Input:
+
+5
+
+Toggle
+
+Toggle
+
+OFF
+
+Toggle
+
+ON
+
+Output:
+
+2
+
+Explanation:
+
+Intially : OFF
+
+| BEFORE | INSTRUCTION | RESULT |
+------------------------------------
+| OFF        | TOGGLE           | ON |
+| ON          | TOGGLE           |OFF|
+| OFF        | OFF                  | OFF |
+| OFF        | TOGGLE           | ON |
+| ON          | ON                   | ON |
+As we can see that the bulb has been switched from OFF to ON 2 times once during the first(TOGGLE) instruction and then during the 4th(TOGGLE) instruction. So the output is 2
+'''
+'''
+n=int(input())
+a=[]
+for i in range(n):
+    a.append(input())
+b=0
+count=0
+for j in range(n):
+    if a[i]=="Toggle":
+        if b==0:
+            b=1
+            count+=1
+        else:
+            b=0
+    elif a[i]=="ON":
+        if b==0:
+            b=1
+            count+=1
+        else:
+            b=1
+    elif a[i]=="OFF":
+            b=0
+print(count)
+'''
+n=int(input())
+a=[]
+for j in range(n):
+    a.append(input())
+b=0
+count=0
+for i in range(n):
+    if b==0 :
+        if a[i]=="Toggle" or a[i]=="ON":
+            b=1
+            count+=1
+        else:
+            b=1
+    elif b==1:
+        if(a[i]=="Toggle") or (a[i]=="OFF") :
+            b=0
+        else:
+            b=1
+print(count)
+

10X/Python/Array/Parity Minimum.py

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+'''
+Parity Minimum
+Description
+Given an array of length n which contains only positive integers, let S be the sum of the digits of the 
+minimal element of the array.
+Return 0 if S is odd, otherwise return 1.
+
+Input format
+First line contains a positive integer n, which denotes the number of elements in the array. This is 
+followed by n lines each containing one integer denoting one element of the array.
+
+Output format
+One line which is 0 or 1.
+
+Sample input
+4
+34
+23
+1
+24
+Sample output
+0
+Explanation
+First line is 4, i.e. 4 elements in the array. Minimum element of the array is 1. Sum of digits of 1 is 
+1 and as it is odd, the output is 0
+
+Sample input
+2
+33
+44
+Sample output
+1
+Explanation
+First line is 2, i.e. 2 elements in the array. Minimum element of the array is 33. Sum of digits of 33 
+is 6 and as it is even, the output is 1
+'''
+n=int(input())
+a=[]
+for i in range(n):
+    a.append(int(input()))
+mi=min(a)
+su=0
+for i in str(mi):
+    su+=int(i)
+if su%2==0:
+    print(1)
+else:
+    print(0)

10X/Python/Class/Person.py

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+'''
+Person
+Define a class named Person, which should have the name and age as the properties. You don't need to worry about input/output and object of the class. The given template will take care of it.
+
+The input will contain the name and age. The same will be printed in seperate lines as output.
+
+Input
+One line containing two space seperated values, denoting name and age respectively.
+
+Output
+Print name and age in newline each.
+
+Example
+Input1:
+
+Jonny 15
+Output1:
+
+Jonny
+15
+'''
+### Define the required class here...
+class Person:
+    def __init__(self, name, age):
+        self.name=name
+        self.age=age
+
+
+### DO NOT CHANGE ANYTHING BELOW THIS LINE
+
+if __name__ == '__main__':
+    
+    input_string = input().split()
+
+    p1 = Person(input_string[0], int(input_string[1]))
+
+    print(p1.name)
+    print(p1.age)

10X/Python/String/MaxProduct.py

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+'''
+Maximum Product
+link https://6793fdf6.widgets.sphere-engine.com/lp?hash=atbecI0dwg
+You are given a list of integers. Find the maximum product that can be obtained from multiplying adjacent integers in the list.
+
+Input
+First line contains n, indicating the number of elements in the list, 2 <= n <= 10
+
+This is followed by n lines each containing an integer
+
+Output
+One integer indicating the maximum product achievable from adjacent elements of the list
+
+Example
+Input:
+
+4
+
+1
+
+3
+
+4
+
+10
+
+Output:
+
+40
+
+Explination:
+
+First line of input contains 4 indicating there are 4 elements in the list
+
+The next four lines contain the elements of the list: 1,3,4,10
+
+The possible products we can obtains is 1x3=3, 3x4=12, 4x10=40 where 40 is the maximum
+
+
+'''
+n=int(input())
+a=[]
+
+for i in range(n):
+    a.append(int(input()))
+ma=a[0]
+if n>1:
+    for j in range(1,n):
+        if ma<int(a[j-1]*a[j]):
+            ma=int(a[j-1]*a[j])
+    print(ma)
+elif n==0:
+    print(0)
+else:
+    print(ma)