REmove 3

Author: iamnishantchandra

10X/Python/Array/Remove_3.py

@@ -0,0 +1,70 @@
+'''
+Remove '3'
+You have been given an integer as input. you have to remove all the instances of the digit 3 present in the integer and print the remaining integer.
+
+ex- input= 122345337 output= 122457
+
+To solve this problem you have been given a solution template and you need to complete the following functions.
+
+intToArr-> takes integer as input and returns list of all digits of the number.(ex- 123-> [1,2,3])
+
+arrToInt-> takes list of digits as input and returns the corresponding integer to the list.(ex- [1,2,4] -> 124)
+
+remove_3-> takes a list of integers as input and returns a modified list in which every 3 is removed (ex- [1,2,3,4,3]->[1,2,4])
+
+Input
+Input contains only 1 integer as input.
+
+Output
+print the final integer in which all 3's are removed.
+
+Example
+Input:
+
+12353373999983
+
+Output:
+
+125799998
+'''
+def intToArr(N):
+    #complete this function
+    temp=0
+    n=0
+    arr=[]
+    while N>0:
+        temp=N%10
+        N=N//10
+        arr.append(temp)
+    return arr
+
+
+def remove_3(arr):
+    #complete this function
+    ar=[]
+    for i in arr:
+        if i!=3:
+            ar.append(i)
+    return ar[::-1]
+
+def arrToInt(arr):
+    #complete this function
+    sumo=0
+    for i in arr:
+        if i==0:
+            sumo*=10
+        elif i==3:
+            pass
+        else:
+            sumo=sumo*10+i
+
+    return sumo
+
+
+#DO NOT change anything below this line
+
+N=int(input())
+arrNum=intToArr(N)
+arrNumWithout3=remove_3(arrNum)
+
+print(arrToInt(arrNumWithout3))